Std. X Unit test - 1
Duration : 1hr MATHEMATICS II Marks : 20
CHAPTERS - 1 and 2
Q.1. (A) Choose the correct alternative : 4
1. ABC and DEF are equilateral triangles. If A(ABC) : A(DEF) = 1 : 2.
D
If AB = 4, then what is length of DE ?
(i) 2 2 (ii) 4 A
(iii) 8 (iv) 4 2
B C E F
2. In ABC and PQR, in a one to one correspondence
AB BC CA
If = = then A Q
QR PR PQ
(i) PQR ~ ABC
(ii) PQR ~ CAB
B R P
(iii) CBA ~ PQR C
(iv) BCA ~ PQR
3. Altitude on the hypotenuse of a right angled triangle divides it in two parts of
lengths 4 cm and 9 cm. Find the length of the altitude.
(i) 9 cm (ii) 4 cm
(iii) 6 cm (iv) 2 6
4. Out of the dates given below which date constitutes a Pythagorean triplet ?
(i) 15/08/17 (ii) 16/08/16
(iii) 3/5/17 (iv) 4/9/15
Q.1. (B) Solve the following : (Any 2) 4
1. In RST, S = 90º, T = 30º, RT = 12 cm, then find RS and ST.
2. Ratio of areas of two triangles with equal heights is 2 : 3. If base of the smaller
triangle is 6 cm, then what is the corresponding base of the bigger triangle ?
3. LMN ~ PQR, 9 × A(PQR) = 16 × A(LMN). If QR = 20, then find MN.
Duration : 1hr MATHEMATICS II Marks : 20
CHAPTERS - 1 and 2
Q.1. (A) Choose the correct alternative : 4
1. ABC and DEF are equilateral triangles. If A(ABC) : A(DEF) = 1 : 2.
D
If AB = 4, then what is length of DE ?
(i) 2 2 (ii) 4 A
(iii) 8 (iv) 4 2
B C E F
2. In ABC and PQR, in a one to one correspondence
AB BC CA
If = = then A Q
QR PR PQ
(i) PQR ~ ABC
(ii) PQR ~ CAB
B R P
(iii) CBA ~ PQR C
(iv) BCA ~ PQR
3. Altitude on the hypotenuse of a right angled triangle divides it in two parts of
lengths 4 cm and 9 cm. Find the length of the altitude.
(i) 9 cm (ii) 4 cm
(iii) 6 cm (iv) 2 6
4. Out of the dates given below which date constitutes a Pythagorean triplet ?
(i) 15/08/17 (ii) 16/08/16
(iii) 3/5/17 (iv) 4/9/15
Q.1. (B) Solve the following : (Any 2) 4
1. In RST, S = 90º, T = 30º, RT = 12 cm, then find RS and ST.
2. Ratio of areas of two triangles with equal heights is 2 : 3. If base of the smaller
triangle is 6 cm, then what is the corresponding base of the bigger triangle ?
3. LMN ~ PQR, 9 × A(PQR) = 16 × A(LMN). If QR = 20, then find MN.