GROUP 7
CE 486
STRUCTURAL
DESIGN
STAGE-2
1. CALCULATION OF THICKNESS OF SLABS
2. CALCULATION OF LOADS OF SLABS
3. CALCULATION OF MOMENTS AT SLABS
4. CALCULATION OF REINFORCEMENT OF SLABS
5. CALCULATION OF REINFORCEMENT OF SUPPORTS
6. SKETCH OF REINFORCEMENT
SUBMITTED BY: ÜMİT GÜLER
FATİH SUSİ
SEMİH SERDAR ASLANHAN
FERHAT KÖKSAL
SUBMITTED TO: RESEARCH. ASST. KASIM MERMERDAŞ
01.04.2011
GROUP 7
, 1. INTRODUCTION
Firstly we calculated thickness of the slabs. The thickness of the balcony slabs are 16 cm,
and the others are 12 cm. These thickness are bigger thickness of the balcony and room slabs,
respectively. They are most critical thickness. Then we calculated dead and live loads. According
to those loads we determined the moments. After that we found required steel area of each slab.
According to ϕ8 steel bar, we determined space of the reinforcement bars. Then we calculated
required steel area of supports. Finally we sketched each slabs reinforcements.
2. CALCULATION OF SLAB THICKNESSES
➢ D101:
ll 4,7 470 + 2 * 300
m= = = 1,56 < 2 two way slab s = = 0,695
ls 3 2 * 300 + 470 * 2
l sn 270 0,695
hmin 1 − s = 1 − = 8,01 cm
20 4 20 4
15 + 15 +
m 1,56
➢ D102:
ll 4,7 2 * 470 + 2 * 415
m= = = 1,13 < 2 two way slab s = =1
ls 4,15 2 * 415 + 470 * 2
l sn 385 1
hmin 1 − s = 1 − = 8,83 cm
20 4 15 + 20 4
15 +
m 1,13
, ➢ D103:
ll 4,05 2 * 345 + 2 * 405
m= = = 1,17 < 2 two way slab s = =1
ls 345 2 * 345 + 405 * 2
l sn 315 1
hmin 1 − s = 1 − = 7,36 cm
20 4 20 4
15 + 15 +
m 1,17
➢ D104:
ll 4,15 2 * 415 + 2 * 405
m= = = 1,02 < 2 two way slab s = =1
ls 4,05 2 * 415 + 405 * 2
l sn 375 1
hmin 1 − s = 1 − = 8,12 cm
20 4 20 4
15 + 15 +
m 1,02
➢ D105:
ll 4,7 410 + 2 * 470
m= = = 1,15 < 2 two way slab s = = 0,767
ls 4,1 2 * 410 + 470 * 2
l sn 380 0,767
hmin 1 − s = 1 − = 9,48 cm
15 +
20 4 15 + 20 4
m 1,15
, ➢ D106:
ll 4,90 2 * 490 + 2 * 420
m= = = 1,17 < 2 two way slab s = =1
ls 4,20 2 * 490 + 420 * 2
l sn 390 1
hmin 1 − s = 1 − = 8,12 cm
20 4 15 + 20 4
15 +
m 1,17
➢ D107:
ll 5,2 2 * 520
m= = = 1,89 < 2 two way slab s = = 0,654
ls 2,75 2 * 520 + 2 * 275
l sn 375 0,654
hmin 1 − s = 1 − 8,17 cm
15 +
20 4 15 + 20 4
m 1,89
➢ D108 – D109: (Balconies)
𝑙𝑛 120
hmin = = = 10 cm (Cantilever slabs)
12 12
CE 486
STRUCTURAL
DESIGN
STAGE-2
1. CALCULATION OF THICKNESS OF SLABS
2. CALCULATION OF LOADS OF SLABS
3. CALCULATION OF MOMENTS AT SLABS
4. CALCULATION OF REINFORCEMENT OF SLABS
5. CALCULATION OF REINFORCEMENT OF SUPPORTS
6. SKETCH OF REINFORCEMENT
SUBMITTED BY: ÜMİT GÜLER
FATİH SUSİ
SEMİH SERDAR ASLANHAN
FERHAT KÖKSAL
SUBMITTED TO: RESEARCH. ASST. KASIM MERMERDAŞ
01.04.2011
GROUP 7
, 1. INTRODUCTION
Firstly we calculated thickness of the slabs. The thickness of the balcony slabs are 16 cm,
and the others are 12 cm. These thickness are bigger thickness of the balcony and room slabs,
respectively. They are most critical thickness. Then we calculated dead and live loads. According
to those loads we determined the moments. After that we found required steel area of each slab.
According to ϕ8 steel bar, we determined space of the reinforcement bars. Then we calculated
required steel area of supports. Finally we sketched each slabs reinforcements.
2. CALCULATION OF SLAB THICKNESSES
➢ D101:
ll 4,7 470 + 2 * 300
m= = = 1,56 < 2 two way slab s = = 0,695
ls 3 2 * 300 + 470 * 2
l sn 270 0,695
hmin 1 − s = 1 − = 8,01 cm
20 4 20 4
15 + 15 +
m 1,56
➢ D102:
ll 4,7 2 * 470 + 2 * 415
m= = = 1,13 < 2 two way slab s = =1
ls 4,15 2 * 415 + 470 * 2
l sn 385 1
hmin 1 − s = 1 − = 8,83 cm
20 4 15 + 20 4
15 +
m 1,13
, ➢ D103:
ll 4,05 2 * 345 + 2 * 405
m= = = 1,17 < 2 two way slab s = =1
ls 345 2 * 345 + 405 * 2
l sn 315 1
hmin 1 − s = 1 − = 7,36 cm
20 4 20 4
15 + 15 +
m 1,17
➢ D104:
ll 4,15 2 * 415 + 2 * 405
m= = = 1,02 < 2 two way slab s = =1
ls 4,05 2 * 415 + 405 * 2
l sn 375 1
hmin 1 − s = 1 − = 8,12 cm
20 4 20 4
15 + 15 +
m 1,02
➢ D105:
ll 4,7 410 + 2 * 470
m= = = 1,15 < 2 two way slab s = = 0,767
ls 4,1 2 * 410 + 470 * 2
l sn 380 0,767
hmin 1 − s = 1 − = 9,48 cm
15 +
20 4 15 + 20 4
m 1,15
, ➢ D106:
ll 4,90 2 * 490 + 2 * 420
m= = = 1,17 < 2 two way slab s = =1
ls 4,20 2 * 490 + 420 * 2
l sn 390 1
hmin 1 − s = 1 − = 8,12 cm
20 4 15 + 20 4
15 +
m 1,17
➢ D107:
ll 5,2 2 * 520
m= = = 1,89 < 2 two way slab s = = 0,654
ls 2,75 2 * 520 + 2 * 275
l sn 375 0,654
hmin 1 − s = 1 − 8,17 cm
15 +
20 4 15 + 20 4
m 1,89
➢ D108 – D109: (Balconies)
𝑙𝑛 120
hmin = = = 10 cm (Cantilever slabs)
12 12
