Boron Sulphide react violently with water to form boric acid and Hydrogen Sulphide
gas(the smell of rotten eggs).The unbalanced equation is:
(x1)B2S3+ (x2)H2O−→(x3)H3BO 3+ (x4)H2S (1)
Find the value of coefficients x1.x2, x3andx4
B2S3=
B
S
H
O
=
2
3
0
0
H2O=
B
S
H
O
=
0
0
2
1
H3BO 3=
B
S
H
O
=
1
0
3
3
H2S=
B
S
H
O
=
0
1
2
0
x1
2
3
0
0
+x2
0
0
2
1
=x3
1
0
3
3
+x4
0
1
2
0
1 x1
2
3
0
0
+x2
0
0
2
1
−x3
1
0
3
3
−x4
0
1
2
0
=
0
0
0
0
2x1+ 0x2−1x3−0x4
3x1+ 0x2−0x3−1x4
0x1+ 2x2−3x3−2x4
0x1+ 1x2−3x3−0x4
=
0
0
0
0
Augmented Matrix
2 0 −1 0 0
3 0 0 −1 0
0 2 −3−2 0
0 1 −3 0 0
Applying elementary row operation on the matrix
2 0 −1 0 0
3 0 0 −1 0
0 2 −3−2 0
0 2 −6 0 0
2R4
Applying elementary row operation on the matrix
2 0 −1 0 0
3 0 0 −1 0
0 2 −3−2 0
0 0 −3 2 0
R4−R3
2
gas(the smell of rotten eggs).The unbalanced equation is:
(x1)B2S3+ (x2)H2O−→(x3)H3BO 3+ (x4)H2S (1)
Find the value of coefficients x1.x2, x3andx4
B2S3=
B
S
H
O
=
2
3
0
0
H2O=
B
S
H
O
=
0
0
2
1
H3BO 3=
B
S
H
O
=
1
0
3
3
H2S=
B
S
H
O
=
0
1
2
0
x1
2
3
0
0
+x2
0
0
2
1
=x3
1
0
3
3
+x4
0
1
2
0
1 x1
2
3
0
0
+x2
0
0
2
1
−x3
1
0
3
3
−x4
0
1
2
0
=
0
0
0
0
2x1+ 0x2−1x3−0x4
3x1+ 0x2−0x3−1x4
0x1+ 2x2−3x3−2x4
0x1+ 1x2−3x3−0x4
=
0
0
0
0
Augmented Matrix
2 0 −1 0 0
3 0 0 −1 0
0 2 −3−2 0
0 1 −3 0 0
Applying elementary row operation on the matrix
2 0 −1 0 0
3 0 0 −1 0
0 2 −3−2 0
0 2 −6 0 0
2R4
Applying elementary row operation on the matrix
2 0 −1 0 0
3 0 0 −1 0
0 2 −3−2 0
0 0 −3 2 0
R4−R3
2
