Refresher - MATHEMATICS Quiz 5
PROBLEM 1:
From the given expansion of partial fractions, determine the value of A.
2x 4 + 3x 3 + 7x 2 + 10x + 10 A Bx + C Dx + E
= + +
(x - 1)(x 2 + 3)2 x - 1 x 2 + 3 (x 2 + 3)2
Solution
2x4 + 3x3 + 7x2 + 10x + 10 = A(x2 + 3)2 + (Bx + C)(x – 1)(x2 + 3)
+ (Dx + E)(x - 1)
when x = 1
2(1) + 3(1) + 7(1) + 10 + 10 = A(4)2 + 0 + 0
A=2
, Refresher - MATHEMATICS Quiz 5
PROBLEM 2:
A ship is sailing due East when a light is observed bearing N. 62˚10’ E. After the
ship has traveled 2250 m. the light bears N. 48˚25’ E. If the course is continued,
how close will the ship approach the light?
Solution: 62 10’
o Light
2250 BL 13 45’
o
48 25’
o
=
Sin 13˚ 45' Sin 27˚50' N h
48 25’
o
BC = 4419.82 62 10’E
o
138 35’
o
41 35’
o
27 50’
o
LC = 4419.82 Sin 41˚35'
A 2250 m Ship C
LC = 2934 ft. B
PROBLEM 1:
From the given expansion of partial fractions, determine the value of A.
2x 4 + 3x 3 + 7x 2 + 10x + 10 A Bx + C Dx + E
= + +
(x - 1)(x 2 + 3)2 x - 1 x 2 + 3 (x 2 + 3)2
Solution
2x4 + 3x3 + 7x2 + 10x + 10 = A(x2 + 3)2 + (Bx + C)(x – 1)(x2 + 3)
+ (Dx + E)(x - 1)
when x = 1
2(1) + 3(1) + 7(1) + 10 + 10 = A(4)2 + 0 + 0
A=2
, Refresher - MATHEMATICS Quiz 5
PROBLEM 2:
A ship is sailing due East when a light is observed bearing N. 62˚10’ E. After the
ship has traveled 2250 m. the light bears N. 48˚25’ E. If the course is continued,
how close will the ship approach the light?
Solution: 62 10’
o Light
2250 BL 13 45’
o
48 25’
o
=
Sin 13˚ 45' Sin 27˚50' N h
48 25’
o
BC = 4419.82 62 10’E
o
138 35’
o
41 35’
o
27 50’
o
LC = 4419.82 Sin 41˚35'
A 2250 m Ship C
LC = 2934 ft. B
