Level 3 GCE
Wednesday 13 May 2020
Paper Reference 8MA0/01
Solved by shahbaz ahmed
November 2024
Mathematics
Advanced Subsidiary
Paper 1: Pure Mathematics
1. A curve has equation
y = 2x3 − 4x + 5
Find the equation of the tangent to the curve
at the point P (2, 13).
Write your answer in the form y = mx + c,
1
,where m and c are integers to be found
Solution
y = 2x3 − 4x + 5
dy d
= (2x3 − 4x + 5)
dx dx
dy d d d
= (2x3) − (4x) + (5)
dx dx dx dx
dy d dx d
= 2 (x3) − 4 + (5)
dx dx dx dx
dy
= 2(3x2) − 4 + 0 = 6x2 − 4
dx
Slope of the line at the point P (2, 13) = P (x, y)
dy
m= = 6(2)2 − 4 = 20
dx
Where m denotes the slope at the point P (2, 13)
Putting P (2, 13) = P (x, y) and m = 20 in :
y = mx + c
2
, 13 = 20 × 2 + c
13 = 40 + c
40 + c = 13
c = 13 − 40 = −27
Putting m=20, c=-27 , equation of tangent to the curve
at the point P(2,13)
y = mx + c = 20x − 27
Or
y = 20x − 27
3
, Graph of solution
............................................................................
Solution
(a) Calculate the bearing on which the boat is
moving.
To calculate the bearing, we first determine the dis-
placement vector. The displacement vector d is given
by:
d = final position − initial position.
4