FORM1PHYSICSEXAM
MARKINGSCHEME
OPENEREXAMINATIONTERM3,2023
SECTIONA:40MKS
1. Thefollowingarebranchesofphysics.Elaboratewhateachoneofthementails.
a. Thermodynamics(1mk)
Itisthestudyofthetransformationofheattoandfromotherformsofenergy
b. Atomicphysics(1mk)
Itinvolvesthestudyofthebehaviourofparticlesconstitutingthenucleusandtheacc
ompanyingenergychanges
2. Statehow
(a) physicsisrelatedtoRELIGION(1mk)
Systemsintheuniverserevealgreatorderlinesswhichcanbetracedbacktothecreator
(b)PhysicsisrelatedtoHOMESCIENCE(1mk)
Physicsknowledgehasbeenappliedinthedesignandmanufactureofkitchenequipments.
3. DefineaLABORATORY(1mk)
Itisaroomdesignedandequippedfortheconductingofexperimentsandpracticalworkinth
ecourseofthestudyingsciencesubjects.
4. Statethefirstaidmeasuresyouwouldundertakeifanyofthefollowingcalamitiesbefallyou:
(a)Cuts(1mk)
Seekassistancetostopbleedingandforimmediatedressingupofthewound
(b) Eyedamageduetochemicals(1mk)
Washwithalotofwaterthenseektreatment.
5. (a)DefinelengthstatingitsSIunits(2mk)
Lengthisameasureofdistancebetweentwopointsexpressedinmeters
(b)A240cmlongrodwhenstandingperpendiculartothegroundcastitsshadow160cmlong
ontheground.Ifatreecastsitsshadow990cmlongonthegroundatthesametime,determin
etheheightofthetree(3mks)
height of tree lenght of the shadow of thetree
=
height of rod length of the shadow of the rod
h 990 cm
=
240 cm 160 cm
990
H= x240
160
=1485cm
6. Thediameteroftheboreofcapillarytubeis2.0mm.Calculatethecrosssectionareaofthebor
eincm2.(take π=3.142)(3mks)
Crosssectionarea= πr 2
1
, 2 2
3.142 x ( )
= 2
100
3.142 x 1
=
100
=0.0142cm2
7. (a)Definedensityofsubstance. (1mk)
Densityismassperunitvolumeexpressedinkilogrampercubicmeter
(b)Acylindricalglassofmass770gramshasaradiusof7cmandheight20cm.Calculateitsden
sitying/cm3 (3mks)
mass
Density=
volume
770
= 22 x 7 x 7 x 20
7
770
=
22 x 7 x 20
=0.25g/cm3
(c) Themassofadensitybottleis20gwhenemptyand45gwhenfullofwater.Whenfullofmercur
y,itsmassis360g.Determinethedensityofmercury(takedensityofwatertobe1gm/cm 3)
Calculate
i. Massofwater(1mk)
Massofwater=45–20=25g
ii. Volumeofwater(1mks)
25 cm3
=
1 g /cm 3
=25cm3
iii. Volumeofmercury(1mk)
Volumeofmercury=volumeofdensitybottle
=25cm3
iv. Densityofmercury(2mks)
mass of hg
- Densityofmercury=
volume of hg
3400
- =
25
- 13.6g/cm3
8. (a)DefineaforcestatingitsSIunits(2mk)
Itisapushorapull,expressedinnewtons
(d) Aform1studenthasamassof60kg.Determinehisweight(g=10N/kg)(2mks)
Weight=massxgravitationalfieldintensity
2
MARKINGSCHEME
OPENEREXAMINATIONTERM3,2023
SECTIONA:40MKS
1. Thefollowingarebranchesofphysics.Elaboratewhateachoneofthementails.
a. Thermodynamics(1mk)
Itisthestudyofthetransformationofheattoandfromotherformsofenergy
b. Atomicphysics(1mk)
Itinvolvesthestudyofthebehaviourofparticlesconstitutingthenucleusandtheacc
ompanyingenergychanges
2. Statehow
(a) physicsisrelatedtoRELIGION(1mk)
Systemsintheuniverserevealgreatorderlinesswhichcanbetracedbacktothecreator
(b)PhysicsisrelatedtoHOMESCIENCE(1mk)
Physicsknowledgehasbeenappliedinthedesignandmanufactureofkitchenequipments.
3. DefineaLABORATORY(1mk)
Itisaroomdesignedandequippedfortheconductingofexperimentsandpracticalworkinth
ecourseofthestudyingsciencesubjects.
4. Statethefirstaidmeasuresyouwouldundertakeifanyofthefollowingcalamitiesbefallyou:
(a)Cuts(1mk)
Seekassistancetostopbleedingandforimmediatedressingupofthewound
(b) Eyedamageduetochemicals(1mk)
Washwithalotofwaterthenseektreatment.
5. (a)DefinelengthstatingitsSIunits(2mk)
Lengthisameasureofdistancebetweentwopointsexpressedinmeters
(b)A240cmlongrodwhenstandingperpendiculartothegroundcastitsshadow160cmlong
ontheground.Ifatreecastsitsshadow990cmlongonthegroundatthesametime,determin
etheheightofthetree(3mks)
height of tree lenght of the shadow of thetree
=
height of rod length of the shadow of the rod
h 990 cm
=
240 cm 160 cm
990
H= x240
160
=1485cm
6. Thediameteroftheboreofcapillarytubeis2.0mm.Calculatethecrosssectionareaofthebor
eincm2.(take π=3.142)(3mks)
Crosssectionarea= πr 2
1
, 2 2
3.142 x ( )
= 2
100
3.142 x 1
=
100
=0.0142cm2
7. (a)Definedensityofsubstance. (1mk)
Densityismassperunitvolumeexpressedinkilogrampercubicmeter
(b)Acylindricalglassofmass770gramshasaradiusof7cmandheight20cm.Calculateitsden
sitying/cm3 (3mks)
mass
Density=
volume
770
= 22 x 7 x 7 x 20
7
770
=
22 x 7 x 20
=0.25g/cm3
(c) Themassofadensitybottleis20gwhenemptyand45gwhenfullofwater.Whenfullofmercur
y,itsmassis360g.Determinethedensityofmercury(takedensityofwatertobe1gm/cm 3)
Calculate
i. Massofwater(1mk)
Massofwater=45–20=25g
ii. Volumeofwater(1mks)
25 cm3
=
1 g /cm 3
=25cm3
iii. Volumeofmercury(1mk)
Volumeofmercury=volumeofdensitybottle
=25cm3
iv. Densityofmercury(2mks)
mass of hg
- Densityofmercury=
volume of hg
3400
- =
25
- 13.6g/cm3
8. (a)DefineaforcestatingitsSIunits(2mk)
Itisapushorapull,expressedinnewtons
(d) Aform1studenthasamassof60kg.Determinehisweight(g=10N/kg)(2mks)
Weight=massxgravitationalfieldintensity
2
