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Exam (elaborations)

A volume of 120mL of H2O is initially at room temperature (22.0 degre

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A volume of 120mL of H2O is initially at room temperature (22.0 degree C). A chilled steel rod at 2.00 degree C is placed in the water. If the final temperature of the system is 21.0 degree C , what is the mass of the steel bar? Use the following values: specific heat of water = 4.18 J/(g . degree C) specific heat of steel = 0.452 J/(g . degree C) Express your answer to three significant figures and include the appropriate units. Solution Q gain = Q lost 120* 4.18 (22-21) = m * 0.452 * (21-2) m = 58.407 gm

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A volume of 120mL of H2O is initially at room temperature (22.0 degree C). A chilled steel rod
at 2.00 degree C is placed in the water. If the final temperature of the system is 21.0 degree C ,
what is the mass of the steel bar? Use the following values: specific heat of water = 4.18 J/(g .
degree C) specific heat of steel = 0.452 J/(g . degree C) Express your answer to three significant
figures and include the appropriate units.


Solution
Q gain = Q lost 120* 4.18 (22-21) = m * 0.452 * (21-2) m = 58.407 gm
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June 26, 2023
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Written in
2022/2023
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Exam (elaborations)
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  • volume
  • 120ml
  • h2o
  • initially
  • room
  • temperature
  • degre
  • is
  • 220
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