AEE1000 / MEC1151- Electrical Circuits and Analysis
Dr Hong Fan, University of Glasgow, 2022
Tutorial – Topic 4 : Circuit Theorems
[Linearity Property]
4.1 For the circuit in Figure 4.1, assume vo = 1 V, and use linearity to find the actual value of vo.
12=2+4
= Gr
'
( { + to )
-
brH6n =
= 3h
ñi : ñi V0
R = 3+3
¥"33n
Figure 4.1
= Gr
'
6h16m = (÷ + f- g-
= 3h
V0 = I V
us
• in "
voltage divider
§3r
rule
,
R 3h
I =
when V0 IV
Vs =
,
Rea 10
Vg =
✓
[Superposition] i.
Vs = 2 ÷ ¥ 3
4.2 Given the circuit in Figure 4.2, use superposition to get io.
=
%✓ : . When Vs = 15W
,
I turn off 2A 3,4A V0 = 4- 5V
#
i'
+
tut3h Nt
+
> Min
-
t&
2h
2
+
3 turn off ITV } 2A
iii. Win
+;"=%
LIV
-
5h
÷§ᵗ
' "
(÷
"
Req =
4 + +
3+2 + g) A
5h 4A
ION
- -
= 9h
V '
i. i. = 3
Req v
I
i¥§
=
9
=
%A
4A
2 turn off 12W } 4A Figure 4.2 ion
-
5h -
2A
2A
A A
7
ᵗ
current divider rule
Using ,
using current divider rule ,
ii.
3
" " " £
+
M3^1 Mi
•
= × 2 "☐
Min
+ =
>
29=+7+3 4
-
×
In 5+5 +
(+4+40)-1
: > =
a =
14
A
g-
-
ion
'
5h
" " "^
I
+
'
-
Mt : I = ×
7
%)
_
,
( ÷,
-
Runt Dion = +
(F- 7) i 10
¥
+ n ,, '5 :
.
=
, ×
4+10
=
F-
§A
n
Copp direction I
= -
¥ direction )
.
=
A Copp
-
.
1 I
: io =
,
+ I, + is
4
=
3- + C- §) + ( -
¥)
≈ -
0.111 A
#
Dr Hong Fan, University of Glasgow, 2022
Tutorial – Topic 4 : Circuit Theorems
[Linearity Property]
4.1 For the circuit in Figure 4.1, assume vo = 1 V, and use linearity to find the actual value of vo.
12=2+4
= Gr
'
( { + to )
-
brH6n =
= 3h
ñi : ñi V0
R = 3+3
¥"33n
Figure 4.1
= Gr
'
6h16m = (÷ + f- g-
= 3h
V0 = I V
us
• in "
voltage divider
§3r
rule
,
R 3h
I =
when V0 IV
Vs =
,
Rea 10
Vg =
✓
[Superposition] i.
Vs = 2 ÷ ¥ 3
4.2 Given the circuit in Figure 4.2, use superposition to get io.
=
%✓ : . When Vs = 15W
,
I turn off 2A 3,4A V0 = 4- 5V
#
i'
+
tut3h Nt
+
> Min
-
t&
2h
2
+
3 turn off ITV } 2A
iii. Win
+;"=%
LIV
-
5h
÷§ᵗ
' "
(÷
"
Req =
4 + +
3+2 + g) A
5h 4A
ION
- -
= 9h
V '
i. i. = 3
Req v
I
i¥§
=
9
=
%A
4A
2 turn off 12W } 4A Figure 4.2 ion
-
5h -
2A
2A
A A
7
ᵗ
current divider rule
Using ,
using current divider rule ,
ii.
3
" " " £
+
M3^1 Mi
•
= × 2 "☐
Min
+ =
>
29=+7+3 4
-
×
In 5+5 +
(+4+40)-1
: > =
a =
14
A
g-
-
ion
'
5h
" " "^
I
+
'
-
Mt : I = ×
7
%)
_
,
( ÷,
-
Runt Dion = +
(F- 7) i 10
¥
+ n ,, '5 :
.
=
, ×
4+10
=
F-
§A
n
Copp direction I
= -
¥ direction )
.
=
A Copp
-
.
1 I
: io =
,
+ I, + is
4
=
3- + C- §) + ( -
¥)
≈ -
0.111 A
#
