ANALYSIS OF VARIANCE
The analysis of variance is a powerful statistical tool for tests of significance.
We consider the following types of ANOVA
I) One- way classification (One factor ANOVA) –Completely Randomized Design.
II) Two-Way classification (Two factors)-Randomized Block Design.
III) Latin Square Design-Three Way ANOVA
ONE - WAY ANOVA
One- way classification observations are classified according to one factor
WORKING PROCEDURE:
Null Hypothesis 𝐻0 : 𝑇ℎ𝑒𝑟𝑒 𝑖𝑠 𝑛𝑜 𝑠𝑖𝑔𝑛𝑖𝑓𝑖𝑐𝑎𝑛𝑐𝑒 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 𝑏𝑒𝑡𝑤𝑒𝑒𝑛 … … …
Alternative Hypothesis 𝐻1 : 𝑇ℎ𝑒𝑟𝑒 𝑖𝑠 𝑠𝑖𝑔𝑛𝑖𝑓𝑖𝑐𝑎𝑛𝑐𝑒 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 𝑏𝑒𝑡𝑤𝑒𝑒𝑛 … … … ..
STEP1: To find the following
𝑁 = 𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑜𝑏𝑠𝑒𝑟𝑣𝑎𝑡𝑖𝑜𝑛𝑠
𝑇 = ∑ 𝑋1 + ∑ 𝑋2 + ∑ 𝑋3 + ⋯
𝑇2
Correction factor: 𝐶. 𝐹 = 𝑁
STEP2: To Calculate the following
𝑇𝑆𝑆 = ∑𝑋12 + ∑𝑋22 + ∑𝑋32 + ⋯ − 𝐶. 𝐹
(∑ 𝑋1 )2 (∑ 𝑋2 )2
𝑆𝑆𝐶 = 𝑛1
+ 𝑛2
+ ⋯ − 𝐶. 𝐹
𝑆𝑆𝐸 = 𝑇𝑆𝑆 − 𝑆𝑆𝐶
STEP3: O NE- WAY ANOVA TABLE
SOURCE OF SUM OF SQUARES DEGREES OF MEAN SUM OF VARIATION RATIO
VARIATION FREEDOM SQUARES
BETWEEN SSC = C–1= 𝑆𝑆𝐶 𝑀𝑆𝐸
𝑀𝑆𝐶 = 𝐹𝑐 =
COLUMNS 𝐶−1 𝑀𝑆𝐶
ERROR SSE = N–C= 𝑆𝑆𝐸
𝑀𝑆𝐸 =
𝑁−𝐶
TOTAL
, NOTE: IF CALCULATED VALUE OF F < TABULATED VALUE OF F, THEN 𝐻0 IS ACCEPTED.
IF CALCULATED VALUE OF F > TABULAED VALUE OF F, THEN 𝐻0 𝐼𝑆 𝑅𝐸𝐽𝐸𝐶𝑇𝐸𝐷.
PROBLEM 1:
The following figures relate to production in kgs. of three variables A, B, C of wheat sown on 12 plots
A 14 16 18
B 14 13 15 22
C 18 16 19 19 22
Is there any significant difference in the production of the Varieties.
SOLUTION:
Null Hypothesis:
𝐻0 ∶ 𝑇ℎ𝑒𝑟𝑒 𝑖𝑠 𝑛𝑜 𝑠𝑖𝑔𝑛𝑖𝑓𝑖𝑐𝑎𝑛𝑐𝑒 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 𝑏𝑒𝑡𝑤𝑒𝑒𝑛 𝑖𝑛 𝑡ℎ𝑒 𝑝𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑜𝑛 𝑜𝑓 𝑣𝑎𝑟𝑖𝑒𝑡𝑖𝑒𝑠.
Alternative Hypothesis:
𝑯 𝟏 : 𝑇ℎ𝑒𝑟𝑒 𝑖𝑠 𝑠𝑖𝑔𝑛𝑖𝑓𝑖𝑐𝑎𝑛𝑐𝑒 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 𝑏𝑒𝑡𝑤𝑒𝑒𝑛 𝑖𝑛 𝑡ℎ𝑒 𝑝𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑜𝑛 𝑜𝑓 𝑡ℎ𝑒 𝑣𝑎𝑟𝑖𝑒𝑡𝑖𝑒𝑠.
𝑋1 𝑋2 𝑋3 𝑋12 𝑋22 𝑋32
14 14 18 196 196 324
16 13 1 256 169 256
18 15 19 324 225 341
22 19 484 361
20 400
TOTAL ∑𝑋2 = 64 ∑𝑋3 = 92 ∑𝑋12 = 776 ∑𝑋22 = 1074 ∑𝑋32 = 1702
∑𝑋1 = 48
The analysis of variance is a powerful statistical tool for tests of significance.
