AMAN TILAK
[ PRESENTS ]
UDAAN 1 HOUR NEET mini TEST
SOLUTIONS
SYLLABUS
PHYSICS - Motion in 2 D
CHEMISTRY - Chemical Bonding
BIOLOGY - Morphology of Flowering Plants
S.No. Subject(s) No. of Mark(s)* Type of
Questions *(Each Question Carries 04 (Four) marks) Question(s)
1 PHYSICS 15 60 MCQ
( Multiple
2 CHEMISTRY 15 60 Choice
3 BIOLOGY 30 120 Questions)
TOTAL MARKS 240
Note : Correct option marked will be given (4) marks and Incorrect option marked will be minus
one (-1) mark. Unattempted / Unanswered Questions will be given no marks.
The Important points to note :
1. Each question carries 04 (four) marks and, for each correct answer candidate will get 04 (four) marks.
2. For each incorrect answer, 01 (one) mark will be deducted from the total score.
3. To answer a question, the candidate has to find, for each question, the correct answer / best option.
4. NEET 2021 New Pattern + 4 -1 Marking | Total Marks : 240
Dr. Jyotsana | Dr. Ashwani | Dr. Rajat | Dr. Praveen | dr. piyush | er. nikhil | dr. sudhir
, ANSWER KEYS AND DETAILED SOLUTIONS
PHYSICS
R 1
1. (b) cos = = = 60
B 2
Angle between A and B = 90° + = 150°
2. (a) A1 = 2, A2 = 3, | A1 + A 2 | = 3
| A1 + A 2 | 2 = 9
A12 + A 22 + 2A1 .A 2 = 9
22 + 32 + 2A1 .A 2 = 9 A1 .A 2 = −2
Now, (A1 + 2A 2 ).(3A1 − 4A 2 ) = 3A12 − 8A 22 + 2A1 .A 2
= 3(2)2 – 8(3)2 + 2(-2)
= - 64
3. (d) A.B = 0 (given) A⊥B
A . C = 0 (given) A⊥C
A is perpendicular to both B and C .
We know from the definition of cross product that B C is perpendicular to both B
and C .
So A is parallel to B C .
4. (c) OCand OA are equal in magnitude and inclined to each other at an angle of 90°.
So their resultant is 2r . It acts mid-way between OCand OA , i.e., along OB.
Now, both r and 2r are along the same line and in the same direction.
Resultant = r + 2r = r(1 + 2)
5. (b) Displacement= AB , angle between r1 and r2 is = 75° - 15° = 60°
From Figure, AB2 = r12 + r22 − 2r1r2 cos
= 32 + 42 – 2 × 3 × 4 cos 60° = 13
AB = 13
6. (a) The horizontal distance covered by bomb,
2h 2 80
BC = v H = 150 = 660 m
g 10
[ PRESENTS ]
UDAAN 1 HOUR NEET mini TEST
SOLUTIONS
SYLLABUS
PHYSICS - Motion in 2 D
CHEMISTRY - Chemical Bonding
BIOLOGY - Morphology of Flowering Plants
S.No. Subject(s) No. of Mark(s)* Type of
Questions *(Each Question Carries 04 (Four) marks) Question(s)
1 PHYSICS 15 60 MCQ
( Multiple
2 CHEMISTRY 15 60 Choice
3 BIOLOGY 30 120 Questions)
TOTAL MARKS 240
Note : Correct option marked will be given (4) marks and Incorrect option marked will be minus
one (-1) mark. Unattempted / Unanswered Questions will be given no marks.
The Important points to note :
1. Each question carries 04 (four) marks and, for each correct answer candidate will get 04 (four) marks.
2. For each incorrect answer, 01 (one) mark will be deducted from the total score.
3. To answer a question, the candidate has to find, for each question, the correct answer / best option.
4. NEET 2021 New Pattern + 4 -1 Marking | Total Marks : 240
Dr. Jyotsana | Dr. Ashwani | Dr. Rajat | Dr. Praveen | dr. piyush | er. nikhil | dr. sudhir
, ANSWER KEYS AND DETAILED SOLUTIONS
PHYSICS
R 1
1. (b) cos = = = 60
B 2
Angle between A and B = 90° + = 150°
2. (a) A1 = 2, A2 = 3, | A1 + A 2 | = 3
| A1 + A 2 | 2 = 9
A12 + A 22 + 2A1 .A 2 = 9
22 + 32 + 2A1 .A 2 = 9 A1 .A 2 = −2
Now, (A1 + 2A 2 ).(3A1 − 4A 2 ) = 3A12 − 8A 22 + 2A1 .A 2
= 3(2)2 – 8(3)2 + 2(-2)
= - 64
3. (d) A.B = 0 (given) A⊥B
A . C = 0 (given) A⊥C
A is perpendicular to both B and C .
We know from the definition of cross product that B C is perpendicular to both B
and C .
So A is parallel to B C .
4. (c) OCand OA are equal in magnitude and inclined to each other at an angle of 90°.
So their resultant is 2r . It acts mid-way between OCand OA , i.e., along OB.
Now, both r and 2r are along the same line and in the same direction.
Resultant = r + 2r = r(1 + 2)
5. (b) Displacement= AB , angle between r1 and r2 is = 75° - 15° = 60°
From Figure, AB2 = r12 + r22 − 2r1r2 cos
= 32 + 42 – 2 × 3 × 4 cos 60° = 13
AB = 13
6. (a) The horizontal distance covered by bomb,
2h 2 80
BC = v H = 150 = 660 m
g 10
