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Beginners guide to DSA

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This document will start your journey into the topic called dynamic programming. This will help you understand various data structures like Loops, Lists, and queues.

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We will learn about flow charts, pseudocode and programming
languages. We will also learn about programming languages and why
do we use them. After this, we will write our program. This will be our
flow whenever we will solve any problem. First question, then given
values, then approach and at last we will code it. Bhaiya explains what is
a flowchart is a diagramatic approach of that approach known as flow
chart. The flow chart constitute various components, connected with
each other Bhaiyan says. He says that from where a program is starting
we have a component called terminator. Terminator is used to show the
start and end start of the program. Next block is a simple rectangle,
which shows a process. Bhaiya explains how to make a flowchart for the
sum of 2 numbers. He says the pseudocode as a whole is a generic way
of representing logic. The flow of a flow chart is the same as the flow of
the components of the flow chart. We use parallelogram to show the
input/output of the program.

We want to make a flowchart for calculating simple interest This is the
formula for simple interest You must have studied it in your school We
started our program from this start block I do n't know p , r , t , so I
need to take them as inputs first So I asked user to give me the values
for p, r and t So now I have P , R and T So I made this rectangular block
for the calculation part Here I wrote this formula After finding this
answer in the above calculation , I have to print the output too So here I
will print output with this block print SI and then we will end this
program We started the program , took a , b as input then we checked
whether a is less than b or not. If a < b print `` YES '' else print `` NO ''
and its done Simple You just have to write in english what you are
thinking and it is called pseudocode. If any number has 2 as its factor ,
then it is even number or ODD number. We have to check a condition
that whether N is ODD or EVEN , so we will make one block for this
condition Here is the decision making block , Is N % 2 = 0 ? We will get
2 outputs , YES or NO If output is YES, then it is an EVEN number , so I
printed ODD Else, I will print ODD Then I made this end block and
ended this program something like this This is the flowchart for EVEN ,
ODD Got it right ? Bhaiya, why are you putting this inverting commas
again and again , you will come to know soon.

We have to print something and then increment too You have to Print
and then increase the printed number too You can see here , we printed

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Uploaded on
February 26, 2023
Number of pages
2
Written in
2022/2023
Type
Class notes
Professor(s)
Luv babbar
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