MLT ASCP BOARD EXAM LATEST 2023-2024 ACTUAL
EXAM 100 QUESTIONS AND CORRECT DETAILED
ANSWERS WITH RATIONALES (VERIFIED ANSWERS)
|ALREADY GRADED A
For which of the following antibodies is the DAT most likely to be negative when testing a
newborn for possible HDFN?
A. anti-A
B. anti-c
C. anti-D
D. anti-K
E. anti-Fya - ANSWER-A;
RATIONALE;The DAT is most likely to be negative in ABO HDFN. It's possible that the
washing done as part of the DAT may break the bonds between anti-A (or anti-B) and the
newborn's poorly developed A (or B) antigens.
General Hospital is considering the addition of a new chemistry panel containing 12 tests. The
laboratory is asked to calculate the total cost of quality control per new chemistry test panel.
Quality control must be performed 3 times per day (every 8 hours). The labor cost per quality
control test for this panel is $2.63. A month's worth of quality control reagent costs $354.00.
What is the total quality control cost per new chemistry test panel if 76,000 of these new panels
are performed each y - ANSWER-B;
This scenario's answer can be calculated by first deciding what the total quality control
labor costs are as well as what the total consumable costs are. In this case, if quality
control is run 3 times per day, a total of 1095 quality control runs are performed each
year. The direct labor cost of $2.63 multiplied by 1095 quality control runs equals
$2879.85 per year in quality control direct labor. The hospital pays $354.00 per month on
quality control consumables, which equals $4248.00 per y
A normal hemoglobin molecule is comprised of the following:
A. Ferrous iron and four globin chains
B. Four heme and four globin chains
C. Four heme and one globin chains
, MLT ASCP BOARD EXAM LATEST 2023-2024 ACTUAL
EXAM 100 QUESTIONS AND CORRECT DETAILED
ANSWERS WITH RATIONALES (VERIFIED ANSWERS)
|ALREADY GRADED A
D. One heme and four globin chains - ANSWER-B;
RATIONALE:A normal hemoglobin molecule consists of a tetramer, of four heme and
four globin chains, with a molecular weight of 64,500 daltons. Each of the four units can
bind a molecule of oxygen for transport to the body's tissues. In the image shown below,
there are four monomers (2 red globin chains and 2 blue globin chains) which form the
entire hemoglobin tetramer structure. The green portions represent the 4 heme groups.
Which of the following immunoglobulin classes is chiefly responsible for the degranulation of
mast cells and basophils:
A. IgG
B. IgA
C. IgM
D. IgE - ANSWER-D;
IgE levels are often increased in patients with allergic disease. IgE binds to the
membranes of mast cells and basophils, and if specific antigen is present to react with
the IgE molecule, degranulation of these cells occurs, releasing histamines, and other
substances into the blood or tissues.
A microscopic examination of a normal urine pH 8.0 shows 2+ yellow-brown thorny spheres
which are MOST probably:
A. ammonium biurate crystals
B. ampicillin crystals
C. amorphous urate crystals
D. crenated red cells
E. waxy casts - ANSWER-A;
Ammonium biurate crystalsare typically round, irregularly spiked and yellow-brown in
color.
Electrophoretic separation of hemoglobin fundamentally relies on:
, MLT ASCP BOARD EXAM LATEST 2023-2024 ACTUAL
EXAM 100 QUESTIONS AND CORRECT DETAILED
ANSWERS WITH RATIONALES (VERIFIED ANSWERS)
|ALREADY GRADED A
A. Size differences of molecules
B. Net charge differences of molecules
C. Concentration differences of molecules
D. Shape variations of molecules - ANSWER-B;
Hemoglobin electrophoresis uses an electric field to separate hemoglobin molecules
based on differences in net electrical charge. The rate of electrophoretic migration is also
dependent on the ionic radius of the molecule, the viscosity of the solution through
which it is migrating, the electrical field strength, temperature, and the type of supporting
medium used.
