Edition Jerome
1 Review and Applications of
Basic Mathematics
Exercise 1.1
a. 10 + 10 x 0 = 10 + 0 = 10
b. 2x2+4–8=4+4–8=0
c. (10 + 10) x 0 = 20 x 0 = 0
d. 2 x (2 + 4) – 8 = 2 x 6 – 8 = 12 – 8 = 4
e. 0 + 3 x 3 – 32 + 10 = 0 + 9 – 9 + 10 = 10
f. 12 – 2 x 5 + 22 x 0 = 12 – 10 + 4 x 0 = 12 – 10 + 0 = 2
g. 0 + 3 x 3 – (32 + 10) = 0 + 9 – 19 = -10
h. (12 – 2) x (5 + 22) x 0 = 10 x 9 x 0 = 0
22 - 4 4-4 0
i. 2
= 2
= =0
(4- 2) 2 4
(2 - 4)2 (-2)2 4
j. = = =4
5- 22 5- 4 1
1. 20 − 4 2 − 8 = 20 − 8 − 8 = 4
2. 18 3 + 6 2 = 6 + 12 = 18
3. (20 − 4) 2 − 8 = 16 2 − 8 = 32 − 8 = 24
4. 18 (3 + 6) 2 = 18 9 2 = 2 2 = 4
5. 20 − (4 2 − 8) = 20 − (8 − 8) = 20
6. (18 3 + 6) 2 = (6 + 6) 2 = 24
7. 54 − 36 4 + 22 = 54 − 9 + 4 = 49
8. (5 + 3)2 − 3 2 9 + 3 = 8 2 − 9 9 + 3 = 64 − 1 + 3 = 66
9. (54 − 36) (4 + 2) 2 = 18 6 2 = 18 36 = 0.5
(
10. 5 + 3 2 − 3 ) 2
(9 + 3) = 5 + (9 − 3)2 12 = 5 + 36 12 = 5 + 3 = 8
82 − 42 64 − 16 48
11. = = =6
(4 − 2) 3
2 3 8
12.
(8 − 4)2 =
42
=
16
= −4
4 − 23 4−8 −4
13. 3(6 + 4)2 − 5(17 − 20)2 = 3 10 2 − 5(− 3)2 = 3 100 − 5 9 = 300 − 45 = 255
Chapter 1: Review and Applications of Basic Mathematics 1
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14. (4 3 − 2)2 (4 − 3 22 ) = (12 − 2)2 (4 − 3 4) = 10 2 (4 − 12) = 100 (− 8) = − 12.5
15. (20 + 8 5) − 7 (− 3) 9 = (20 + 40 + 21) 9 = 81 9 = 9
( )
2
16. 5 19 + 5 2 − 16 = 5 19 + (25 − 16 )2 = 5(19 + 81)2 = 5 100 2 = 50 ,000
2 2
17. $100(1+ 0.06 365
45
) = $100(1+ 0.00739726) = $100.74
$200 $200 $200
18. = = = $194.17
1 + 0.09 12 1 + 0.03 1.03
4
$500 $500 $500
19. = = = $453.51
(1 + 0.05) 2
1.05 2
1.1025
( )
20. $1000 (1 + 0.02) = $1000 1.023 = $1000 ( 1.061208 ) = $1061.21
3
(1 + 0.04)2 − 1 1.042 − 1
= $100
0.0816
21. $100 = $100 = $204.00
0.04 0.04 0.04
1 1
1 − 2 1−
22. $300
(1 + 0.03 ) = $300 1.0609 = $300 1 − 0.942596 = $574.04
0.03 0.03 0.03
Concept Questions (Section 1.2)
1. You must retain at least one more figure than you require in the answer. To achieve four-
figure accuracy in the answer, you must retain a minimum of five figures in the values
used in the calculations. B)
2. We want six-figure accuracy in the answer. Therefore, values used in the calculations
must be accurate to at least seven figures. B)
3. We want seven-figure accuracy in the answer. Therefore, values used in the calculations
must retain at least eight figures. C)
4. To be accurate to the nearest 0.01%, an interest rate greater than 10% must have four-
figure accuracy. Therefore, five figures must be retained in numbers used in the
calculations. C)
Exercise 1.2
1
a. 10
= 0.10 = 10%
2
b. = 0.40 = 40%
5
1
c. = 0.25 = 25%
4
3
d. = 0.75 = 75%
4
1
e. 1 2 = 1.50 = 150%
1
f. 2 3 = 2.3333 = 233.33%
2 Business Mathematics in Canada, 11/e
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, ACCESS Test Bank for Business Mathematics In Canada 11th Canadian
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10
g. = 2.00 = 200%
5
2
h. 53 = 5.6667 = 566.67%
i. 0.25 x 80 = 20
j. 0.20 x 120 = 24
k. Money in Savings = 0.20 x $1000 = $200
Money in TFSA = 0.50 x $200 = $100
1. 7
8
= 0.87500 = 87.500%
2. 65
104
= 0.62500 = 62.500%
3. 47
20
= 2.3500 = 235.00%
9
4. − = −0.56250 = −56.250%
16
−35
5. = −1.4000 = −140.00%
25
7
6. 1 25 = 1.2800 = 128.00%
7. 25
1000
= 0.025000 = 2.5000%
8. 1000
25
= 40.000 = 4000.0%
9. 2
2 100 = 2.0200 = 202.00%
10. − 1 32
11
= −1.3438 = −134 .38%
11. 37.5
50
= 0.75000 = 75.000%
12. 22.5
−12
= − 1.8750 = − 187.50%
13. 5
6
= 0.83 = 83. 3%
14. − 83 = −2. 6 = −266. 6%
15. 7 79 = 7.7 = 777.7%
1 = 1. 09 = 109. 09%
16. 111
17. 10 = 11
. = 1111
.%
9
4
18. − 900 = −0.004̅ = −0. 4̅%
19. − 270
7
= − 0.0259 = − 2.592%
20. 37
27
= 1. 370 = 137. 037%
21. 11.3845 11.38
22. 9.6455 9.646
23. 0.5545454 0.5545
24. 1000.49 1000
Chapter 1: Review and Applications of Basic Mathematics 3
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