NIMS-Job Planning, Benchwork, & Layout
Taper Per Inch (*TPI*) = - ANS- = (*D* - *d*) /*L*
*D*-Big diameter of taper
*d* -Small diameter of taper
*L* - Length of taper
Length of Taper *L* = - ANS- = (*D* - *d*) /*TPI*
Big diameter of taper *D* = - ANS- = (*TPI* x *L*) + *d*
Small Diameter of Taper *d* = - ANS- = *D* - (*TPI* x *L*)
Taper Per Foot *TPF* = - ANS- = [(*D* - *d*) /*L*] x 12
or
= *TPI* x 12
Included Angle of Taper = - ANS- = 2 x ArcTan (*TPF*/24)
or
= 2 x (Angle to center line)
Angle to Center line of Taper = - ANS- = ArcTan (*TPF*/24)
Referring to The Machinist's Handbook, what is the minimum pitch diameter for an
external thread 7/16-14 UNC - 2A?
A) 0.3862 inches
B) 0.3909 inches
C) 0.385 inches
D) 0.3876 inches - ANS- 0.385 inches
Applying the formula below, find the taper per foot for a workpiece with a large diameter
of 3.5 inches and a small diameter of 2.75 inches with a taper length of 5.5 inches. TPF=
[(D-d)/(Length of taper)] × 12
A) 3.5 inches
B) 1.64 inches
C) 3.27 inches
D) 1.75 inches - ANS- 1.64 inches
, Use a calculator to determine the included angle for a taper of 0.550 inches per foot.
A) 1.313 degrees
B) 2.614 degrees
C) 2.626 degrees
D) 5.248 degrees - ANS- 2.626 degrees
What is the taper per foot for a piece 7.5 inches long with a with 0.056 taper?
A) 0.0896 inch taper per foot
B) 0.1125 inch taper per foot
C) 5.0439 inch taper per foot
D) 0.0560 inch taper per foot - ANS- 0.0896 inch taper per foot
Referring to the Machinery's Handbook, what is the tap drill for a 5/16-18 UNC thread with
a 75% thread engagement?
A) 0.272-inch diameter drill
B) 0.257-inch diameter drill
C) 0.2983-inch diameter drill
D) 0.201-inch diameter drill - ANS- 0.257-inch diameter drill
The feed rate on a lathe is given in:
A) IPR
B) IPM
C) RPM
D) SFM - ANS- IPR
Calculate the rpm for a drilling operation with a cutting speed of 150 SFM applying a 1/4"
diameter drill with a feed rate of 0.005 inches per revolution.
A) 2400 RPM
B) 7500 RPM
C) 4800 RPM
D) 3750 RPM - ANS- 2400 RPM
The time required to make three turning passes over a piece of stainless steel 8.5 inches
in length at 350 rpm with a 0.006" feed is approximately ________ minutes.
A) 26.7 minutes
B) 12.1 minutes
C) 10.7 minutes
D) 4.1 minutes - ANS- 12.1 minutes
Taper Per Inch (*TPI*) = - ANS- = (*D* - *d*) /*L*
*D*-Big diameter of taper
*d* -Small diameter of taper
*L* - Length of taper
Length of Taper *L* = - ANS- = (*D* - *d*) /*TPI*
Big diameter of taper *D* = - ANS- = (*TPI* x *L*) + *d*
Small Diameter of Taper *d* = - ANS- = *D* - (*TPI* x *L*)
Taper Per Foot *TPF* = - ANS- = [(*D* - *d*) /*L*] x 12
or
= *TPI* x 12
Included Angle of Taper = - ANS- = 2 x ArcTan (*TPF*/24)
or
= 2 x (Angle to center line)
Angle to Center line of Taper = - ANS- = ArcTan (*TPF*/24)
Referring to The Machinist's Handbook, what is the minimum pitch diameter for an
external thread 7/16-14 UNC - 2A?
A) 0.3862 inches
B) 0.3909 inches
C) 0.385 inches
D) 0.3876 inches - ANS- 0.385 inches
Applying the formula below, find the taper per foot for a workpiece with a large diameter
of 3.5 inches and a small diameter of 2.75 inches with a taper length of 5.5 inches. TPF=
[(D-d)/(Length of taper)] × 12
A) 3.5 inches
B) 1.64 inches
C) 3.27 inches
D) 1.75 inches - ANS- 1.64 inches
, Use a calculator to determine the included angle for a taper of 0.550 inches per foot.
A) 1.313 degrees
B) 2.614 degrees
C) 2.626 degrees
D) 5.248 degrees - ANS- 2.626 degrees
What is the taper per foot for a piece 7.5 inches long with a with 0.056 taper?
A) 0.0896 inch taper per foot
B) 0.1125 inch taper per foot
C) 5.0439 inch taper per foot
D) 0.0560 inch taper per foot - ANS- 0.0896 inch taper per foot
Referring to the Machinery's Handbook, what is the tap drill for a 5/16-18 UNC thread with
a 75% thread engagement?
A) 0.272-inch diameter drill
B) 0.257-inch diameter drill
C) 0.2983-inch diameter drill
D) 0.201-inch diameter drill - ANS- 0.257-inch diameter drill
The feed rate on a lathe is given in:
A) IPR
B) IPM
C) RPM
D) SFM - ANS- IPR
Calculate the rpm for a drilling operation with a cutting speed of 150 SFM applying a 1/4"
diameter drill with a feed rate of 0.005 inches per revolution.
A) 2400 RPM
B) 7500 RPM
C) 4800 RPM
D) 3750 RPM - ANS- 2400 RPM
The time required to make three turning passes over a piece of stainless steel 8.5 inches
in length at 350 rpm with a 0.006" feed is approximately ________ minutes.
A) 26.7 minutes
B) 12.1 minutes
C) 10.7 minutes
D) 4.1 minutes - ANS- 12.1 minutes