True/False
For those facilities that in the interest of safety use a special calculation for RhIg dosage,
regardless if they round up or round down, they always add one vial. - ANSWER-True
Regardless of rounding up or down, when calculating RhIg dosage, such facilities always add
one vial. For example:
1.4 = 1 +1 = 2 vials
1.5 = 2 +1 = 3 vials
A sample of cerebrospinal fluid is diluted 1:100; the standard 9 squares of a hemocytometer are
counted on each side for a total of 18 large squares.
Side 1-- 186 nucleated cells counted
Side 2-- 184 nucleated cells counted
total nucleated cells = 370
Using the standard hemocytometer formula shown on the right, what is the nucleated cell count
per microliter (µL)?
, MLT ASCP BOARD EXAM LATEST 2023-2024 ACTUAL
EXAM 100 QUESTIONS AND CORRECT DETAILED
ANSWERS WITH RATIONALES (VERIFIED ANSWERS)
|ALREADY GRADED A
A. 1.03 x 10^4
B. 2.06 x 10^4
C. 4.62 x 10^4
D. 9.25 x 10^4 - ANSWER-B;
Using the formula on the right,
Cells/µL = 370 x x 0.1
Cells/µL = .8
Cells/µL = 20556 or 2.06 x 104
Which of the following are not considered normal flora of the gastrointestinal tract:
A. Lactobacillus
B. Clostridium
C. Peptostreptococcus
D. Shigella - ANSWER-D;
Shigella and Salmonella are not found as normal flora in the gastrointestinal tract.
True/False
The nuclear appendage at the tip of the arrow is a normal finding in females but not in males. -
ANSWER-True
The small drumstick-like nuclear extension (Barr body) marked by the blue arrow is a chromatin
mass which may represent a chromosomal remnant.
These nuclear appendages are found in normal XX females, but would not be present in normal
XY males. If such an appendage is found in a phenotypic male, Klinefelter's syndrome (XXY
male) may be identified clinically. The appendage has a "drumstick" morphology.
EXAM 100 QUESTIONS AND CORRECT DETAILED
ANSWERS WITH RATIONALES (VERIFIED ANSWERS)
|ALREADY GRADED A
For which of the following antibodies is the DAT most likely to be negative when testing a
newborn for possible HDFN?
A. anti-A
B. anti-c
C. anti-D
D. anti-K
E. anti-Fya - ANSWER-A;
RATIONALE;The DAT is most likely to be negative in ABO HDFN. It's possible that the
washing done as part of the DAT may break the bonds between anti-A (or anti-B) and the
newborn's poorly developed A (or B) antigens.
General Hospital is considering the addition of a new chemistry panel containing 12 tests. The
laboratory is asked to calculate the total cost of quality control per new chemistry test panel.
Quality control must be performed 3 times per day (every 8 hours). The labor cost per quality
control test for this panel is $2.63. A month's worth of quality control reagent costs $354.00.
What is the total quality control cost per new chemistry test panel if 76,000 of these new panels
are performed each y - ANSWER-B;
This scenario's answer can be calculated by first deciding what the total quality control
labor costs are as well as what the total consumable costs are. In this case, if quality
control is run 3 times per day, a total of 1095 quality control runs are performed each
year. The direct labor cost of $2.63 multiplied by 1095 quality control runs equals
$2879.85 per year in quality control direct labor. The hospital pays $354.00 per month on
quality control consumables, which equals $4248.00 per y
A normal hemoglobin molecule is comprised of the following:
A. Ferrous iron and four globin chains
B. Four heme and four globin chains
C. Four heme and one globin chains
, MLT ASCP BOARD EXAM LATEST 2023-2024 ACTUAL
EXAM 100 QUESTIONS AND CORRECT DETAILED
ANSWERS WITH RATIONALES (VERIFIED ANSWERS)
|ALREADY GRADED A
D. One heme and four globin chains - ANSWER-B;
RATIONALE:A normal hemoglobin molecule consists of a tetramer, of four heme and
four globin chains, with a molecular weight of 64,500 daltons. Each of the four units can
bind a molecule of oxygen for transport to the body's tissues. In the image shown below,
there are four monomers (2 red globin chains and 2 blue globin chains) which form the
entire hemoglobin tetramer structure. The green portions represent the 4 heme groups.
