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MATH 225N Week 7 Hypothesis Testing Question and
Answers Chamberlain College of Nursing
Psychiatric/Mental Health Nursing (Nevada State College)
,MATH 225N Week 7 Hypothesis Testing Question and Answers
Latest Update 2023 Rated A+
• Steve listens to his favorite streaming music service when he works out. He wonders whether the
service algorithm does a good job of finding random songs that he will like often. To test this, he listens
to 50 songs chosen by the service at random and finds that he likes 32 of them.
Use Excel to test whether Steve will like a randomly selected song more than not and then draw a conclusion
in the context of a problem. Use α = 0.05. Type equation here .
Ho: p = ≤ 0.5 (50%) p = 0.5
Ha: p = > 0.5 (strictly ¿>≠ )
P-value = 0.02 which is < α =0.05 we reject Ho and support the Ha
Hypothesis Test for p
population proportion
Level of (decimal)
Significance Proportion
0.05
under (decimal)
H0 0.5000
n 50
Number of
Successes 32
Sample Proportion 0.640000
StDev 0.500000
SE 0.070711
1.979899
Test Statistic 0.023852
(z) One-Sided p- 0.047704
value Two-Sided
p-value
Right-Tailed (>) 1.644854
-
Left-Tailed (<) 1.644854
Two-Tailed (≠) ± 1.959964
,MATH 225N Week 7 Hypothesis Testing Question and Answers
Latest Update
, Answer: Reject the null hypothesis. There is sufficient evidence to prove that Steve will like a random selected
song more often than not.
• A magazine regularly tested products and gave the reviews to its customers. In one of its
reviews, it tested 2 types of batteries and claimed that the batteries from company A
outperformed batteries from company B in 108 of the tests. There were 200 tests. Company
B decided to sue the magazine, claiming that the results were not significantly different
from 50% and that the magazine was slandering its good name.
Use Excel to test whether the true proportion of times that Company A’s batteries outperformed Company
B’s batteries is different from 0.5. Identify the p=value rounding it to 3 decimal places.
Ho: p = 0.5 Ha ≠ 0.5 (two tailed test) n = 200 (α is not given soleave it 0.05)
Hypothesis Test for p
population proportion
Level of
Significance Proportion 0.05
under
H0 0.5000
n 200
Number of
Successes 108
Sample Proportion
StDev 0.540000
SE 0.500000
Test Statistic 0.035355
1.131371
(z) One-Sided p- 0.129238
value Two-Sided 0.258476
p-value
Right-Tailed (>) 1.644854
-
Left-Tailed (<) 1.644854
Two-Tailed (≠) ± 1.959964
Answer: 0.258 (because it is a two tailed test). We are not rejecting the null hypothesis and we do not have
evidence to support the alternative hypothesis.
• A candidate in an election lost by 5.8% of the vote. The candidate sued the state and said
that more than 5.8% of the ballots were defective and not counted by the voting machine, so
a full recount would need to be done. His opponent wanted to ask for the case to be
dismissed,
MATH 225N Week 7 Hypothesis Testing Question and Answers
MATH 225N Week 7 Hypothesis Testing Question and
Answers Chamberlain College of Nursing
Psychiatric/Mental Health Nursing (Nevada State College)
,MATH 225N Week 7 Hypothesis Testing Question and Answers
Latest Update 2023 Rated A+
• Steve listens to his favorite streaming music service when he works out. He wonders whether the
service algorithm does a good job of finding random songs that he will like often. To test this, he listens
to 50 songs chosen by the service at random and finds that he likes 32 of them.
Use Excel to test whether Steve will like a randomly selected song more than not and then draw a conclusion
in the context of a problem. Use α = 0.05. Type equation here .
Ho: p = ≤ 0.5 (50%) p = 0.5
Ha: p = > 0.5 (strictly ¿>≠ )
P-value = 0.02 which is < α =0.05 we reject Ho and support the Ha
Hypothesis Test for p
population proportion
Level of (decimal)
Significance Proportion
0.05
under (decimal)
H0 0.5000
n 50
Number of
Successes 32
Sample Proportion 0.640000
StDev 0.500000
SE 0.070711
1.979899
Test Statistic 0.023852
(z) One-Sided p- 0.047704
value Two-Sided
p-value
Right-Tailed (>) 1.644854
-
Left-Tailed (<) 1.644854
Two-Tailed (≠) ± 1.959964
,MATH 225N Week 7 Hypothesis Testing Question and Answers
Latest Update
, Answer: Reject the null hypothesis. There is sufficient evidence to prove that Steve will like a random selected
song more often than not.
• A magazine regularly tested products and gave the reviews to its customers. In one of its
reviews, it tested 2 types of batteries and claimed that the batteries from company A
outperformed batteries from company B in 108 of the tests. There were 200 tests. Company
B decided to sue the magazine, claiming that the results were not significantly different
from 50% and that the magazine was slandering its good name.
Use Excel to test whether the true proportion of times that Company A’s batteries outperformed Company
B’s batteries is different from 0.5. Identify the p=value rounding it to 3 decimal places.
Ho: p = 0.5 Ha ≠ 0.5 (two tailed test) n = 200 (α is not given soleave it 0.05)
Hypothesis Test for p
population proportion
Level of
Significance Proportion 0.05
under
H0 0.5000
n 200
Number of
Successes 108
Sample Proportion
StDev 0.540000
SE 0.500000
Test Statistic 0.035355
1.131371
(z) One-Sided p- 0.129238
value Two-Sided 0.258476
p-value
Right-Tailed (>) 1.644854
-
Left-Tailed (<) 1.644854
Two-Tailed (≠) ± 1.959964
Answer: 0.258 (because it is a two tailed test). We are not rejecting the null hypothesis and we do not have
evidence to support the alternative hypothesis.
• A candidate in an election lost by 5.8% of the vote. The candidate sued the state and said
that more than 5.8% of the ballots were defective and not counted by the voting machine, so
a full recount would need to be done. His opponent wanted to ask for the case to be
dismissed,
MATH 225N Week 7 Hypothesis Testing Question and Answers
