DMI + AMA PRO CERTIFICATION EXAM 2024 ACTUAL
EXAM COMPLETE 150 QUESTIONS WITH DETAILED
VERIFIED ANSWERS (100% CORRECT ANSWERS) /
ALREADY GRADED A+
in order to demonstrate the greater tubercle of the humerus on an AP projection of
the shoulder, the epicondyles must be:
a. in a neutral postion
b. at a 45 degree angle with the plane of the IR
c. parallel with the plane of the IR
d. perpendicular with the plane of the IR - ANSWER: parallel with the plane of the IR
for an AP projection of the shoulder, the central ray should be directed
15 degrees
30 degrees
15 to 30 degrees
perpendicular to the IR - ANSWER: perpendicular to the IR
for an AP projection of the shoulder, the central ray should enter
1 inch inferior to the coracoid processs
1 inch inferior to the acromion
2 inches inferior to the coracoid process
2 inches inferior to the acromion - ANSWER: 1 inch inferior to the coracoid process
which of the following is prominently shown "in profile" on an AP projection of the
shoulder with the humerus in external rotation?
lesser tubercle
greater tubercle
scapulohumeral joint
acromioclavicular joint - ANSWER: greater tubercle
if the patient places the palm of the hand against the thigh, the humerus will be in
lateral position
external rotation
internal rotation
neutral position - ANSWER: neutral position
when the arm cannot be rotated or abducted due to injury, which of the following
methods can be used to perform a lateral projection of the shoulder
settegast
holmblad
lawrence
pearson - ANSWER: lawrence
, where should the center of the IR be positioned for a lateral projection of the
shoulder?
acromion process
anatomical neck
surgical neck
greater tubercle - ANSWER: surgical neck
for the PA oblique projection (scapular y)of the shoulder, the body is rotated so that
the midcoronal plane is how many degrees from the IR - ANSWER: 45 to 60 degrees
which of the following will be directl superimposed over the junction of the "y" on
the PA oblique (scapular y) projection?
humerus
humeral head
coracoid process
acromion process - ANSWER: humeral head
the pearson method is an AP projection of the
shoulder joint
proximal humerus
scapulohumeral joint
acromioclavicular articulation - ANSWER: acromioclavicular articulation
how many pounds of weight should be affixed to each wrist for the AP projection of
the AC joint?
2lb
3lb
2 to 4lb
5 to 10 - ANSWER: 5 to 10 lb
how should the central ray be angeld for the AP projection (pearson method) of the
AC joints
0 degrees perpendicular to the IR
5 degrees cephalad to the IR
7 degrees cephalad to the IR
5-7 degrees cephalad IR - ANSWER: 0 degrees perpendicular to the IR
the central ray angle of angle for an AP axial projection of the clavicle when
performed on a patient in the supine position is - ANSWER: 15 degrees
how is the arm poistioned for an ap scapula?
abducted 90 degrees forarm flexed
EXAM COMPLETE 150 QUESTIONS WITH DETAILED
VERIFIED ANSWERS (100% CORRECT ANSWERS) /
ALREADY GRADED A+
in order to demonstrate the greater tubercle of the humerus on an AP projection of
the shoulder, the epicondyles must be:
a. in a neutral postion
b. at a 45 degree angle with the plane of the IR
c. parallel with the plane of the IR
d. perpendicular with the plane of the IR - ANSWER: parallel with the plane of the IR
for an AP projection of the shoulder, the central ray should be directed
15 degrees
30 degrees
15 to 30 degrees
perpendicular to the IR - ANSWER: perpendicular to the IR
for an AP projection of the shoulder, the central ray should enter
1 inch inferior to the coracoid processs
1 inch inferior to the acromion
2 inches inferior to the coracoid process
2 inches inferior to the acromion - ANSWER: 1 inch inferior to the coracoid process
which of the following is prominently shown "in profile" on an AP projection of the
shoulder with the humerus in external rotation?
lesser tubercle
greater tubercle
scapulohumeral joint
acromioclavicular joint - ANSWER: greater tubercle
if the patient places the palm of the hand against the thigh, the humerus will be in
lateral position
external rotation
internal rotation
neutral position - ANSWER: neutral position
when the arm cannot be rotated or abducted due to injury, which of the following
methods can be used to perform a lateral projection of the shoulder
settegast
holmblad
lawrence
pearson - ANSWER: lawrence
, where should the center of the IR be positioned for a lateral projection of the
shoulder?
acromion process
anatomical neck
surgical neck
greater tubercle - ANSWER: surgical neck
for the PA oblique projection (scapular y)of the shoulder, the body is rotated so that
the midcoronal plane is how many degrees from the IR - ANSWER: 45 to 60 degrees
which of the following will be directl superimposed over the junction of the "y" on
the PA oblique (scapular y) projection?
humerus
humeral head
coracoid process
acromion process - ANSWER: humeral head
the pearson method is an AP projection of the
shoulder joint
proximal humerus
scapulohumeral joint
acromioclavicular articulation - ANSWER: acromioclavicular articulation
how many pounds of weight should be affixed to each wrist for the AP projection of
the AC joint?
2lb
3lb
2 to 4lb
5 to 10 - ANSWER: 5 to 10 lb
how should the central ray be angeld for the AP projection (pearson method) of the
AC joints
0 degrees perpendicular to the IR
5 degrees cephalad to the IR
7 degrees cephalad to the IR
5-7 degrees cephalad IR - ANSWER: 0 degrees perpendicular to the IR
the central ray angle of angle for an AP axial projection of the clavicle when
performed on a patient in the supine position is - ANSWER: 15 degrees
how is the arm poistioned for an ap scapula?
abducted 90 degrees forarm flexed
