Summary Solution manual for Algebra and Trigonometry Enhanced with Graphing Utilities 7th edition by Michael Sullivan

Solution manual for Algebra and
Trigonometry Enhanced with Graphing
Utilities 7th edition by Michael Sullivan

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Full download please contact or qidiantiku.com




Full download please contact or qidiantiku.com




Full download please contact or qidiantiku.com




Full download please contact or qidiantiku.com




Full download please contact or qidiantiku.com

, Chapter 1
Graphs, Equations, and Inequalities
Section 1.1 (f) Quadrant IV

1. 0

2. 5 − ( −3) = 8 = 8

3. 32 + 42 = 25 = 5

4. 112 + 602 = 121 + 3600 = 3721 = 612
Since the sum of the squares of two of the sides
of the triangle equals the square of the third side,
the triangle is a right triangle.

1 16. (a) Quadrant I
5. bh
2 (b) Quadrant III
(c) Quadrant II
6. True (d) Quadrant I
7. x-coordinate; y-coordinate (e) y-axis
(f) x-axis
8. quadrants
9. midpoint
10. False; the distance between two points is never
negative.
11. False; points that lie in Quadrant IV will have a
positive x-coordinate and a negative y-coordinate.
The point ( −1, 4 ) lies in Quadrant II.

 x + x y + y2 
12. True; M =  1 2 , 1 17. The points will be on a vertical line that is two
 2 2  units to the right of the y-axis.
13. d
14. c
15. (a) Quadrant II
(b) x-axis
(c) Quadrant III
(d) Quadrant I
(e) y-axis




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, Section 1.1: The Distance and Midpoint Formulas; Graphing Utilities; Introduction to Graphing Equations


18. The points will be on a horizontal line that is 26. X min = −90
three units above the x-axis. X max = 30
X scl = 10
Y min = −50
Y max = 70
Y scl = 10

27. X min = −10
X max = 110
X scl = 10
Y min = −10
Y max = 160
Y scl = 10
19. ( −1, 4 ) ; Quadrant II 28. X min = −20
20. (3, 4); Quadrant I X max = 110
X scl = 10
21. (3, 1); Quadrant I
Y min = −10
22. ( −6, −4 ) ; Quadrant III Y max = 60
Y scl = 10
23. X min = −11
29. X min = −6
X max = 5
X max = 6
X scl = 1
X scl = 2
Y min = −3
Y min = −4
Y max = 6
Y max = 4
Y scl = 1
Y scl = 2
24. X min = −3
30. X min = −3
X max = 7
X max = 3
X scl = 1
X scl = 1
Y min = −4
Y min = −2
Y max = 9
Y max = 2
Y scl = 1
Y scl = 1
25. X min = −30
X max = 50 31. X min = −6
X scl = 10 X max = 6
Y min = −90 X scl = 2
Y max = 50 Y min = −1
Y scl = 10 Y max = 3
Y scl = 1




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, Chapter 1: Graphs, Equations, and Inequalities


32. X min = −9
42. d ( P1 , P2 ) = (10 − 2 )2 + ( 3 − (−3) )2 = 82 + 6 2
X max = 9
X scl = 3 = 64 + 36 = 100 = 10
Y min = −12 2
43. d ( P1 , P2 ) = (6 − 4) 2 + ( 4 − (−3) ) = 22 + 7 2
Y max = 4
Y scl = 4 = 4 + 49 = 53

33. X min = 3 44. d ( P1 , P2 ) = ( 6 − (− 4) )2 + ( 2 − (−3) )2
X max = 9
X scl = 1 = 102 + 52 = 100 + 25
Y min = 2 = 125 = 5 5
Y max = 10
Y scl = 2 45. d ( P1 , P2 ) = (0 − a ) 2 + (0 − b) 2 = a 2 + b 2

34. X min = −22 46. d ( P1 , P2 ) = (0 − a) 2 + (0 − a ) 2 = a 2 + a 2
X max = −10
= 2a 2 = 2 a
X scl = 2
Y min = 4 47. P1 = (1,3) ; P2 = ( 5,15 )
Y max = 8
Y scl = 1
d ( P1 , P2 ) = ( 5 − 1)2 + (15 − 3)2

2 2
= ( 4 )2 + (12 )2
35. d ( P1 , P2 ) = (2 − 0) + (1 − 0) = 4 + 1 = 5
= 16 + 144
36. d ( P1 , P2 ) = (− 2 − 0)2 + (1 − 0) 2 = 4 + 1 = 5 = 160 = 4 10

48. P1 = ( −8, −4 ) ; P2 = ( 2,3)
37. d ( P1 , P2 ) = (− 2 − 1) 2 + (2 − 1) 2 = 9 + 1 = 10
( 2 − ( −8) ) + ( 3 − ( −4 ) )
2 2
d ( P1 , P2 ) =
38. d ( P1 , P2 ) = ( 2 − (−1) )2 + (2 − 1)2 = (10 )2 + ( 7 )2
= 9 + 1 = 10
= 100 + 49
= 149
39. d ( P1 , P2 ) = (5 − 3) 2 + ( 4 − ( −4 ) ) = 22 + ( 8 )
2 2


= 4 + 64 = 68 = 2 17 49. P1 = ( −4, 6 ) ; P2 = ( 4, −8 )

( 4 − ( −4 ) ) + ( −8 − 6 )2
2
d ( P1 , P2 ) =
( 2 − ( −1) ) + ( 4 − 0 )
2 2 2
40. d ( P1 , P2 ) = = ( 3) +4 2


= 9 + 16 = 25 = 5
= (8 )2 + ( −14 )2
= 64 + 196
2
41. d ( P1 , P2 ) = (11 − (−5) ) + (9 − ( −3)) 2
= 260 = 2 65
2 2
= 16 + 12 = 256 + 144
= 400 = 20




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