Edexcel A Level Physics Paper 1 June
2024 Exam Questions and Answers
100% Pass
Newton's Third Law - Answer>>If object A exerts a force on
object B, then object B exerts an equal but opposite force on
object A
Newton's Third Law pairs - Answer>>Example: An object exerts
a weight of 50N onto the earth. The third law pair would be that
the earth would exert a NCF of 50N on the object
Conditions for Newton's Third Law Pairs to be true - Answer>>-
Two Different Forces
- Act on the same line
- Same magnitude
- Different objects
- same time
Potential Dividers - Answer>>A circuit that is used to only
output part of the voltage provided
Potential Divider equation - Answer>>Vout/Vin = R1/R1+R2
Potential Dividers and thermistors - Answer>>If a thermistor is
used as R1, as temperature decreases resistance increases and
thus Vout increases as they are proportional, this can be used as
a heating system to turn it on if it gets cold enough
Potential Dividers and LDRs - Answer>>If a LDR is used as R1,
as light decreases resistance increases and thus Vout increases
as they are proportional, this can be used for street lights to be
turned on as light decreases
,Thermistor - Answer>>a resistor whose resistance depends on
the temperature of the thermistor
As temperature decreases resistance increases
LDR - Answer>>Light dependent resistor
As light increases resistance decreases
Rheostat - Answer>>When a variable resistor is used to control
current
Variable Resistor - Answer>>A resistor whose value can be
varied between its minimum and maximum values.
Variable Resistors and Potential Divider Uses - Answer>>A
variable resistor can act as a potential divider to act as a
continuous slider to increases or decrease Vout. This can be used
as a dimmer switch
Magnetic Flux Density - Answer>>a measure of the strength of
the magnetic field.
How densely packed lines of flux are equates to how strong a
field is
Measures in Tesla T
Magnetic Flux - Answer>>The total number magnetic field lines
that pass through a surface
= magnetic flux density x Area
,Magnetic Flux Linkage - Answer>>The product of the magnetic
flux and the number of turns in a given coil.
= Number of coils x magnetic flux
Equations of motion - Answer>>v = u + at
s = 1/2(v+u)t
s = ut + 1/2at^2
v^2 = u^2 + 2as
Equation of motion for velocity - Answer>>v = u + at
Equation of motion for distance - Answer>>s = 1/2(v+u)t
s = ut + 1/2at^2
Equation of motion for velocity squared - Answer>>v^2 = u^2 +
2as
Equation for an magnetic field on a wire - Answer>>F = BIL
F = Force
B = Magnetic field strength (density)
I = Current
L = length
Equation for a magnetic field on a wire not at 90 degrees to the
field - Answer>>F = BILsin(angle)
F = Force
B = Magnetic field strength (density)
I = Current
L = length
, Angle at 90 degrees should just use F = BIL as sin90 = 1
therefore cos component will not affect the force
Angle at 0 degrees will be 0 as sin0 = 0
Equation for a magnetic field on a moving charge - Answer>>F
= BQV
F = Force
B = Magnetic field strength (density)
Q = charge
V = velocity
Equation for a magnetic field of a moving charge not at 90
degrees to the field - Answer>>F = BQVsin(angle)
F = Force
B = Magnetic field strength (density)
Q = charge
V = velocity
Angle at 90 degrees should just use F = BIL as sin90 = 1
therefore cos component will not affect the force
Angle at 0 degrees will be 0 as sin0 = 0
Fleming's Left Hand Rule - Answer>>First Finger Field
seCond finger Current
thuMb Motion
Relativistic Effects - Answer>>Only when objects approach the
speed of light do our observations begin to depart measurably
from the predictions of Newtonian Physics
2024 Exam Questions and Answers
100% Pass
Newton's Third Law - Answer>>If object A exerts a force on
object B, then object B exerts an equal but opposite force on
object A
Newton's Third Law pairs - Answer>>Example: An object exerts
a weight of 50N onto the earth. The third law pair would be that
the earth would exert a NCF of 50N on the object
Conditions for Newton's Third Law Pairs to be true - Answer>>-
Two Different Forces
- Act on the same line
- Same magnitude
- Different objects
- same time
Potential Dividers - Answer>>A circuit that is used to only
output part of the voltage provided
Potential Divider equation - Answer>>Vout/Vin = R1/R1+R2
Potential Dividers and thermistors - Answer>>If a thermistor is
used as R1, as temperature decreases resistance increases and
thus Vout increases as they are proportional, this can be used as
a heating system to turn it on if it gets cold enough
Potential Dividers and LDRs - Answer>>If a LDR is used as R1,
as light decreases resistance increases and thus Vout increases
as they are proportional, this can be used for street lights to be
turned on as light decreases
,Thermistor - Answer>>a resistor whose resistance depends on
the temperature of the thermistor
As temperature decreases resistance increases
LDR - Answer>>Light dependent resistor
As light increases resistance decreases
Rheostat - Answer>>When a variable resistor is used to control
current
Variable Resistor - Answer>>A resistor whose value can be
varied between its minimum and maximum values.
Variable Resistors and Potential Divider Uses - Answer>>A
variable resistor can act as a potential divider to act as a
continuous slider to increases or decrease Vout. This can be used
as a dimmer switch
Magnetic Flux Density - Answer>>a measure of the strength of
the magnetic field.
How densely packed lines of flux are equates to how strong a
field is
Measures in Tesla T
Magnetic Flux - Answer>>The total number magnetic field lines
that pass through a surface
= magnetic flux density x Area
,Magnetic Flux Linkage - Answer>>The product of the magnetic
flux and the number of turns in a given coil.
= Number of coils x magnetic flux
Equations of motion - Answer>>v = u + at
s = 1/2(v+u)t
s = ut + 1/2at^2
v^2 = u^2 + 2as
Equation of motion for velocity - Answer>>v = u + at
Equation of motion for distance - Answer>>s = 1/2(v+u)t
s = ut + 1/2at^2
Equation of motion for velocity squared - Answer>>v^2 = u^2 +
2as
Equation for an magnetic field on a wire - Answer>>F = BIL
F = Force
B = Magnetic field strength (density)
I = Current
L = length
Equation for a magnetic field on a wire not at 90 degrees to the
field - Answer>>F = BILsin(angle)
F = Force
B = Magnetic field strength (density)
I = Current
L = length
, Angle at 90 degrees should just use F = BIL as sin90 = 1
therefore cos component will not affect the force
Angle at 0 degrees will be 0 as sin0 = 0
Equation for a magnetic field on a moving charge - Answer>>F
= BQV
F = Force
B = Magnetic field strength (density)
Q = charge
V = velocity
Equation for a magnetic field of a moving charge not at 90
degrees to the field - Answer>>F = BQVsin(angle)
F = Force
B = Magnetic field strength (density)
Q = charge
V = velocity
Angle at 90 degrees should just use F = BIL as sin90 = 1
therefore cos component will not affect the force
Angle at 0 degrees will be 0 as sin0 = 0
Fleming's Left Hand Rule - Answer>>First Finger Field
seCond finger Current
thuMb Motion
Relativistic Effects - Answer>>Only when objects approach the
speed of light do our observations begin to depart measurably
from the predictions of Newtonian Physics
