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PHYSICS 12 Questions & Answers

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2/13/22, 4:07 PM Golf Range Gizmo : ExploreLearning Print PageASSESSMENT QUESTIONS: UBAIDULLAH HABIBI Q1 Q2 Q3 Q4 Q5 SCORE Your Results saved for class PHYSICS 12 5/5 Questions & Answers       1. The golf ball below has reached the top of its trajectory in the time shown. What will the total hang time be when the ball hits the ground? Assume no air resistance or spin. A. 6.15 seconds B. 8.20 seconds C. 12.30 seconds D. 16.40 seconds Correct Answer: B. 8.20 seconds Explanation: Assuming no spin, the

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2/13/22, 4:07 PM Golf Range Gizmo : ExploreLearning




 ASSESSMENT QUESTIONS: Print Page


UBAIDULLAH HABIBI Q1 Q2 Q3 Q4 Q5 SCORE


Your Results saved for      5/5
class PHYSICS 12



Questions & Answers

1. The golf ball below has reached the top of its trajectory in the time shown. What will the total
hang time be when the ball hits the ground? Assume no air resistance or spin.




A. 6.15 seconds
B. 8.20 seconds
C. 12.30 seconds
D. 16.40 seconds


Correct Answer: B. 8.20 seconds

Explanation: Assuming no spin, the flight of a golf ball is symmetrical; it takes the same
amount of time to go up as it takes to come down. Since it took 4.10 seconds to rise to
the top of it's trajectory, it will take another 4.10 seconds to descend, for a total hang time
of 8.20 seconds.




You answered this question correctly!




This study source was downloaded by 100000844530682 from CourseHero.com on 04-18-2022 15:35:36 GMT -05:00

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, 2/13/22, 4:07 PM Golf Range Gizmo : ExploreLearning


2. The golfer shown below has hit the ball with the initial velocity and launch angle shown. What
was the initial horizontal velocity of the golf ball, vx ?




A. 29.0 m/s
B. 38.7 m/s
C. 41.0 m/s
D. 45.0 m/s


Correct Answer: C. 41.0 m/s

Explanation: To find the horizontal component of velocity, multiply the initial velocity by
the cosine of the launch angle. The cosine of 45° is 0.7071, so the horizontal component
of velocity is 58.0 • 0.7071 = 41.0 m/s.




You answered this question correctly!




3. A cannon shoots a ball with an initial velocity of 152 m/s and a launch angle of 62°. The
gravitational acceleration is 9.8 m/s2. Assuming no air resistance, how long will the cannonball
stay in the air?

A. 24.6 s
B. 27.4 s
C. 31.3 s
D. 39.7 s


Correct Answer: B. 27.4 s
This study source was downloaded by 100000844530682 from CourseHero.com on 04-18-2022 15:35:36 GMT -05:00

https://gizmos.explorelearning.com/index.cfm?method=cResource.dspView&ResourceID=26&ClassID=2144279 2/5
https://www.coursehero.com/file/130192901/Golf-Range-Gizmo-ExploreLearningpdf/

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