In this guide, we will discuss the process of solving
quadratic equations using the quadratics formula. Let's
take the example equation:
2x 2 + 3x - 2 = 0
Our goal is to determine the value of x that would make
this equation true. To apply the formula, we must first
determine the coefficients in the equation:
a=2
b=3
c = -2
We can now plug these values into the quadratic
formula:
x = (-b ± √(b 2 - 4ac)) / 2a
With our values plugged in, we can simplify:
x = (-3 ± √(3 2 - 4(2)(-2))) / 2(2)
x = (-3 ± √(9 + 16)) / 4
x = (-3 ± √25) / 4
We can further simplify:
x = (-3 + 5) / 4 = 1/2
x = (-3 - 5) / 4 = -4/2 = -2
Therefore, the solutions for the equation 2x 2 + 3x - 2 =
0 are:
x = 1/2, -2
quadratic equations using the quadratics formula. Let's
take the example equation:
2x 2 + 3x - 2 = 0
Our goal is to determine the value of x that would make
this equation true. To apply the formula, we must first
determine the coefficients in the equation:
a=2
b=3
c = -2
We can now plug these values into the quadratic
formula:
x = (-b ± √(b 2 - 4ac)) / 2a
With our values plugged in, we can simplify:
x = (-3 ± √(3 2 - 4(2)(-2))) / 2(2)
x = (-3 ± √(9 + 16)) / 4
x = (-3 ± √25) / 4
We can further simplify:
x = (-3 + 5) / 4 = 1/2
x = (-3 - 5) / 4 = -4/2 = -2
Therefore, the solutions for the equation 2x 2 + 3x - 2 =
0 are:
x = 1/2, -2
