PortagecLearningc/cCHEMc103c/cModulec1ctoc6cExamcanswers
1
MODULEc1cEXAM
Question 1 c
Clickcthisc linkctoc accessc thec Periodic
ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
c Table.c Thisc mayc bec helpfulc throughout cthecexam.
1. Convertc 845.3c toc exponentialc formc andc explainc yourc answer.
2. Convertc 3.21c xc10-5cc tocordinaryc formc andc explainc yourc answer.
1. Convertc845.3c=clargercthanc1c=cpositivecexponent,cmovecdecimalc2cplaces
=c8.453c xc102
2. Convertc 3.21c xc10-
5ccc
=c negativec exponentc =csmallerc thanc1,c movec decimalc5cplacesc=c0.0000321
Question 2 c
Clickcthisc linkctoc accessc thec Periodic
ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
c Table.c Thisc maycbechelpfulc throughoutcthecexam.
Usingc thec followingc information,c doc thec conversionsc shownc below,c showingc allcwork:
1cftc=c12cinches 1cpoundc=c16coz 1cgallonc=c4cquarts
1cmilec=c5280cfeet 1ctonc=c2000cpounds 1cquartc=c2cpints
kiloc(=c1000)c millic(=c 1/1000)c centic(=
1/100) decic(=c1/10)
1. 24.6cgramsc=c?ckg
2. 6.3cftc=c?cinches
1.c 24.6cgramscxc1ckgc/c1000cgc=c0.0246ckg
2. 6.3c ftc xc 12c inc /c 1c ftc =c 75.6c inches
pleasec alwaysc usec thec correctc unitsc inc yourc finalc answer
,PortagecLearningc/cCHEMc103c/cModulec1ctoc6cExamcanswers
2
Question 3 c
,PortagecLearningc/cCHEMc103c/cModulec1ctoc6cExamcanswers
3
Clickc thisc linkc toc accessc thec Periodicc Table.c Thisc mayc bec helpfulc throughoutcthe
cexam.
Doc thecconversionsc showncbelow,c showingc allc work:
1.
28oCc=c ?coKc2
.
158oFc =c ?coCc
3. 343oKc =c ?coF
1. 28oCc+c273c =c301coK o
Cc→c oKc (makeclarger)
+273
2. 158oFc -c 32c ÷c1.8c =c70coC o
Fc →c oCc(makec smaller)
-32c÷1.8
3. 343oKc -c273c =c70coCc xc1.8c +c32c =c158c oF o
Kc →c oCc→c oF
Question 4 c
Clickcthisc linkctoc accessc thec Periodic
ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
c Table.c Thisc maycbechelpfulc throughoutcthecexam.
Bec surec toc showc thec correctc numberc ofc significantc figuresc inc eachc calculation.
1. Showctheccalculationcofcthecmasscofcac18.6cmlcsamplecofcfreoncwithcdensit
yc ofc1.49c g/ml
2. Showc thec calculationc ofc thec densityc ofc crudec oilc ifc 26.3c gc occupiesc 30.5cml
.
1. Mc=cDcxcVc=c1.49cxc18.6c=c27.7cg
2. Dc=cMc/cVc=c26.3c/c30.5c=c0.862cg/ml
Question 5 c
Clickcthisc linkctoc accessc thec Periodic
ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
c Table.c Thisc mayc bec helpfulc throughout cthecexam.
, PortagecLearningc/cCHEMc103c/cModulec1ctoc6cExamcanswers
4
1. 3.0600c containsc?c significantc figures.
1
MODULEc1cEXAM
Question 1 c
Clickcthisc linkctoc accessc thec Periodic
ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
c Table.c Thisc mayc bec helpfulc throughout cthecexam.
1. Convertc 845.3c toc exponentialc formc andc explainc yourc answer.
2. Convertc 3.21c xc10-5cc tocordinaryc formc andc explainc yourc answer.
1. Convertc845.3c=clargercthanc1c=cpositivecexponent,cmovecdecimalc2cplaces
=c8.453c xc102
2. Convertc 3.21c xc10-
5ccc
=c negativec exponentc =csmallerc thanc1,c movec decimalc5cplacesc=c0.0000321
Question 2 c
Clickcthisc linkctoc accessc thec Periodic
ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
c Table.c Thisc maycbechelpfulc throughoutcthecexam.
Usingc thec followingc information,c doc thec conversionsc shownc below,c showingc allcwork:
1cftc=c12cinches 1cpoundc=c16coz 1cgallonc=c4cquarts
1cmilec=c5280cfeet 1ctonc=c2000cpounds 1cquartc=c2cpints
kiloc(=c1000)c millic(=c 1/1000)c centic(=
1/100) decic(=c1/10)
1. 24.6cgramsc=c?ckg
2. 6.3cftc=c?cinches
1.c 24.6cgramscxc1ckgc/c1000cgc=c0.0246ckg
2. 6.3c ftc xc 12c inc /c 1c ftc =c 75.6c inches
pleasec alwaysc usec thec correctc unitsc inc yourc finalc answer
,PortagecLearningc/cCHEMc103c/cModulec1ctoc6cExamcanswers
2
Question 3 c
,PortagecLearningc/cCHEMc103c/cModulec1ctoc6cExamcanswers
3
Clickc thisc linkc toc accessc thec Periodicc Table.c Thisc mayc bec helpfulc throughoutcthe
cexam.
Doc thecconversionsc showncbelow,c showingc allc work:
1.
28oCc=c ?coKc2
.
158oFc =c ?coCc
3. 343oKc =c ?coF
1. 28oCc+c273c =c301coK o
Cc→c oKc (makeclarger)
+273
2. 158oFc -c 32c ÷c1.8c =c70coC o
Fc →c oCc(makec smaller)
-32c÷1.8
3. 343oKc -c273c =c70coCc xc1.8c +c32c =c158c oF o
Kc →c oCc→c oF
Question 4 c
Clickcthisc linkctoc accessc thec Periodic
ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
c Table.c Thisc maycbechelpfulc throughoutcthecexam.
Bec surec toc showc thec correctc numberc ofc significantc figuresc inc eachc calculation.
1. Showctheccalculationcofcthecmasscofcac18.6cmlcsamplecofcfreoncwithcdensit
yc ofc1.49c g/ml
2. Showc thec calculationc ofc thec densityc ofc crudec oilc ifc 26.3c gc occupiesc 30.5cml
.
1. Mc=cDcxcVc=c1.49cxc18.6c=c27.7cg
2. Dc=cMc/cVc=c26.3c/c30.5c=c0.862cg/ml
Question 5 c
Clickcthisc linkctoc accessc thec Periodic
ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
c Table.c Thisc mayc bec helpfulc throughout cthecexam.
, PortagecLearningc/cCHEMc103c/cModulec1ctoc6cExamcanswers
4
1. 3.0600c containsc?c significantc figures.
