ADVANCED
CLASS
STATISTICS
Ad Stats: Dist Theory
Name Description Logical Statement
The σ -algebra with the
largest number of members is
Let Ψbe a set and let Bbe a collection of subsets of Ψ.
given by including every
Bis called a σ -algebra. i) ∅ ∈ B, i.e. the empty set is a
Definition of subset of Ψ. B = {A :
member of Bii) If A ∈ B, then Ac ∈ B, i.e. Bis closed
$\sigma-algebra$ A ⊆ Ψ} This is referred to
under complementation iii) If A1 , A2 , ... ∈ B, then
as the power set of Ψ,
∪Ai ∈ B, i.e. Bis closed under countable unions
sometimes written P (Ψ)or
{0, 1} Ψ
Given a measurable space (Ψ, B), a measure on
(Ψ, B)is a function, m, where m : B → ℜ+ i) Measures allow us to express
Definition of
m(A) ≥ 0 for all A ∈ Bii) m(∅) = 0 iii) If the size of sets The size of
measure
A1 , A2 , ... ∈ Bare mutually exclusive then:
the power set is 2 n(Ψ)
m(∪Ai ) = Σm(Ai )
Probability of a union of disjoint events is the sum of the
Boole Inequality individual probabilities. When the events are not disjoint,
then P (∪Ai ) ≤ ΣP (Ai )
The number of possible ordered sequences, of k objects
Permutations selected without replacement from nobjects n Pk =
n!
(n−k)!
The number of unordered sequences, of k objects
also known as the binomial
Combinations selected without replacement from nobjects n Ck =
coefficient
(nk ) = k!(n−k)!
n!
Chain Rule of
P (A1 ∩ A2 ∩ A3 ) = P (A1 ∣A2 ∩ A3 )P (A2 ∩ A3 ) P (∩Aj ) =
0 then:
Conditional
= P (A1 ∣A2 ∩ A3 )P (A2 ∣A3 )P (A3 ) P (∩Aj ) = ΠP (Aj ∣ ∩ Ai )
Probabilities
1. Fx is a non-decreasing function, i.e. if x < ythen
Properties of
Fx (x) ≤ Fx (y)2. limx→−∞ Fx (x) = P (X = x) = FX (x) −
Distribution
0 and limx→∞ Fx (x) = 1 3. Fx is right continuous, i.e. FX (x− )
Functions
Fx (x+ ) = Fx (x)for all x ∈ R
X ∼ Degenerate(a)Concentrates all probability at a
Degenerate 1 f or x=a
single point. p X (x) = { 0 otherwise Distribution function
moment generating function:
, Name Description Logical Statement
random variable, such that, xdenotes the number of
favourable outcomes with a constant probability of
n
success π . X ∼ Bin(n, π)p X (x) = (x)π x (1 −
π)n−x for x ≥ 0 FX (x) = Σxi=0 (ni )π i (1 − π)n−i for
0 ≤ x < n
Consider an experiment of events with only two possible
outcomes. Let X be the random variable, such that, x
denotes the number of events for the first favourable
Geometric moment generating function:
outcome. E.g. Flipping of a coin x = 4 times. There are 3 πe t
Distribution v1 MX (t) = 1−e t (1−π)
(4-1) tails (unfavourable) before getting the first head.
X ∼ Geo1 (π)pX (x) = (1 − π)x−1 π for X ≥ 1
FX (x) = 1 − (1 − π)x for X ≥ 1
Consider an experiment of events with only two possible
outcomes. Let X be the random variable, such that, x
denotes the number of failures before the first favourable
Geometric moment generating function:
outcome. E.g. Getting x = 3 tails on the flip of a coin π
Distribution v2 MX (t) = 1−et (1−π)
∼ Geo0 (π)pX (x) =
before getting the first head. X
(1 − π)x π for X ≥ 0 FX (x) = 1 − (1 − π)x+1 for
X ≥ 0
Extends the Geometric distribution to X number of
independent events until the r number of favourable
Negative outcomes with a constant probability of success π . In
th
moment generating function:
Binomial order to have r favourable outcomes on the X trial, we (πe t ) r
MX (t) =
Distribution v1 must have r − 1 outcomes favourable in the first x − 1 [1−(1−π)e t ]r
x−1
trials. X ∼ N eg. Bin(r, π)p X (x) = ( r−1 )π r (1 −
π) x−r
for X ≥ r
Negative X − N eg. Bin∗ (r, π), where X is the number of
moment generating function:
Binomial failures before the r th successes p X (x) = πr
MX (t) = [1−(1−π)e t ]r
(x+r−1 )π r (1 − π)x for X ≥ 0
Distribution v2 r−1
Newton’s
Binomial Σ(mi )Z i = (Z + 1)m
Theorem
Let X be the random variable, such that, xdenotes the
🌟 Poisson number of rare occurrences of events over a fixed period.
e −λ λx
moment generating function:
t
Distribution X ∼ P ois(λ)pX (x) =
x!
for
x ≥ 0 FX (x) =
MX (t) = eλ(e −1)
−λ i
Σx e i!λ for x ≥ 0
Continuous 1
X ∼ U [a, b]fX (x) = b−a
for a ≤ x ≤ bFX (x) = moment generating function:
Uniform
x−a e bt −e at
for a ≤ x < b MX (t) = (b−a)t
Distribution b−a
X ∼ Exp(λ)fX (x) = λe−λx for x ≥ 0 FX (x) =
Exponential moment generating function:
1 − e−λx for x ≥ 0 https://statproofbook.github.io/P/exp- λ
Distribution MX (t) = λ−t
cdf.html
1
Normal X ∼ N (μ, σ 2 )fX (x) =
2πσ 2
exp[− 2σ1 2 (x
− μ)2 ] moment generating function:
2 2