Introduction to ADC and DAC
ALL ABOUT ELECTRONICS
We all are using this [UNK] and the [UNK] in our day
to day life. Most of the signals which we nd around
us are analog in nature.. Digital signals are less
susceptible to the noise and they are easy to process
and store in the digital domain. But conversions are
not lossless.. That means during the conversion,
some information of the analog signal will be lost..
THe analog signal is sampled at a particular rate and
quantized in nite levels. After the quantization, This
signal is encoded in the binary format.. THe resolution
of the [UNK] decides how the assigned value or the
quantized value is close to the actual value.. THis
resolution de nes the minimum change in the input
signal, which can be detected by the [UNK] For
example, for a 3 bit [UNK]. The full-scale range is
[UNK] divided by 2 to the power N. IF. The full-scale
range of the [UNK] is [UNK]. The resolution of the
given [UNK] will be equal to [UNK] divided by 2 to the
power 3.. That is equal to 125 [UNK] SO, by changing
the reference voltage, the minimum detectable voltage
can be increased. But at the same time, the
conversion range will also reduce. In a way, we can
say that there is a trade-off for changing the voltage..
fi fi
ALL ABOUT ELECTRONICS
We all are using this [UNK] and the [UNK] in our day
to day life. Most of the signals which we nd around
us are analog in nature.. Digital signals are less
susceptible to the noise and they are easy to process
and store in the digital domain. But conversions are
not lossless.. That means during the conversion,
some information of the analog signal will be lost..
THe analog signal is sampled at a particular rate and
quantized in nite levels. After the quantization, This
signal is encoded in the binary format.. THe resolution
of the [UNK] decides how the assigned value or the
quantized value is close to the actual value.. THis
resolution de nes the minimum change in the input
signal, which can be detected by the [UNK] For
example, for a 3 bit [UNK]. The full-scale range is
[UNK] divided by 2 to the power N. IF. The full-scale
range of the [UNK] is [UNK]. The resolution of the
given [UNK] will be equal to [UNK] divided by 2 to the
power 3.. That is equal to 125 [UNK] SO, by changing
the reference voltage, the minimum detectable voltage
can be increased. But at the same time, the
conversion range will also reduce. In a way, we can
say that there is a trade-off for changing the voltage..
fi fi