Thermodynamic Properties and Relationships questions with answers

1) Thermodynamic Properties and Relationships 1) Thermodynamic Properties and Relationships .g.e Given pand x NIST(Tables get) s,s,T then s s s(2.0 )s ⇒ f g = f + g − f sg sf s Entropy definition (change): rev 2 1 2 1 T Q S S S ∫       δ ∆ = − = TdS equations: (J/K) TdS = dU + pdV ),J( Tds = du + pdυ kg/J( ) TdS = dH − Vdp ),J( Tds = dh − υdp kg/J( ) This study source was downloaded by from CourseH on :56:59 GMT -06:00 11/26/2015 2 1) Thermodynamic Properties and Relationships Special Cases – Analytic Expressions Ideal Gas: Intermolecular Forces are negligible, Z=1 Equation of state: pυ = RT p( = ρRT pV, = mRT) Internal Energy and Enthalpy are only functions of Temperature. , p p lnR T dT lnR , s s s )T(c T dT s s s )T(c , h h h dT)T(c dT dh )T(c , u u u dT)T(c dT du )T(c 2 1 2 1 2 1 2 1 T T 1 2 2 1 p T T 1 2 2