ALGEBRA PRACTICE QUESTIONS FOR
GRADE 10
Question 1 :
Find the square root of 289x4 −612x3 + 970x2 −684x + 361.
Solution :
Question 2 :
Solve √(y + 1) + √(2y −5) = 3
, Solution :
√(y + 1) + √(2y −5) = 3
√(y + 1) = 3 - √(2y −5)
Taking squares on both sides
[√(y + 1)]2 = [3 - √(2y −5)]2
(y + 1) = 9 - 6√(2y −5) + (2y - 5)
y + 1 - 2y + 5 - 9 = - 6√(2y −5)
- y - 3 = - 6√(2y −5)
[- (y + 3)]2 = [- 6√(2y −5)]2
y2 + 6y + 9 = 36(2y - 5)
y2 + 6y - 72y + 9 + 180 = 0
y2 - 66y + 189 = 0
(y - 63)(y - 3) = 0
y = 63 and y = 3
Question 3 :
A boat takes 1.6 hours longer to go 36 kms up a river than down the river. If
the speed of the water current is 4 km per hr, what is the speed of the
boat in still water?
Solution :
GRADE 10
Question 1 :
Find the square root of 289x4 −612x3 + 970x2 −684x + 361.
Solution :
Question 2 :
Solve √(y + 1) + √(2y −5) = 3
, Solution :
√(y + 1) + √(2y −5) = 3
√(y + 1) = 3 - √(2y −5)
Taking squares on both sides
[√(y + 1)]2 = [3 - √(2y −5)]2
(y + 1) = 9 - 6√(2y −5) + (2y - 5)
y + 1 - 2y + 5 - 9 = - 6√(2y −5)
- y - 3 = - 6√(2y −5)
[- (y + 3)]2 = [- 6√(2y −5)]2
y2 + 6y + 9 = 36(2y - 5)
y2 + 6y - 72y + 9 + 180 = 0
y2 - 66y + 189 = 0
(y - 63)(y - 3) = 0
y = 63 and y = 3
Question 3 :
A boat takes 1.6 hours longer to go 36 kms up a river than down the river. If
the speed of the water current is 4 km per hr, what is the speed of the
boat in still water?
Solution :