We will learn about flow charts, pseudocode and programming languages. We will also learn
about programming languages and why do we use them. After this, we will write our
program. This will be our flow whenever we will solve any problem. First question, then
given values, then approach and at last we will code it. Bhaiya explains what is a flowchart is
a diagramatic approach of that approach known as flow chart. The flow chart constitute
various components, connected with each other Bhaiyan says. He says that from where a
program is starting we have a component called terminator. Terminator is used to show the
start and end start of the program. Next block is a simple rectangle, which shows a process.
Bhaiya explains how to make a flowchart for the sum of 2 numbers. He says the pseudocode
as a whole is a generic way of representing logic. The flow of a flow chart is the same as the
flow of the components of the flow chart. We use parallelogram to show the input/output of
the program.
This Passage provides insights into programming languages, flow charts,, and pseudocode..
The author discusses how these tools can be used to solve problems.. He also provides an
example problem and the solution he comes up with in pseudocode. Finally, he explains how
to convert these solutions into executable code. The flowchart in this passage shows the
process of a program, including the various components that are used to create it.. The first
component is the terminator, which shows the start and end of the program... The next block
is a simple rectangle, which shows a process.. The next block is a diamond-shaped block,
which is used for decision making.. The next block is an arrow, which connects the previous
two blocks.. The last component is a circle, which is used to connect the previous three
blocks.. The code block that starts. The program will take in two numbers, A and B, and will
print out their sum as 5 and 10. After that, the program will end..
We want to make a flowchart for calculating simple interest This is the formula for simple
interest You must have studied it in your school We started our program from this start block
I do n't know p , r , t , so I need to take them as inputs first So I asked user to give me the
values for p, r and t So now I have P , R and T So I made this rectangular block for the
calculation part Here I wrote this formula After finding this answer in the above calculation ,
I have to print the output too So here I will print output with this block print SI and then we
will end this program We started the program , took a , b as input then we checked whether a
is less than b or not. If a < b print `` YES '' else print `` NO '' and its done Simple You just
have to write in english what you are thinking and it is called pseudocode. If any number has
2 as its factor , then it is even number or ODD number. We have to check a condition that
whether N is ODD or EVEN , so we will make one block for this condition Here is the
decision making block , Is N % 2 = 0 ? We will get 2 outputs , YES or NO If output is YES,
then it is an EVEN number , so I printed ODD Else, I will print ODD Then I made this end
block and ended this program something like this This is the flowchart for EVEN , ODD Got
it right ? Bhaiya, why are you putting this inverting commas again and again , you will come
to know soon.
We have to print something and then increment too You have to Print and then increase the
printed number too You can see here , we printed and then increased the numbe by 1 But we
do n't know how to do it How we will increase again and again Let 's rub it You know that we
have to start from 1 and print till 5 So if I give you a number which starts from 1 to 5, will it
work ? Your are like , yes , this is what we needed So I took a number =1 This is not a input ,
it is a process , so I wrote it inside rectangular block. You have to print all the odd numbers
from 1 to N as a part of your homework. The catch is , 1 and N are inclusive here in the
answer should be 15. The solution is easy , you just have to use less than equal to instead of
less than. We know that we have to start with num=1 and increment it till N I know N = 5 ,
Num =1 , and sum =0 in the beginning. Then I added number in the sum and incremented the
number by 1 and then again did the same thing over and over again In the beginning , number
about programming languages and why do we use them. After this, we will write our
program. This will be our flow whenever we will solve any problem. First question, then
given values, then approach and at last we will code it. Bhaiya explains what is a flowchart is
a diagramatic approach of that approach known as flow chart. The flow chart constitute
various components, connected with each other Bhaiyan says. He says that from where a
program is starting we have a component called terminator. Terminator is used to show the
start and end start of the program. Next block is a simple rectangle, which shows a process.
Bhaiya explains how to make a flowchart for the sum of 2 numbers. He says the pseudocode
as a whole is a generic way of representing logic. The flow of a flow chart is the same as the
flow of the components of the flow chart. We use parallelogram to show the input/output of
the program.
This Passage provides insights into programming languages, flow charts,, and pseudocode..
The author discusses how these tools can be used to solve problems.. He also provides an
example problem and the solution he comes up with in pseudocode. Finally, he explains how
to convert these solutions into executable code. The flowchart in this passage shows the
process of a program, including the various components that are used to create it.. The first
component is the terminator, which shows the start and end of the program... The next block
is a simple rectangle, which shows a process.. The next block is a diamond-shaped block,
which is used for decision making.. The next block is an arrow, which connects the previous
two blocks.. The last component is a circle, which is used to connect the previous three
blocks.. The code block that starts. The program will take in two numbers, A and B, and will
print out their sum as 5 and 10. After that, the program will end..
We want to make a flowchart for calculating simple interest This is the formula for simple
interest You must have studied it in your school We started our program from this start block
I do n't know p , r , t , so I need to take them as inputs first So I asked user to give me the
values for p, r and t So now I have P , R and T So I made this rectangular block for the
calculation part Here I wrote this formula After finding this answer in the above calculation ,
I have to print the output too So here I will print output with this block print SI and then we
will end this program We started the program , took a , b as input then we checked whether a
is less than b or not. If a < b print `` YES '' else print `` NO '' and its done Simple You just
have to write in english what you are thinking and it is called pseudocode. If any number has
2 as its factor , then it is even number or ODD number. We have to check a condition that
whether N is ODD or EVEN , so we will make one block for this condition Here is the
decision making block , Is N % 2 = 0 ? We will get 2 outputs , YES or NO If output is YES,
then it is an EVEN number , so I printed ODD Else, I will print ODD Then I made this end
block and ended this program something like this This is the flowchart for EVEN , ODD Got
it right ? Bhaiya, why are you putting this inverting commas again and again , you will come
to know soon.
We have to print something and then increment too You have to Print and then increase the
printed number too You can see here , we printed and then increased the numbe by 1 But we
do n't know how to do it How we will increase again and again Let 's rub it You know that we
have to start from 1 and print till 5 So if I give you a number which starts from 1 to 5, will it
work ? Your are like , yes , this is what we needed So I took a number =1 This is not a input ,
it is a process , so I wrote it inside rectangular block. You have to print all the odd numbers
from 1 to N as a part of your homework. The catch is , 1 and N are inclusive here in the
answer should be 15. The solution is easy , you just have to use less than equal to instead of
less than. We know that we have to start with num=1 and increment it till N I know N = 5 ,
Num =1 , and sum =0 in the beginning. Then I added number in the sum and incremented the
number by 1 and then again did the same thing over and over again In the beginning , number
