Tech Mahindra Aptitude Questions & Answers - Paper 5
Quantitative Aptitude
Topic - Percentages
1. Price of item A was increased by 6% while that of item B was
decreased by P%. After this the price of both the items together
becomes 2% more than it was together earlier. If the price of the
item A and B earlier was in ratio 15:8, find the value of P?
a) 2.5
b) 4
c) 5.5
d) 8
Correct Choice: c
Explanation:
Let initially the price of the items A and B were 15y and 8y respectively.
Price of A was increased by 6%, so final price of item A = 15y + 6% of 15y
= 15y + 0.06 × 15y = 15y + 0.9y = 15.9y
Let the price of item B was reduced by P%, then price of B after reduction =
8y – P% of 8y
, Tech Mahindra Aptitude Questions & Answers - Paper 5
P
= 8y – 8y = [1 – 0.01P] 8y
100
Final price of both the item together is 2% more than the price earlier, so
initial price = 15y + 8y = 23y
Final price = 15.9y + [1 – 0.01P] 8y
Increase in price = final price – initial price = 15.9y + [1 – 0.01P] 8y – 23y =
0.9y – 0.08Py
Increase in price is 2%, so
(0.9y – 0.08Py)
× 100 = 2
23y
90 – 8P = 46
8P = 44
P = 5.5
Thus, the price of item B was reduced by 5.5%.
Hence, option C is correct.
, Tech Mahindra Aptitude Questions & Answers - Paper 5
Topic – Simple Interest – Compound Interest
2. A person deposited some amount in a Bank at 6.75% per annum
simple interest rate. He withdrew all his money after 3 years and
spentRs. 310 from it and then deposited the entire remaining
amount in another Bank at 5 (5/9)% per annum simple interest
rate for 2 years. After 2 years, the total amount he got was Rs.
5000. What was the initial amount he deposited?
a) Rs. 2500
b) Rs. 3500
c) Rs. 4000
d) Rs. 3800
Correct Choice: c
Explanation:
Let the initial amount was Rs. P, then the SI he would got from first bank
deposit would be
(P × 6.75 × 3)
= 0.2025P
100
Total = P + 0.2025p = 1.2025P
He spent Rs. 310 from this, thus the amount he will deposit again would be
= (1.2025P – 310)
Quantitative Aptitude
Topic - Percentages
1. Price of item A was increased by 6% while that of item B was
decreased by P%. After this the price of both the items together
becomes 2% more than it was together earlier. If the price of the
item A and B earlier was in ratio 15:8, find the value of P?
a) 2.5
b) 4
c) 5.5
d) 8
Correct Choice: c
Explanation:
Let initially the price of the items A and B were 15y and 8y respectively.
Price of A was increased by 6%, so final price of item A = 15y + 6% of 15y
= 15y + 0.06 × 15y = 15y + 0.9y = 15.9y
Let the price of item B was reduced by P%, then price of B after reduction =
8y – P% of 8y
, Tech Mahindra Aptitude Questions & Answers - Paper 5
P
= 8y – 8y = [1 – 0.01P] 8y
100
Final price of both the item together is 2% more than the price earlier, so
initial price = 15y + 8y = 23y
Final price = 15.9y + [1 – 0.01P] 8y
Increase in price = final price – initial price = 15.9y + [1 – 0.01P] 8y – 23y =
0.9y – 0.08Py
Increase in price is 2%, so
(0.9y – 0.08Py)
× 100 = 2
23y
90 – 8P = 46
8P = 44
P = 5.5
Thus, the price of item B was reduced by 5.5%.
Hence, option C is correct.
, Tech Mahindra Aptitude Questions & Answers - Paper 5
Topic – Simple Interest – Compound Interest
2. A person deposited some amount in a Bank at 6.75% per annum
simple interest rate. He withdrew all his money after 3 years and
spentRs. 310 from it and then deposited the entire remaining
amount in another Bank at 5 (5/9)% per annum simple interest
rate for 2 years. After 2 years, the total amount he got was Rs.
5000. What was the initial amount he deposited?
a) Rs. 2500
b) Rs. 3500
c) Rs. 4000
d) Rs. 3800
Correct Choice: c
Explanation:
Let the initial amount was Rs. P, then the SI he would got from first bank
deposit would be
(P × 6.75 × 3)
= 0.2025P
100
Total = P + 0.2025p = 1.2025P
He spent Rs. 310 from this, thus the amount he will deposit again would be
= (1.2025P – 310)
