1
ARJUNA JEE 2023
Wave Motion DPP-02
1. The energy in the superposition of waves: 5. The periodic waves of amplitude 5m and 2m
(1) Is lost respectively, pass together through a region. The
(2) Increase difference in the maximum and the minimum
(3) remain same, only redistribution occurs resultant amplitude possible is
(1) 5 m (2) 2 m
(4) None of the above
(3) 4 m (4) 1 m
2. Two waves of intensity ratio of 9 : 1 what will be 6. Two waves of equal amplitude when superposed, give
ratio of maximum and minimum intensity in a resultant wave having an amplitude equal to that of
interference pattern of these waves: either wave. The phase difference between the two
(1) 10 : 8 waves is
(2) 7 : 2
(1) radian (2) Zero
(3) 4 : 1 3
(4) 2 : 1 2
(3) radian (4) radian
2 3
3. For constructive interference condition is:
(1) Same phase 7. Three coherent waves having amplitudes
(2) Phase difference is even integral multiple of n 12 mm, 6 mm and 4 mm arrive at a given point with
(3) Path difference is integer multiple of successive phase difference of π/2 . Then, the
(4) All of the above amplitude of the resultant wave is
(1) 7 mm (2) 10 mm
(3) 5 mm (4) 4.8 mm
4. Four waves are described by equations as follow
Y1 = A cos(t − kx) 8. Two interfering waves of the same frequency have an
A intensity ratio 16 : 1. The ratio of intensities at the
Y2 = cos t − kx + maxima and minima is
2 2
(1) 25/16 (2) 9
A
Y3 = cos ( t − kx + ) (3) 4 (4) 25/9
4
A 3 9. Two interfering waves of the same frequency have
Y4 = cos t − kx + amplitudes in the ratio 1 : 3,. If the intensity of the
8 2
first wave, is I, the intensity at the maxima of
and their resultant wave is calculated as interference is
Y = Y1 + Y2 + Y3 + Y4 such as (1) 16 I (2) 8 I
Y = A1cos(t – kx + ) then …….(symbols have their (3) 4 I (4) 64 I
usual meanings)
10. Two interfering waves of the same frequency have
5A 1
(1) A1 = = tan −1 amplitudes in the ratio 1 : 3,. If the intensity of the
8 4 first wave, is I, the intensity at the minima is
2 5A 1 (1) zero (2) 2 I
(2) A1 = = tan −1 (3) 4 I (4) 8 I
8 3
3 5A 1
(3) A1 = = tan −1 11. Waves from two sources of intensities I and 4 I
8 2 interfere at a point. The resultant intensity at a point
4 5A where the phase difference is /2 is
(4) A1 = = tan–1 (1) (1) 9 I (2) 5 I
8
(3) 3 I (4) I
ARJUNA JEE 2023
Wave Motion DPP-02
1. The energy in the superposition of waves: 5. The periodic waves of amplitude 5m and 2m
(1) Is lost respectively, pass together through a region. The
(2) Increase difference in the maximum and the minimum
(3) remain same, only redistribution occurs resultant amplitude possible is
(1) 5 m (2) 2 m
(4) None of the above
(3) 4 m (4) 1 m
2. Two waves of intensity ratio of 9 : 1 what will be 6. Two waves of equal amplitude when superposed, give
ratio of maximum and minimum intensity in a resultant wave having an amplitude equal to that of
interference pattern of these waves: either wave. The phase difference between the two
(1) 10 : 8 waves is
(2) 7 : 2
(1) radian (2) Zero
(3) 4 : 1 3
(4) 2 : 1 2
(3) radian (4) radian
2 3
3. For constructive interference condition is:
(1) Same phase 7. Three coherent waves having amplitudes
(2) Phase difference is even integral multiple of n 12 mm, 6 mm and 4 mm arrive at a given point with
(3) Path difference is integer multiple of successive phase difference of π/2 . Then, the
(4) All of the above amplitude of the resultant wave is
(1) 7 mm (2) 10 mm
(3) 5 mm (4) 4.8 mm
4. Four waves are described by equations as follow
Y1 = A cos(t − kx) 8. Two interfering waves of the same frequency have an
A intensity ratio 16 : 1. The ratio of intensities at the
Y2 = cos t − kx + maxima and minima is
2 2
(1) 25/16 (2) 9
A
Y3 = cos ( t − kx + ) (3) 4 (4) 25/9
4
A 3 9. Two interfering waves of the same frequency have
Y4 = cos t − kx + amplitudes in the ratio 1 : 3,. If the intensity of the
8 2
first wave, is I, the intensity at the maxima of
and their resultant wave is calculated as interference is
Y = Y1 + Y2 + Y3 + Y4 such as (1) 16 I (2) 8 I
Y = A1cos(t – kx + ) then …….(symbols have their (3) 4 I (4) 64 I
usual meanings)
10. Two interfering waves of the same frequency have
5A 1
(1) A1 = = tan −1 amplitudes in the ratio 1 : 3,. If the intensity of the
8 4 first wave, is I, the intensity at the minima is
2 5A 1 (1) zero (2) 2 I
(2) A1 = = tan −1 (3) 4 I (4) 8 I
8 3
3 5A 1
(3) A1 = = tan −1 11. Waves from two sources of intensities I and 4 I
8 2 interfere at a point. The resultant intensity at a point
4 5A where the phase difference is /2 is
(4) A1 = = tan–1 (1) (1) 9 I (2) 5 I
8
(3) 3 I (4) I
