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AQA-7356-2-MATHEMATICS FINAL MARK SCHEME PAPER 2-AS LEVEL-Jun24-v1.0

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AQA-7356-2-MATHEMATICS FINAL MARK SCHEME PAPER 2-AS LEVEL-Jun24-v1.0. Q Marking instructions AO Marks Typical solution 1 Circles third answer 1.1b B1 4 5 Question 1 Total 1 Q Marking instructions AO Marks Typical solution 2 Ticks third box 1.2 B1 cos2x = 1 – sin2x Question 2 Total 1 Q Marking instructions AO Marks Typical solution 3 Uses power law for logarithms at least once 1.1a M1 loga x 3 = loga 72 – loga 32 loga x 3 = loga 72 9 = loga 8 x 3 = 8 x = 2 Uses subtraction law for logarithms OE PI by loga 8 OE Condone log 72 log 9 a a if recovered to loga 8 Condone omission of the base a 1.1a M1 Obtains loga 8 on right-hand side of equation OE Or loga 9x 3 on left-hand side Condone omission of the base a 1.1b A1 Obtains x = 2 CAO 1.1b A1 Question 3 Total 4 Q Marking instructions AO Marks Typical solution 4(a) Obtains y = 8sinx + 4 OE 1.1b B1 y = 8sinx + 4 Subtotal 1 Q Marking instructions AO Marks Typical solution 4(b) Obtains y = 32sinx OE 1.1b B1 y = 32sinx Subtotal 1 Q Marking instructions AO Marks Typical solution 4(c) Obtains y = 8sin x 2 OE 1.1b B1 y = 8sin x 2 Subtotal 1 Question 4 Total 3 000006 Page 6 of 17 MATHEMATICS MARK SCHEME – AS MATHEMATICS – 7356/2 – JUNE 2024 7 Q Marking instructions AO Marks Typical solution 5 Evaluates 4n 2 + 3 for at least one value of n 3.1a M1 n = 1 gives 7 n = 2 gives 19 n = 3 gives 39 39 = 3 × 13 so not prime Obtains one value that is not prime 2.3 A1 Shows explicitly that their value factorises. 2.4 R1 Question 5 Total 3 Q Marking instructions AO Marks Typical solution 6(a) Applies Binomial Expansion formula to x 2 term. At least two of nC2, 3n – 2 or (ax) 2 or a 2 correct. 1.1a M1 x 2 term = nC2 3n – 2(ax) 2 n n( ) −1 2 × n 3 9 × a 2 = 4860 3 n a 2n(n – 1) = 2 × 9 × 4860 = 87480 Expresses nC2 = n n( ) −1 2 Or 3 n – 2 as n 3 9 or 3n × 3−2 1.2 B1 Completes reasoned argument to obtain given expression AG 2.1 R1 Subtotal 3 Q Marking instructions AO Marks Typical solution 6(b)(i) Verifies that n = 6 1.1b B1 Constant term is 3n 3 6 = 729 So n = 6 Subtotal 1 Q Marking instructions AO Marks Typical solution 6(b)(ii) Substitutes n = 6 into formula from (a) Or Obtains 6C2 34a 2 = 4860 PI by a = 2 or a = −2 or a 2 = 4 1.1a M1 729a 2 × 6 × 5 = 87480 a 2 = 4 a = ±2 Negative x coefficient so a = –2 Obtains a 2 = 4 ACF PI by a = 2 or a = −2 1.1b A1 Deduces that a = –2 2.2a R1 Subtotal 3

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AQA

AS
MATHEMATICS
7356/2




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Paper 2




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Mark scheme




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June 2024
Version: 1.0 Final
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Page 1 of 17

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MARK SCHEME – AS MATHEMATICS – 7356/2 – JUNE 2024



Mark schemes are prepared by the Lead Assessment Writer and considered, together with the relevant
questions, by a panel of subject teachers. This mark scheme includes any amendments made at the
standardisation events which all associates participate in and is the scheme which was used by them in
this examination. The standardisation process ensures that the mark scheme covers the students’
responses to questions and that every associate understands and applies it in the same correct way.
As preparation for standardisation each associate analyses a number of students’ scripts. Alternative
answers not already covered by the mark scheme are discussed and legislated for. If, after the
standardisation process, associates encounter unusual answers which have not been raised they are
required to refer these to the Lead Examiner.

It must be stressed that a mark scheme is a working document, in many cases further developed and
expanded on the basis of students’ reactions to a particular paper. Assumptions about future mark
schemes on the basis of one year’s document should be avoided; whilst the guiding principles of




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assessment remain constant, details will change, depending on the content of a particular examination
paper.




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No student should be disadvantaged on the basis of their gender identity and/or how they refer to the
gender identity of others in their exam responses.




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A consistent use of ‘they/them’ as a singular and pronouns beyond ‘she/her’ or ‘he/him’ will be credited in
exam responses in line with existing mark scheme criteria.
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Further copies of this mark scheme are available from aqa.org.uk
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MARK SCHEME – AS MATHEMATICS – 7356/2 – JUNE 2024



Mark scheme instructions to examiners
General
The mark scheme for each question shows:
• the marks available for each part of the question
• the total marks available for the question
• marking instructions that indicate when marks should be awarded or withheld including the principle
on which each mark is awarded. Information is included to help the examiner make his or her
judgement and to delineate what is creditworthy from that not worthy of credit
• a typical solution. This response is one we expect to see frequently. However credit must be given on
the basis of the marking instructions.




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If a student uses a method which is not explicitly covered by the marking instructions the same
principles of marking should be applied. Credit should be given to any valid methods. Examiners should




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seek advice from their senior examiner if in any doubt.

Key to mark types




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M mark is for method
R mark is for reasoning A
A mark is dependent on M marks and is for accuracy
B mark is independent of M marks and is for method and accuracy
E mark is for explanation
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F follow through from previous incorrect result

Key to mark scheme abbreviations

CAO correct answer only
TH


CSO correct solution only
ft follow through from previous incorrect result
‘their’ indicates that credit can be given from previous incorrect result
AWFW anything which falls within
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AWRT anything which rounds to
ACF any correct form
M




AG answer given
SC special case
OE or equivalent
NMS no method shown
PI possibly implied
sf significant figure(s)
dp decimal place(s)
ISW Ignore Subsequent Workings




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