PROBLEM SET I
:+ B difference b A B
ii=1t
R
a)draw the vector
+
vectors
=
2i 24 the sum and
3,
n.F
-
a
=
+ k
R
&
- ein an 45:
-
B
5,
&
(1.4i) (2:0 2k) j ((2-5i) (-3.44) is B
b.) and in terms ofunitvectors
it (734-24) -(14.5j) 4 Calculate
- +
+ - -
=
T A B 2.00 6.00 3.009
=(6 5)i (4 4)y (10 12) A 2.008
+ =
- + = + -
+ + +
+
A E -
5.00; +4.00;
88 22k
=
=
4 + +
AE +
[ D
B 5 A B 2.004 6.005-3.004 +
= -
= +
2.005
1,004 8.00
+
= -
Fr
c)Calculate Canal in terms ofpolar coordinates, with angles
a) A 3" 24 and B 44-4j
=
=
-
measured with respectto the positive X axis
A AY
=
AY
+
B Bx
= +
By
2
A.B.20
cost:
8 82.3°
AB
1332 =
4 ( 4)
=
+
3 (- 2)
=
-
+
20 I 25.0
=
+ 14.0 atman" (5)
32
=
O c0s
=
=13 13752
=6.40 at 38.7°
b) A =
-
24 44
+
and B 34
= -
45 2
+
B (-1.0032+18.00attan"
=
(.*88
S
A : -
22 42 +
(b)(-16)
8 cos"
=
2029
=8.04 at (180"82.9°
=
20
8.04
= at 97.2
8 1560
=
B 32= -
42 22 +
29
=
2) A Y-24 = +
2K and B 3 4K
= +
A1 =
-
2
+
22 - ( 6)(8)
-
8 COS=
=
9
925
a) the magnitude and direction ofB AB
= +
+
c
8 81.30 5: (3 1 2)i ( 3 4
5)
=
+
- + - - -
B ( 3) +(4)
=
-
=
29-2j
=
25
B 2
=
+
( 2) -
0 tan"()
=
- ⑧ =tan"(-1)
=2.83m 0 3150
=
b.) the magnitude and direction OF E=-A-B+ C
E( =
-
3 -
1 -
2)4 (3 4 +
+
5)y
+
= -
6i 12] +
E( = -
b) (12)2 +
8: tan"
65m
=
-tan"(-)
=13.42m
=+an"(-2)
0 1170
=
:+ B difference b A B
ii=1t
R
a)draw the vector
+
vectors
=
2i 24 the sum and
3,
n.F
-
a
=
+ k
R
&
- ein an 45:
-
B
5,
&
(1.4i) (2:0 2k) j ((2-5i) (-3.44) is B
b.) and in terms ofunitvectors
it (734-24) -(14.5j) 4 Calculate
- +
+ - -
=
T A B 2.00 6.00 3.009
=(6 5)i (4 4)y (10 12) A 2.008
+ =
- + = + -
+ + +
+
A E -
5.00; +4.00;
88 22k
=
=
4 + +
AE +
[ D
B 5 A B 2.004 6.005-3.004 +
= -
= +
2.005
1,004 8.00
+
= -
Fr
c)Calculate Canal in terms ofpolar coordinates, with angles
a) A 3" 24 and B 44-4j
=
=
-
measured with respectto the positive X axis
A AY
=
AY
+
B Bx
= +
By
2
A.B.20
cost:
8 82.3°
AB
1332 =
4 ( 4)
=
+
3 (- 2)
=
-
+
20 I 25.0
=
+ 14.0 atman" (5)
32
=
O c0s
=
=13 13752
=6.40 at 38.7°
b) A =
-
24 44
+
and B 34
= -
45 2
+
B (-1.0032+18.00attan"
=
(.*88
S
A : -
22 42 +
(b)(-16)
8 cos"
=
2029
=8.04 at (180"82.9°
=
20
8.04
= at 97.2
8 1560
=
B 32= -
42 22 +
29
=
2) A Y-24 = +
2K and B 3 4K
= +
A1 =
-
2
+
22 - ( 6)(8)
-
8 COS=
=
9
925
a) the magnitude and direction ofB AB
= +
+
c
8 81.30 5: (3 1 2)i ( 3 4
5)
=
+
- + - - -
B ( 3) +(4)
=
-
=
29-2j
=
25
B 2
=
+
( 2) -
0 tan"()
=
- ⑧ =tan"(-1)
=2.83m 0 3150
=
b.) the magnitude and direction OF E=-A-B+ C
E( =
-
3 -
1 -
2)4 (3 4 +
+
5)y
+
= -
6i 12] +
E( = -
b) (12)2 +
8: tan"
65m
=
-tan"(-)
=13.42m
=+an"(-2)
0 1170
=
