MULTIPLEmCHOICE
1. In man manalysismof mvariance mproblem mif mSSTm=m120 mand mSSTRm=m80,mthen mSSEmis
a. 200
b. 40
c. 80
d. 120
ANS:m B PTS:m m 1
2. In mthemanalysismof mvariance mprocedure m(ANOVA), mfactormrefersmto
a. themdependentmvariable
b. themindependentmvariable
c. differentmlevelsmof mamtreatment
d. themcriticalmvaluemof mFmA
NS:m B
PTS:m m 1
3. In man manalysismofmvariancemproblem minvolvingm3 mtreatmentsmand m10 mobservationsmpermtreatment,mSSEm=
399.6.mThemMSEmformthismsituation mis
a. 133.2
b. 13.32
c. 14.8
d. 30.0
ANS:m C PTS:m m 1
4. When man manalysismofmvariancemismperformedmon msamplesmdrawn mfrommkmpopulations,mthemmean msq
uarembetween mtreatmentsm(MSTR)mis
a. SSTR/n T
b. SSTR/(n Tm-m1)
c. SSTR/k
d. SSTR/(km-m1)
e. Nonemofmthesemalternativesmismcorrec
t.mANS:m D PTS:m 1
5. In man manalysismofmvariancemwheremthemtotalmsamplemsizemformthemexperimentmismn Tmand mthemnumb
ermof mpopulationsmismk,mthemmean msquaremwithin mtreatmentsmis
a. SSE/(n Tm-mk)
b. SSTR/(n Tm-mk)
c. SSE/(km-m1)
d. SSE/k
ANS:m A PTS:m m 1
6. ThemFmratio min mamcompletely mrandomized mANOVAmismthemratio mof
a. MSTR/MSE
b. MST/MSE
c. MSE/MSTR
d. MSE/MST
, ANS:m A PTS:m m 1
7. ThemcriticalmFmvalue mwith m6 mnumeratormand m60 mdenominatormdegreesmof mfreedom matm m=m.05 mis
a. 3.74
b. 2.25
c. 2.37
d. 1.96
ANS:m B PTS:m m 1
8. ThemANOVAmprocedure mismamstatisticalmapproach mformdeterminingmwhethermormnot
a. themmeansmof mtwo msamplesmaremequal
b. themmeansmof mtwo mormmoremsamplesmaremequal
c. themmeansmof mmoremthan mtwo msamplesmaremequal
d. themmeansmofmtwomormmorempopulationsmaremequ
almANS:m D PTS:m 1
9. Themvariable mof minterestmin man mANOVAmprocedure mismcalled
a. ampartition
b. amtreatment
c. eithermampartition mormamtreatment
d. amfactor
ANS:m D PTS:m m 1
10. An mANOVAmproceduremismappliedmto mdatamobtained mfromm6msamplesmwheremeachmsamplemcontains
m20 mobservations. mThe mdegrees mof mfreedom mformthe mcriticalmvalue mof mFmare
a. 6 mnumeratormand m20 mdenominatormdegreesmof mfreedom
b. 5 mnumeratormand m20 mdenominatormdegreesmof mfreedom
c. 5 mnumeratormand m114 mdenominatormdegreesmof mfreedom
d. 6 mnumeratormand m20mdenominatormdegreesmofmfreedo
mmANS:m C PTS:m 1
11. In mthemANOVA,mtreatmentmrefersmto
a. experimentalmunits
b. differentmlevelsmof mamfactor
c. amfactor
d. applyingmantibioticmto mamwoun
d mANS:m B PTS:m 1
12. Themmean msquaremismthemsummof msquaresmdivided mby
a. themtotalmnumbermof mobservations
b. itsmcorrespondingmdegreesmof mfreedom
c. itsmcorrespondingmdegreesmof mfreedom mminusmone
d. Nonemofmthesemalternativesmismcorrec
t.mANS:m B PTS:m 1
13. In mfactorialmdesigns,mthemresponsemproduced mwhenmthemtreatmentsmofmonemfactorminteractmwith
mthe mtreatments mof manothermin minfluencingmthe mresponse mvariable mismknown mas
a. main meffect
b. replication
c. interaction
, d. Nonemofmthesemalternativesmismcorrec
t.mANS:m C PTS:m 1
14. An mexperimentalmdesign mwheremthemexperimentalmunitsmaremrandomly massignedmtomthemtreatment
smismknown mas
a. factormblock mdesign
b. random mfactormdesign
c. completely mrandomized mdesign
d. Nonemofmthesemalternativesmismcorrec
t.mANS:m C PTS:m 1
15. Themnumbermof mtimesmeach mexperimentalmcondition mismobserved min mamfactorialmdesign mismknown mas
a. partition
b. replication
c. experimentalmcondition
d. factor
ANS:m B PTS:m m 1
Exhibitm13-1
SSTRm=m6,750 H0 :m1 =2 =3 =4
SSEm=m8,000 Ha:matmleastmonemmean mismdifferent
n Tm=m20
16. Refermto mExhibitm13-1.mThemmean msquarembetween mtreatmentsm(MSTR)mequals
a. 400
b. 500
c. 1,687.5
d. 2,250
ANS:m D PTS:m m 1
17. Refermto mExhibitm13-1.mThemmean msquaremwithin mtreatmentsm(MSE)mequals
a. 400
b. 500
c. 1,687.5
d. 2,250
ANS:m B PTS:m m 1
18. Refermto mExhibitm13-1.mThemtestmstatisticmto mtestmthemnullmhypothesismequals
a. 0.22
b. 0.84
c. 4.22
d. 4.5
ANS:m D PTS:m m 1
19. Refermto mExhibitm13-
1.mThemnullmhypothesismismtombemtested matmthem5% mlevelmofmsignificance.mThemcriticalmvaluemfrommthe
mtable mis
a. 2.87
b. 3.24
c. 4.08
, d. 8.7
ANS:m B PTS:m m 1
20. Refermto mExhibitm13-1.mThemnullmhypothesis
a. should mbemrejected
b. should mnotmbemrejected
c. wasmdesigned mincorrectly
d. Nonemofmthesemalternativesmismcorrec
t.mANS:m A PTS:m 1
Exhibitm13-2
Summof Degreesmo Mean
Source mofmVariatio mSquare f mFreedo Square F
n s m
Between mTreatments 2,073.6 4
Between mBlocks 6,000.0 5 1,200
Error 20 288
Total 29
21. Refermto mExhibitm13-2.mThemnullmhypothesismformthismANOVAmproblem mis
a. 1 =2 =3 =4
b.m m 1 =2 =3 =4 =5
c. 1 =2 =3 =4 =5 =6
d.m m 1 =2 =m...m=20
ANS:m B PTS:m m 1
22. Refermto mExhibitm13-2.mThemmean msquarembetween mtreatmentsmequals
a. 288
b. 518.4
c. 1,200
d. 8,294.4
ANS:m B PTS:m m 1
23. Refermto mExhibitm13-2.mThemsummof msquaresmduemto merrormequals
a. 14.4
b. 2,073.6
c. 5,760
d. 6,000
ANS:m C PTS:m m 1
24. Refermto mExhibitm13-2.mThemtestmstatisticmto mtestmthemnullmhypothesismequals
a. 0.432
b. 1.8
c. 4.17
d. 28.8
ANS:m B PTS:m m 1
25. Refermto mExhibitm13-
2.mThemnullmhypothesismismto mbemtestedmatmthem5%mlevelmofmsignificance.mThemcriticalmvaluemfrommthe
mtable mis