ATI$TEAS$TEST$$MATHEMATICS-with$
100%$verified$solutions-2023-2024$
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Which%of%the%following%is%the%percentage%equivalent%of%0.0016?%
A.%16%%
B.%160%%
C.%1.6%%
D.%0.16%%-%D.%To%derive%a%percentage%from%a%decimal,%multiply%by%100:%
0.0016(100)%=%0.16%%
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Curtis%is%taking%a%road%trip%through%Germany,%where%all%distance%signs%are%in%metric.%He%
passes%a%sign%that%states%the%city%of%Dusseldorf%is%45%kilometers%away.%Approximately%how%
far%is%this%in%miles?%
A. 42%miles%
B. 37%miles%
C. 28%miles%
D. 16%miles%-%C.%one%kilometer%is%about%0.62%miles,%
45(0.62)%=%27.9%
approximately%28%miles%
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On%a%floor%plan%drawn%at%a%scale%of%1:100,%the%area%of%a%rectangular%room%is%30%cm2.%What%is%
the%actual%area%of%the%room?%
A.%30,000%cm2%
B.%300%m2%
C.%3,000%m2%
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D.%30%m2%-%D.%Since%there%are%100%cm%in%a%meter,%on%a%1:100%scale%drawing,%each%centimeter%
represents%one%meter.%Therefore,%an%area%of%one%square%centimeter%on%the%drawing%
represents%one%square%meter%tin%actuality.%
-%Since%the%area%of%the%room%in%the%scale%drawing%is%30%cm2,%the%room's%actual%area%is%30%m2.%
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L/100%x%W/100%=%30%cm2%
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lw/100%=%30%cm2%
Area%=%300,000%cm2%
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300,000%cm2%x.%1m/100%cm%x%1m/100%cm%=%30m2%
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Mandy%can%buy%4%containers%of%yogurt%and%3%boxes%of%crackers%for%$9.55.%She%can%buy%2%
containers%of%yogurt%and%2%boxes%of%crackers%for%$5.90.%How%much%does%one%box%of%crackers%
cost?%
A.%$1.75%
B.%$2.00%
C.%$2.25%
D.%$2.50%-%C.%
The%situation%may%be%modeled%by%the%system:%
4x%+%3y%=%9.55%
2x%+%2y%=%5.90%
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Multiplying%the%bottom%equation%by%-%2%gives:%
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4x%+%3y%=%9.55%
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-4x%-%4y%=%-11.80%
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Addition%of%the%two%equations%gives%-%y%=%-2.25%or%y%=%2.25.%Thus,%one%box%of%crackers%costs%
$2.25%
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9.55-11.80%=%-2.25%
-y%=%-2.25%
-y/-1%=%-2.25/-1%
y%=%2.25%
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1.%
THE%NEXT%TWO%QUESTIONS%ARE%BASED%ON%THE%FOLLOWING%INFORMATION:%
%Pernell's%scores%on%her%last%five%chemistry%exams%were%81,%92,%87,%89,%and%94.%
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What%is%the%approximate%average%of%her%scores?%
A.%81%
B. 84%
C. 89%
D. 91%-%C.%To%find%the%average%of%Pernell's%scores,%add%them%up%and%then%divide%by%the%
number%of%scores%(5%in%this%case).%In%other%words,%
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81%+%92%+%87%+%89%+%94%=%443%
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443/5%=%89%
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2.%
THE%NEXT%QUESTIONS%ARE%BASED%ON%THE%FOLLOWING%INFORMATION:%
%Pernell's%scores%on%her%last%five%chemistry%exams%were%81,%92,%87,%89,%and%94.%
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What%is%the%medium%of%Pernell's%scores?%
A.%87%
B. 89%
C. 92%
D. 94%-%B.%To%find%the%median,%list%the%series%of%numbers%form%least%to%greatest.%
The%middle%number%represents%the%median%--%in%this%case%81,%87,%89,%92,%94.%
The%number%89%is%in%the%middle,%so%it%is%the%median.%
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Gordon%purchased%a%television%when%his%local%electronics%store%had%a%sale.%The%television%
was%offered%at%30%%off%its%original%price%of%$472.%What%was%the%sale%price%that%Gordon%paid?%
A.%$141.60%
B.%$225.70%
C.%$305.30%
D.%$330.40%-%D.%The%television%is%30%%off%its%original%price%of%$472.%30%%of%472%is%141.60.%
(0.30)(472)%=%141.60%
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472%-%141.60%=%330.40%
Thus,%Gordon%paid%$330.40%for%the%television.%
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Simplify%the%following%expression:%
(2/3)%/%(4/15)%X%(5/8)%
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