Test Bank For Elementary & Intermediate Algebra 4th Edition By Michael Sullivan III; Katherine R. Struve

DOWNLOAD THE Test Bank for Elementary and Intermediate Algebra 4th Editi
e e e e e e e e e e

on Sullivan e
MULTIPLEeCHOICE.e Choosee thee onee alternativee thate beste completese thee statemente ore answerse thee question.

1)
Answer:e NoeCorrecteAnswere WaseProvided.

Determineeifetheegivenevalueeiseaesolutionetoetheeequation.e Answere YeseoreNo.
2) 8xe-10e=e15;e xe =e3
A) No
B) YeseA
nswer:e A

3) 6me+e3e=e17;e me=e2
A) Yes
B) No
Answer:e B

e 1
4) 6ke-e1e=e1;e ke=e
3
A) Yes
B) No
Answer:e A

e 6
5) 2e-e(xe+e2)e =e3(3xe-e4);e xe=e
5
A) No
B) Yese
Answer:e B

6) 7ne+e1.7e=e8ne+e4.7;e ne=e-3
A) No
B) Yese
Answer:e B

7) 4me-e2e=e-3me-e14;e me=e-2
A) Yes
B) No
Answer:e B

8) 3(xe-e1)e-exe=e4xe+e5;e xe =e-4
A) Yes
B) No
Answer:e A

Solveethee equationeusingethee AdditionePropertyeofe Equality.e Bee suree toecheckeyoure solution.
9) -15e=ebe+e10
A) {-25}
B) {5}
C) {-5}
D) {25}
Answer:e A



1

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,DOWNLOAD THE Test Bank for Elementary and Intermediate Algebra 4th Editi
e e e e e e e e e e

on Sullivan e


10) -20e=e-e19e+ex
A) {-1}
B) {-39}
C) {380}
D) {1}
Answer:e A

11) be+e10e=e7
A) {17}
B) {3}
C) {-17}
D) {-3e }
Answer:e D

12) te-e7e=e17
A) {10}
B) {-24}
C) {24}
D) {-10}
Answer:e C

13) xe-e17e=e-14
A) {-31}
B) {31}
C) {-3}
D) {3}
Answer:e D

e1e e8
14) xe+e =e
9 9
2
A)
3
7
B)
8
7
C)
9
D) 1
Answer:e C

e 1 10
15) xe-e =e
e

11 e1
1
A) 1
e 8
B) e1
1
e 9
C) e1
1
e 9e
D) 10

Answer:e A

2

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e e e e e e e e e e

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14e
e e 19
16) -e =exe-e
23 23
e 5
A) - e

23
B) -
3 e
e
3e
23
e33
C) e2
3
e 5e
D) 23

Answer:e D

e 7 =e-
17) -e e2e
12 e +e
xe3
5
e
A)
4
e1e
B)
12

C)
12

D)
4
Answer:e B

e2e e1
18) xe+e =e-e
3 6
A) - e
e
1
e

2
B) - e
e
8
e

9
C) - e
e
5
e

6
D) - e
e
1
e

3
Answer:e C

1
e e
19) +exe=e6
4
e5
A) e
4
B) 23
e25
C)
3

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, DOWNLOAD THE Test Bank for Elementary and Intermediate Algebra 4th Editi
e e e e e e e e e e


4 e
on Sullivane


23
e
D) e4


Answer:e D




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