Which of the following immunoglobulin classes is chiefly responsible for the degranulation of
mast cells and basophils:
A. IgG
B. IgA
C. IgM
D. IgE - ANSWER-D;
IgE levels are often increased in patients with allergic disease. IgE binds to the
membranes of mast cells and basophils, and if specific antigen is present to react with
the IgE molecule, degranulation of these cells occurs, releasing histamines, and other
substances into the blood or tissues.
A microscopic examination of a normal urine pH 8.0 shows 2+ yellow-brown thorny spheres
which are MOST probably:
A. ammonium biurate crystals
B. ampicillin crystals
C. amorphous urate crystals
D. crenated red cells
E. waxy casts - ANSWER-A;
Ammonium biurate crystalsare typically round, irregularly spiked and yellow-brown in
color.
Electrophoretic separation of hemoglobin fundamentally relies on:
, MLT ASCP BOARD EXAM LATEST 2023-2024 ACTUAL
EXAM 100 QUESTIONS AND CORRECT DETAILED
ANSWERS WITH RATIONALES (VERIFIED ANSWERS)
|ALREADY GRADED A
A. Size differences of molecules
B. Net charge differences of molecules
C. Concentration differences of molecules
D. Shape variations of molecules - ANSWER-B;
Hemoglobin electrophoresis uses an electric field to separate hemoglobin molecules
based on differences in net electrical charge. The rate of electrophoretic migration is also
dependent on the ionic radius of the molecule, the viscosity of the solution through
which it is migrating, the electrical field strength, temperature, and the type of supporting
medium used.
True/False
For those facilities that in the interest of safety use a special calculation for RhIg dosage,
regardless if they round up or round down, they always add one vial. - ANSWER-True
Regardless of rounding up or down, when calculating RhIg dosage, such facilities always add
one vial. For example:
1.4 = 1 +1 = 2 vials
1.5 = 2 +1 = 3 vials
A sample of cerebrospinal fluid is diluted 1:100; the standard 9 squares of a hemocytometer are
counted on each side for a total of 18 large squares.
Side 1-- 186 nucleated cells counted
Side 2-- 184 nucleated cells counted
total nucleated cells = 370
Using the standard hemocytometer formula shown on the right, what is the nucleated cell count
per microliter (µL)?
, MLT ASCP BOARD EXAM LATEST 2023-2024 ACTUAL
EXAM 100 QUESTIONS AND CORRECT DETAILED
ANSWERS WITH RATIONALES (VERIFIED ANSWERS)
|ALREADY GRADED A
A. 1.03 x 10^4
B. 2.06 x 10^4
C. 4.62 x 10^4
D. 9.25 x 10^4 - ANSWER-B;
Using the formula on the right,
Cells/µL = 370 x x 0.1
Cells/µL = .8
Cells/µL = 20556 or 2.06 x 104
Which of the following are not considered normal flora of the gastrointestinal tract:
A. Lactobacillus
B. Clostridium
C. Peptostreptococcus
D. Shigella - ANSWER-D;
Shigella and Salmonella are not found as normal flora in the gastrointestinal tract.
True/False
The nuclear appendage at the tip of the arrow is a normal finding in females but not in males. -
ANSWER-True
The small drumstick-like nuclear extension (Barr body) marked by the blue arrow is a chromatin
mass which may represent a chromosomal remnant.
These nuclear appendages are found in normal XX females, but would not be present in normal
XY males. If such an appendage is found in a phenotypic male, Klinefelter's syndrome (XXY
male) may be identified clinically. The appendage has a "drumstick" morphology.
