Edexcel A-Level Mathematics
Exam Questions and Answers
2024 Review 100% Pass
tanθ
sinθ / cosθ
cotθ
cosθ / sinθ
1
sin²θ + cos²θ
sec²θ
1 + tan²θ
cosec²θ
1 + cot²θ
sin(A + B)
sinAcosB + cosAsinB
sin(A - B)
sinAcosB + cosAsinB
cos(A + B)
cosAcosB - sinAsinB
cos(A - B)
cosAcosB + sinAsinB
tan(A + B)
(tanA + tanB) / (1 - tanAtanB)
tan(A - B)
(tanA - tanB) / (1 + tanAtanB)
cos2θ
, cos²θ-sin²θ ; 2cos²θ - 1 ; 1 - 2sin²θ
sin2θ
2sinθcosθ
tan2θ
2tanθ/(1-tan²θ)
sinθ (small angle)
θ
cosθ (small angle)
1 - [θ² / 2]
tanθ (small angle)
θ
f'(x) (first principles)
limit as h tends to 0 of [f(x + h) - f(x)] / h
Chain rule
dy/dx = dy/du * du/dx
d[e^x]/dx
e^x
d[e^f(x)]/dx
f'(x) * e^f(x)
d[e^(kx)]/dx
k * e^(kx)
d[a^x]/dx
a^x * lna
d[a^(kx)]/dx
k * a^(kx) * lna
d[lnx]/dx
1/x
d[ln(kx)]/dx
1/x
d[lnf(x)]/dx
Exam Questions and Answers
2024 Review 100% Pass
tanθ
sinθ / cosθ
cotθ
cosθ / sinθ
1
sin²θ + cos²θ
sec²θ
1 + tan²θ
cosec²θ
1 + cot²θ
sin(A + B)
sinAcosB + cosAsinB
sin(A - B)
sinAcosB + cosAsinB
cos(A + B)
cosAcosB - sinAsinB
cos(A - B)
cosAcosB + sinAsinB
tan(A + B)
(tanA + tanB) / (1 - tanAtanB)
tan(A - B)
(tanA - tanB) / (1 + tanAtanB)
cos2θ
, cos²θ-sin²θ ; 2cos²θ - 1 ; 1 - 2sin²θ
sin2θ
2sinθcosθ
tan2θ
2tanθ/(1-tan²θ)
sinθ (small angle)
θ
cosθ (small angle)
1 - [θ² / 2]
tanθ (small angle)
θ
f'(x) (first principles)
limit as h tends to 0 of [f(x + h) - f(x)] / h
Chain rule
dy/dx = dy/du * du/dx
d[e^x]/dx
e^x
d[e^f(x)]/dx
f'(x) * e^f(x)
d[e^(kx)]/dx
k * e^(kx)
d[a^x]/dx
a^x * lna
d[a^(kx)]/dx
k * a^(kx) * lna
d[lnx]/dx
1/x
d[ln(kx)]/dx
1/x
d[lnf(x)]/dx
