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Exam (elaborations)

A gas containing carbon and hydrogen analyzed as 92.3 carbon and 7.

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A gas containing carbon and hydrogen analyzed as 92.3 % carbon and 7.7 % hydrogen. A 3.12 g sample of a gas occupied a volume of 1170 ml with a pressure of 3.7 atm at 166 degree C. Enter the molecular formula of the compound. Solution Using, PV = nRT (3.7atm) x (1.17L) = (3.12/Mol. mass) x (0.08206 L-atm/mol-K) x (439K) Solving for Mol. mass, we get Mol. mass = 25.96 g Mass of C = 0.923 x 25.96 g = 23.96 g Mass of H = 0.077 x 25.96 g = 2.00 g Thus, moles of H = 2.00/1.00 = 2 Moles of C = 23.96/12.00 = 2 Thus, formula of compound = C2H2.

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HBO Small Business En Ondernemerschap
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HBO Small Business en Ondernemerschap

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Arrange the steps of DNA replication in the order that they occur. DNA polymerase synthesizes
DNA. DNA ligase joins DNA fragments together. Single-stranded DNA-binding proteins bind
to each template strand. Helicase unwinds the DNA double helix. RNA primers are added.
RNA primers are removed.


Solution
Helicase unwinds the DNA double helix Single-stranded DNA-binding proteins bind to each
template strand RNA primers added DNA polymerase synthesizes DNA RNA primers are
removed DNA ligase joins DNA fragments together
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  • gas
  • containing
  • carbon
  • hydrogen
  • analyzed
  • carbon7
  • as
  • 923
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