PEagle post Mock joint Exam
MATHEMATICS PAPER 2 MARKING SCHEME
2021
0.05 0.05 M1 Expression for
1. +
50.5 100.5 relative error
**Follow through M1
1.51
for alternative ×100 % A1 Percentage error
methods used…
101505
0.1488 % 03
2. Sin-1
√3 =600 B1 For 600
2
2 θ−30 °=60°
2 θ=90° , θ=45 ° B1
2 θ−30 °=120 °
2θ=150° , θ=75° B1
θ=45 ° ,75 ° 03
3. ym = yn+mn M1 Collect terms in n
ym = n(y+m) M1 factor out n
ym A1
n=
y+ m 03
4. (x-3)2+(y-5)2 = 22 M1 Expression in
C(3, 5) A1 factor form
r=2 B1 Centre
03 Radius
k x2 M1 Correct eqn
5. y =
√z
Kx x2 M1
y1 = =k Inserting changes
√z M1
k ×1.22 A1 % change
y2 = =1.6 k
√ 0.81 04
1.6 k−k
% change = ×100 %=60 % increase
1k
100
6. Cp = ×55=50
110 M1
45 x+ 60 y Expression for
=50 M1 unit cost
x+ y
45 x +60 y=50 x +50 y
5x=10y A1
X :y = 2 :1 03
50 M1 A.S.F.
7. A.S.F = =4
12.5
Det M = x(x-2)-x(-2) = 4 M1 Equating Det to
x2 = 4 A1 A.S.F
x = 2 or x = -2 03 For both
8. Y = ∫ ( 3 x 2−8 x ) dx
= x3 – 4x+c M1
1 = 13-4(1)+c A1 Substituted form
Page 1 of 9 Mathematics Paper 2 M/Scheme
, C=4 B1 For c
Y = x3-4x2+4 03 Equation
9. 2x+3y = 3
x+y = 3 M1 Formation of
equation
2x+3y = 3 M1
2x+2y = 6 Attempt to solve
y = -3
x = 6, y = -3 A1
03 For both x and y
10. Construction of tangent B1 Construction of
600 at centre
B1
Construction of
tangent to locate
P
PO = 3.8± 0.1 B1
03
Length of PO
3 B1 Simplified form
11. Amplitude = =1.5
2 B1 allow 1 ½
360 For period
=720° B1
Period = 1
2 03 Reject – 650
Phase angle = 650
12. P(AR) or P(BR)
3 4 B1 Correct
(½x )+(½x ) probability
10 10
3 1 3 4 M1 Correct
+ or + probability
20 6 20 24
A1 Summation
19 38 03
or 0.316̇
60 120
1 1 2 M1 Expression for the
x )+45(28) ( x ¿ −120 ( 2 ) ¿+ …
7
13. 210-10(29) (
4 4 A1 1st 4 terms
a) 1024-128x-720x2-240x3+...
1
b) 2- x=1.975
4
X= 0.1
(1.975)10 = 1024-1280(0.1)+720(0.1)2 M1 Substitution for x
240(0.1)3+ … A1 = 0.1
= 903 03 CAO
Page 2 of 9 Mathematics Paper 2 M/Scheme
MATHEMATICS PAPER 2 MARKING SCHEME
2021
0.05 0.05 M1 Expression for
1. +
50.5 100.5 relative error
**Follow through M1
1.51
for alternative ×100 % A1 Percentage error
methods used…
101505
0.1488 % 03
2. Sin-1
√3 =600 B1 For 600
2
2 θ−30 °=60°
2 θ=90° , θ=45 ° B1
2 θ−30 °=120 °
2θ=150° , θ=75° B1
θ=45 ° ,75 ° 03
3. ym = yn+mn M1 Collect terms in n
ym = n(y+m) M1 factor out n
ym A1
n=
y+ m 03
4. (x-3)2+(y-5)2 = 22 M1 Expression in
C(3, 5) A1 factor form
r=2 B1 Centre
03 Radius
k x2 M1 Correct eqn
5. y =
√z
Kx x2 M1
y1 = =k Inserting changes
√z M1
k ×1.22 A1 % change
y2 = =1.6 k
√ 0.81 04
1.6 k−k
% change = ×100 %=60 % increase
1k
100
6. Cp = ×55=50
110 M1
45 x+ 60 y Expression for
=50 M1 unit cost
x+ y
45 x +60 y=50 x +50 y
5x=10y A1
X :y = 2 :1 03
50 M1 A.S.F.
7. A.S.F = =4
12.5
Det M = x(x-2)-x(-2) = 4 M1 Equating Det to
x2 = 4 A1 A.S.F
x = 2 or x = -2 03 For both
8. Y = ∫ ( 3 x 2−8 x ) dx
= x3 – 4x+c M1
1 = 13-4(1)+c A1 Substituted form
Page 1 of 9 Mathematics Paper 2 M/Scheme
, C=4 B1 For c
Y = x3-4x2+4 03 Equation
9. 2x+3y = 3
x+y = 3 M1 Formation of
equation
2x+3y = 3 M1
2x+2y = 6 Attempt to solve
y = -3
x = 6, y = -3 A1
03 For both x and y
10. Construction of tangent B1 Construction of
600 at centre
B1
Construction of
tangent to locate
P
PO = 3.8± 0.1 B1
03
Length of PO
3 B1 Simplified form
11. Amplitude = =1.5
2 B1 allow 1 ½
360 For period
=720° B1
Period = 1
2 03 Reject – 650
Phase angle = 650
12. P(AR) or P(BR)
3 4 B1 Correct
(½x )+(½x ) probability
10 10
3 1 3 4 M1 Correct
+ or + probability
20 6 20 24
A1 Summation
19 38 03
or 0.316̇
60 120
1 1 2 M1 Expression for the
x )+45(28) ( x ¿ −120 ( 2 ) ¿+ …
7
13. 210-10(29) (
4 4 A1 1st 4 terms
a) 1024-128x-720x2-240x3+...
1
b) 2- x=1.975
4
X= 0.1
(1.975)10 = 1024-1280(0.1)+720(0.1)2 M1 Substitution for x
240(0.1)3+ … A1 = 0.1
= 903 03 CAO
Page 2 of 9 Mathematics Paper 2 M/Scheme