We consider the following types of ANOVA
I) One- way classification (One factor ANOVA) –Completely Randomized Design.
II) Two-Way classification (Two factors)-Randomized Block Design.
III) Latin Square Design-Three Way ANOVA
ONE - WAY ANOVA
One- way classification observations are classified according to one factor
WORKING PROCEDURE:
Null Hypothesis 𝐻0 : 𝑇ℎ𝑒𝑟𝑒 𝑖𝑠 𝑛𝑜 𝑠𝑖𝑔𝑛𝑖𝑓𝑖𝑐𝑎𝑛𝑐𝑒 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 𝑏𝑒𝑡𝑤𝑒𝑒𝑛 … … …
Alternative Hypothesis 𝐻1 : 𝑇ℎ𝑒𝑟𝑒 𝑖𝑠 𝑠𝑖𝑔𝑛𝑖𝑓𝑖𝑐𝑎𝑛𝑐𝑒 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 𝑏𝑒𝑡𝑤𝑒𝑒𝑛 … … … ..
STEP1: To find the following
𝑁 = 𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑜𝑏𝑠𝑒𝑟𝑣𝑎𝑡𝑖𝑜𝑛𝑠
𝑇 = ∑ 𝑋1 + ∑ 𝑋2 + ∑ 𝑋3 + ⋯
𝑇2
Correction factor: 𝐶. 𝐹 = 𝑁
STEP2: To Calculate the following
𝑇𝑆𝑆 = ∑𝑋12 + ∑𝑋22 + ∑𝑋32 + ⋯ − 𝐶. 𝐹
(∑ 𝑋1 )2 (∑ 𝑋2 )2
𝑆𝑆𝐶 = 𝑛1
+ 𝑛2
+ ⋯ − 𝐶. 𝐹
𝑆𝑆𝐸 = 𝑇𝑆𝑆 − 𝑆𝑆𝐶
STEP3: O NE- WAY ANOVA TABLE
SOURCE OF SUM OF SQUARES DEGREES OF MEAN SUM OF VARIATION RATIO
VARIATION FREEDOM SQUARES
BETWEEN SSC = C–1= 𝑆𝑆𝐶 𝑀𝑆𝐸
𝑀𝑆𝐶 = 𝐹𝑐 =
COLUMNS 𝐶−1 𝑀𝑆𝐶
ERROR SSE = N–C= 𝑆𝑆𝐸
𝑀𝑆𝐸 =
𝑁−𝐶
TOTAL
, NOTE: IF CALCULATED VALUE OF F < TABULATED VALUE OF F, THEN 𝐻0 IS ACCEPTED.
IF CALCULATED VALUE OF F > TABULAED VALUE OF F, THEN 𝐻0 𝐼𝑆 𝑅𝐸𝐽𝐸𝐶𝑇𝐸𝐷.
PROBLEM 1:
The following figures relate to production in kgs. of three variables A, B, C of wheat sown on 12 plots
A 14 16 18
B 14 13 15 22
C 18 16 19 19 22
Is there any significant difference in the production of the Varieties.
SOLUTION:
Null Hypothesis:
𝐻0 ∶ 𝑇ℎ𝑒𝑟𝑒 𝑖𝑠 𝑛𝑜 𝑠𝑖𝑔𝑛𝑖𝑓𝑖𝑐𝑎𝑛𝑐𝑒 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 𝑏𝑒𝑡𝑤𝑒𝑒𝑛 𝑖𝑛 𝑡ℎ𝑒 𝑝𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑜𝑛 𝑜𝑓 𝑣𝑎𝑟𝑖𝑒𝑡𝑖𝑒𝑠.
Alternative Hypothesis:
𝑯 𝟏 : 𝑇ℎ𝑒𝑟𝑒 𝑖𝑠 𝑠𝑖𝑔𝑛𝑖𝑓𝑖𝑐𝑎𝑛𝑐𝑒 𝑑𝑖𝑓𝑓𝑒𝑟𝑒𝑛𝑐𝑒 𝑏𝑒𝑡𝑤𝑒𝑒𝑛 𝑖𝑛 𝑡ℎ𝑒 𝑝𝑟𝑜𝑑𝑢𝑐𝑡𝑖𝑜𝑛 𝑜𝑓 𝑡ℎ𝑒 𝑣𝑎𝑟𝑖𝑒𝑡𝑖𝑒𝑠.
𝑋1 𝑋2 𝑋3 𝑋12 𝑋22 𝑋32
14 14 18 196 196 324
16 13 1 256 169 256
18 15 19 324 225 341
22 19 484 361
20 400
TOTAL ∑𝑋2 = 64 ∑𝑋3 = 92 ∑𝑋12 = 776 ∑𝑋22 = 1074 ∑𝑋32 = 1702
∑𝑋1 = 48