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Numerical Computing Class Notes

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This course is about numerical analysis. The associated computations are done using Matlab. • Numerical analysis is concerned with the solution of mathematically formulated problems via computer. • It is what you do when you can’t solve a mathematically formulated problem with pencil and paper alone. • Numerical computing is being done all around us. (“We all use math everyday.”) • The problems themselves can come from many fields of application, e.g., biology, chemistry, physics, engineering, medicine, education, entertainment, the internet, forensics, financial markets, . . . • The stakes are often high, so the results must be accurate, reliable, and robust

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Numerical Computing
(Numerical differentiation and solution of ODE )

Dr. L. Govindarao




Department of Mathematics
Amrita Vishwa Vidyapeetham, Coimbatore, India

,Outline

1 Numerical differentiation
2 Numerical solution of ODE
3 Initial value problems
1 Single step methods
Euler method
Trapezoidal method
Implicit Euler method
Midpoint method
Runge-Kutta methods
2 Multi step methods
Adams-Bashforth methods (Predictor)
Adams-Moulton methods (Corrector)
Predictor-Corrector methods
4 Boundary value problems
1 Finite difference method
2 Shooting method

,Numerical Differentiation

Let f (x) be a continuous function defined on [a, b]. The
Numerical differentiation is a numerical process to find the
numerical values of the derivative of the given function f (x)
at a given point xi = ih, i = 0, 1, · · · , n, where h is the step
length and x0 = a, xn = b.

Finite difference approximation:
f (xi+1 ) − f (xi )
Forward Difference: f 0 (xi ) = + O(h).
h
f (xi ) − f (xi−1 )
Backward Difference: f 0 (xi ) = + O(h).
h
f (xi+1 ) − f (xi−1 )
Centered Difference: f 0 (xi ) = + O(h2 ).
2h

, Examples

Example
Find the derivative of the following function at t = 0.5 by using
forward difference, backward difference and centered difference
scheme, taking the step length h = 0.5 and compare the results
with the exact derivatives.

f (t) = −0.1t 4 − 0.15t 3 − 0.5t 2 − 0.25t + 1.2.


Solution:
Exact value: f 0 (0.5) = −0.9125
f (1) − f (0.5)
Forward Difference: f 0 (0.5) ≈ = −1.45, EA = 0.5375
0.5
f (0.5) − f (0)
Backward Difference: f 0 (0.5) ≈ = −0.55, EA = 0.3625
0.5
f (1) − f (0)
Centered Difference: f 0 (0.5) ≈ = −1.0, EA = 0.0875
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Number of pages
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Written in
2023/2024
Type
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