Designing a Lintel
Q1: Design a lintel whose width is 9 inches and has a clear span of
6ft. Bearing of the lintel is 9 inches. Take fc’ = 3000 Psi and fy =
40000 Psi. Density of brickwork ℽB = 120 lbs/ft3 and density of concrete
ℽC = 150 lbs/ft3.
Given Data:
b = 9 in
Clear span = l = 6ft
Bearing = br = 9 inches
ℽB = 120 lbs/ft3
ℽC = 150 lbs/ft3
fc’ = 3000 Psi
fy = 40000 Psi
Solution:
According to the thumb rule, the span of the lintel is equal in number
to the depth of the lintel but the unit is reduced i.e., if span is 6ft, then
depth will be 6 inches. So,
Depth = d = 6 inches
NOTE:
[In order to calculate the span for the self load calculation of the
lintel. The span will be taken from the middle point of the bearings. If
the bearing is 9 inches, then the span will be taken from the middle of
these points, so, the span will become 6.75 ft.]
Q1: Design a lintel whose width is 9 inches and has a clear span of
6ft. Bearing of the lintel is 9 inches. Take fc’ = 3000 Psi and fy =
40000 Psi. Density of brickwork ℽB = 120 lbs/ft3 and density of concrete
ℽC = 150 lbs/ft3.
Given Data:
b = 9 in
Clear span = l = 6ft
Bearing = br = 9 inches
ℽB = 120 lbs/ft3
ℽC = 150 lbs/ft3
fc’ = 3000 Psi
fy = 40000 Psi
Solution:
According to the thumb rule, the span of the lintel is equal in number
to the depth of the lintel but the unit is reduced i.e., if span is 6ft, then
depth will be 6 inches. So,
Depth = d = 6 inches
NOTE:
[In order to calculate the span for the self load calculation of the
lintel. The span will be taken from the middle point of the bearings. If
the bearing is 9 inches, then the span will be taken from the middle of
these points, so, the span will become 6.75 ft.]
