Analytical Chemistry Exam

Analytical ChemistryLecture (midterm Exam)
Questions: AnsweRS:


* How many ktions are in 6.75 1 molkt x6.75 molkH2PO4 y
6.022 x109kt 4.06x1884
=




mOl KH2PO4 KHePO4
L avogadro's rule
OF I mol




How millimoles
2. many of 10.0gP20sy 1000mg
ImmolPaOs,2mmol4
x
141mmolP
=




phosphorus are in 10.0g oFPcOs? 19 141.94 mgPzOs ImmolP2OS

MM:141.94
g/mol



3. Find Given:
the ofmmol
number of

0.2SOMAC1
250.0mL of mmol HCl:?
solute in
0.25 x 0.250moly 1000mmol=62.5mmol
L
M moles
=

ofsolute 0.150M HCI I mol


V solution 250.0m) 0.25L =




4. Whati s the mass in grams of 185mmolPbOx1 mol. 223.20gPbO 41.39 x =




185 mmol PbO?
MM: 223.20g/mol? 1000 mmol 1 molPbO




5. Whatis the mass in grams OF
0.0552 0.1250
x
mol
1229
x 0.839
=




L
L
I mol
55mL of0.1250M
↳ssmL
solute in

0.1250M
benzoic acid (MM=122g/mol)?



6. Calculate the Ago ofa
H30 antilog) 5.60)
=
-




M
-




solution thathas a pHof =2.51 x1 0


5. 60




7. Whati s the pH ofa solution pH =
-10g 1.2 10
x
-




3)
thathas a H30t molar
2.92
=




concentration of
1.2x18?


@ ⑯ pHb =-log(3 10 m)
-




8. Average human blood contains x



300 nmol ofhemoglobin Hb) x0 mol 3x10 7M
300nmol
M =


x =
=6.52


per liter ofplasma. Calculate Inmol

the pHb in plasma in human Or


SeRUM. M 300nmol
=



x
1 mol 3x10M
=




L
1 mol 1,000,000,000 nmol=
1000000000 nmol


1 10-9 mol
x Inmol
=




note:

(n) antilog( n)
= - (m0) 1000 mmol
=


1 mol 1,000,000,000 nmol
=



M moles
=



ofsolute
↳ molarity4pH/p-value 10-9 mol
mmol
G
1 Inmol UL solution
/mol-Ix 10 x =




I 4
pH =
-10g (n) avogadro's rule:G.2 x mos apity liters


↳ molarity