GENERAL SIR JOHN KOTELAWALA DEFENSE UNIVERSITY
DEPARTMENT OF ELECTRICAL, ELECTRONIC & TELECOMMUNICATION
ENGINEERING
BM4162
Biomechanics II
Assignment 01
Lecturer Dr. PPCR Karunasekara
Name RADVS RANASINGHE
Reg. No D/ENG/18/0094
Intake 35
Stream BIOMEDICAL ENGINEERING
, Question 01
a) Vertical displacement of the heel marker from TOR (frame 1) to the next TOR (frame 70)
b) Instant of heel-off during midstance = (from the graph)
= 0.801s
c) Maximum height of the heel above the ground = 0.2692-0.0384
= 0.2308m
The maximum height of the heel is found by using the peak of the graph following the first toe
off(TOR) of the right leg, which corresponds to frame no: 06 at time 0.072s. The ground level height
is found using the vertical displacement during heel contact of right leg(HCR) , which corresponds to
frame no: 28 at time 0.386s.
This occurs during the mid-swing phase, where the maximum height is achieved by the heel.
2
DEPARTMENT OF ELECTRICAL, ELECTRONIC & TELECOMMUNICATION
ENGINEERING
BM4162
Biomechanics II
Assignment 01
Lecturer Dr. PPCR Karunasekara
Name RADVS RANASINGHE
Reg. No D/ENG/18/0094
Intake 35
Stream BIOMEDICAL ENGINEERING
, Question 01
a) Vertical displacement of the heel marker from TOR (frame 1) to the next TOR (frame 70)
b) Instant of heel-off during midstance = (from the graph)
= 0.801s
c) Maximum height of the heel above the ground = 0.2692-0.0384
= 0.2308m
The maximum height of the heel is found by using the peak of the graph following the first toe
off(TOR) of the right leg, which corresponds to frame no: 06 at time 0.072s. The ground level height
is found using the vertical displacement during heel contact of right leg(HCR) , which corresponds to
frame no: 28 at time 0.386s.
This occurs during the mid-swing phase, where the maximum height is achieved by the heel.
2
