Mechanical technology Specialist Board Assessment Practice Test
LICEO DE CAGAYAN UNIVERSITY
1. Kinematics and Elements
Q1: Think about a mechanical arm with three levels of opportunity. The joint points are θ1, θ2, and θ3.
Assuming the change lattice from the base casing to the end-effector outline is given by:
0 and - 1 and 0 and 0.5 \\
0 and 0 and - 1 and 0.3 \\
1 and 0 and 0 and 1.0 \\
0 and 0 and 0 and 1
\end{bmatrix} \]
Decide the place of the end-effector in the base casing.
**Answer:** The place of the end-effector can be removed from the last segment of the change lattice,
which is \([0.5, 0.3, 1.0]\). Consequently, the place of the end-effector in the base casing is \((0.5, 0.3,
1.0)\) meters.
#### **2. Control Systems**
**Q2:** Provided a second-request direct time-invariant (LTI) framework with the exchange capability:
\[ H(s) = \frac{5}{s^2 + 3s + 5} \]
Decide the normal recurrence (ω_n) and the damping proportion (ζ) of the framework.
**Answer:**
The exchange capability is in the structure:
\[ H(s) = \frac{\omega_n^2}{s^2 + 2\zeta\omega_n s + \omega_n^2} \]
Contrasting coefficients and \( \frac{5}{s^2 + 3s + 5} \), we have:
- \( \omega_n^2 = 5 \) → \( \omega_n = \sqrt{5} \approx 2.236 \)
- \( 2\zeta\omega_n = 3 \) → \( \zeta = \frac{3}{2\omega_n} = \frac{3}{2 \times \sqrt{5}} \approx 0.671 \)
In this way, \( \omega_n \approx 2.236 \) and \( \zeta \approx 0.671 \).
#### **3. Sensors and Actuators**
**Q3:** A robot is outfitted with a closeness sensor that has a recognition scope of 0.1 meters. On the
off chance that the sensor yields a sign that is directly corresponding to the distance estimated, and the
LICEO DE CAGAYAN UNIVERSITY
1. Kinematics and Elements
Q1: Think about a mechanical arm with three levels of opportunity. The joint points are θ1, θ2, and θ3.
Assuming the change lattice from the base casing to the end-effector outline is given by:
0 and - 1 and 0 and 0.5 \\
0 and 0 and - 1 and 0.3 \\
1 and 0 and 0 and 1.0 \\
0 and 0 and 0 and 1
\end{bmatrix} \]
Decide the place of the end-effector in the base casing.
**Answer:** The place of the end-effector can be removed from the last segment of the change lattice,
which is \([0.5, 0.3, 1.0]\). Consequently, the place of the end-effector in the base casing is \((0.5, 0.3,
1.0)\) meters.
#### **2. Control Systems**
**Q2:** Provided a second-request direct time-invariant (LTI) framework with the exchange capability:
\[ H(s) = \frac{5}{s^2 + 3s + 5} \]
Decide the normal recurrence (ω_n) and the damping proportion (ζ) of the framework.
**Answer:**
The exchange capability is in the structure:
\[ H(s) = \frac{\omega_n^2}{s^2 + 2\zeta\omega_n s + \omega_n^2} \]
Contrasting coefficients and \( \frac{5}{s^2 + 3s + 5} \), we have:
- \( \omega_n^2 = 5 \) → \( \omega_n = \sqrt{5} \approx 2.236 \)
- \( 2\zeta\omega_n = 3 \) → \( \zeta = \frac{3}{2\omega_n} = \frac{3}{2 \times \sqrt{5}} \approx 0.671 \)
In this way, \( \omega_n \approx 2.236 \) and \( \zeta \approx 0.671 \).
#### **3. Sensors and Actuators**
**Q3:** A robot is outfitted with a closeness sensor that has a recognition scope of 0.1 meters. On the
off chance that the sensor yields a sign that is directly corresponding to the distance estimated, and the
