Score for this quiz: 100 out of 100
Submitted May 6 at 3:13pm
This attempt took 14 minutes.
Question 1
16..67 pts
A researcher sets the significance level (α) at .01. If the results of the
accept
statistical analysis reveal a p-value of .015, the researcher should
the null hypothesis. The potential error that the researcher is making is a
II
Type error.
Answer 1:
accept
alpha is .01 p value is .015
Using above hypothesis. Patient satisfaction is better in patients cared for solely by
a registered nurse as compared to patient satisfaction in patients cared for by a
team of caregivers.
Study would compare mean (average) patient satisfaction scores for both groups
and compare looking for a statistically significant difference. Alpha is set by
researcher to .01. Testing results in a p value of .015.
This test would be considered non-significant (no difference between groups or
between phenomena (as p is greater than the alpha). Null hypothesis is defined as
no difference between groups so in this example we accept the null hypothesis as
there is no difference. In this example, we accepted the null hypothesis that there
was no difference; however, there is a potential there was a difference and we failed
to detect so there is a potential for a type II error. (Remember from above: Type I
errors occur when we reject a null hypothesis that is actually true. Type II
errors occur when a researcher fails to reject a false null hypothesis (a "false
negative", i.e., rejecting a true hypothesis as incorrect).
Answer 2:
II
alpha is .01 p value is .015
Using above hypothesis. Patient satisfaction is better in patients cared for
solely by a registered nurse as compared to patient satisfaction in patients
cared for by a team of caregivers.
Study would compare mean (average) patient satisfaction scores for both
groups and compare looking for a statistically significant difference. Alpha is
set by researcher to .01. Testing results in a p value of .015.
This test would be considered non-significant (no difference between groups
or between phenomena (as p is greater than the alpha). Null hypothesis is
defined as no difference between groups so in this example we accept the
This study source was downloaded by 100000866399126 from CourseHero.com on 05-06-2023 16:00:17 GMT -05:00
https://www.coursehero.com/file/146831736/Nurs-5366-Assignment-5-Hypothesis-Testingdocx/
Submitted May 6 at 3:13pm
This attempt took 14 minutes.
Question 1
16..67 pts
A researcher sets the significance level (α) at .01. If the results of the
accept
statistical analysis reveal a p-value of .015, the researcher should
the null hypothesis. The potential error that the researcher is making is a
II
Type error.
Answer 1:
accept
alpha is .01 p value is .015
Using above hypothesis. Patient satisfaction is better in patients cared for solely by
a registered nurse as compared to patient satisfaction in patients cared for by a
team of caregivers.
Study would compare mean (average) patient satisfaction scores for both groups
and compare looking for a statistically significant difference. Alpha is set by
researcher to .01. Testing results in a p value of .015.
This test would be considered non-significant (no difference between groups or
between phenomena (as p is greater than the alpha). Null hypothesis is defined as
no difference between groups so in this example we accept the null hypothesis as
there is no difference. In this example, we accepted the null hypothesis that there
was no difference; however, there is a potential there was a difference and we failed
to detect so there is a potential for a type II error. (Remember from above: Type I
errors occur when we reject a null hypothesis that is actually true. Type II
errors occur when a researcher fails to reject a false null hypothesis (a "false
negative", i.e., rejecting a true hypothesis as incorrect).
Answer 2:
II
alpha is .01 p value is .015
Using above hypothesis. Patient satisfaction is better in patients cared for
solely by a registered nurse as compared to patient satisfaction in patients
cared for by a team of caregivers.
Study would compare mean (average) patient satisfaction scores for both
groups and compare looking for a statistically significant difference. Alpha is
set by researcher to .01. Testing results in a p value of .015.
This test would be considered non-significant (no difference between groups
or between phenomena (as p is greater than the alpha). Null hypothesis is
defined as no difference between groups so in this example we accept the
This study source was downloaded by 100000866399126 from CourseHero.com on 05-06-2023 16:00:17 GMT -05:00
https://www.coursehero.com/file/146831736/Nurs-5366-Assignment-5-Hypothesis-Testingdocx/
