INTRODUCTION TO M b b
ECHATRONICSAND M b b
EASUREMENT
SYSTEMS
4th edition
b
b2012(c)
SOLUTIONS MANUAL b
David G. Alciatore an
b b b
d
Michael B. Histand b b
Department of Mechanical Engineering Colorad
b b b b
o State University
b b
Fort Collins, CO 80523
b b b
IntroductionbtobMechatronicsbandbMeasurementbSystems 1
,SolutionsbManual
Thisbmanualbcontainsbsolutionsbtobthebend-of-
chapterbproblemsbinbthebthirdbeditionbofb"IntroductionbtobMechatronicsbandbMeasurementbSystems.
"b Onlybabfewbofbthebopen-
endedbproblemsbthatbdobnotbhavebabuniquebanswerbarebleftbforbyourbcreativebsolutions.b Morebinforma
tion,bincludingbanbexamplebcourseboutline,babsuggestedblaboratorybsyllabus,bMathCADbfilesbforbexam
plesbinbthebbook,bandbotherbsupplementalbmaterialbarebprovidedbonbthebInternetbat:
mechatronics.colostate.edu
Webhavebclass-
testedbthebtextbookbforbseveralbyears,bandbitbshouldbbebrelativelybfreebfromberrors.b However,bifbyoub
noticebanyberrorsborbhavebsuggestionsborbadvicebconcerningbthebtextbook'sbcontentborbapproach,bplea
sebfeelbfreebtobcontactbusbviabe-
te.
Thankbyoubforbchoosingbourbbook.b Webhopebitbhelpsbyoubprovidebyourbstudentsbwithbanbenj
oyablebandbfruitfulblearningbexperiencebinbthebcross-disciplinarybsubjectbofbmechatronics.
2 IntroductionbtobMechatronicsbandbMeasurementbSystems
,SolutionsbManual
2.1 Db=b0.06408binb=b0.001628bm.
2
D - =b 2.082bb10–6
Ab =b ---------
4
b=b1.7bxb10-8b m, Lb=b1000bm
Rb =b -- -L
-- =b 8.2
A
2.2
(a) R1b = 21bb104bb20% sob 168kbbR1bb252kb
(b) R2b = 07bb103bb20% so 5.6kbbR2bb8.4k
(c) Rsb = R1b +bR2b = 217kb b 20% sob 174kbbRsb b260k
Rb1R b b 2
(d) Rpb = ------------------
bR
1b +b R
2
R1 R2
Rp = ----------M--I-N--------M--I--N--- =b 5.43k
MIN R1 +bR
MIN 2 MIN
R1 R2
Rp = ----------M--A---X---------M--A--X---- =b 8.14k
MAX R1 +bR
MAX 2 MAX
2.3 R1b = 10bb102b, R2b = 25bb101
R1R2 (10b b 102)(25b b 101) 1
Rb = = = 20bb10
R1b +bR2 10bb102b+b25bb101
ab=b2b=bred,b bb=b0b=bblack,b cb=b1b=bbrown,b db=bgold
2.4 Inbseries,bthebtrimbpotbwillbaddbanbadjustablebvaluebrangingbfromb0btobitsbmaximumbvaluebtobt
heboriginalbresistorbvaluebdependingbonbthebtrimbsetting.b Whenbinbparallel,bthebtrimbpotbcoul
dbbeb0bperhapsbcausingbabshort.b Furthermore,bthebtrimbvaluebwillbnotbbebadditivebwithbthebfi
xedbresistor.
2.5 Whenbtheblastbconnectionbisbmade,babsparkboccursbatbthebpointbofbconnectionbasbthebcomplete
dbcircuitbisbformed.b Thisbsparkbcouldbignitebgasesbproducedbinbthebbattery.b Thebnegativebter
minalbofbthebbatterybisbconnectedbtobthebframebofbthebcar,bwhichbservesbasbabgroundbreference
bthroughout bthebvehicle.
IntroductionbtobMechatronicsbandbMeasurementbSystems 3
, SolutionsbManual
2.6 No,basblongbasbyoubarebconsistentbinbyourbapplication,byoubwillbobtainbcorrectbanswers.b Ifbyo
ubassumebthebwrongbcurrentbdirection,bthebresultbwillbbebnegative.
2.7 Placebtwob100bresistorsbinbparallelbandbyoubimmediatelybhavebab50bresistance.
2.8 FrombKCL, Isb = I1b +bI2b +b I3
Vs Vs Vs Vs
sobfrombOhm’sbLaw -------- b =b -----
-b+b------b +b------
Req R1 R2 R3
Therefore,b --- ---- =b ----b+b----b+b--1-- sob R
1 1 1 R1R2R3
eqb = ----------------------------------------------------
Req R1 R2 R3 bR R
2 3b +b R1R3b +b R1R2
2.9 Is Is
FrombOhm’sbLawbandbQuestionb2.8,b Vb = ------= ----------------------------------------------------
Req bR R
2 3b +b R1R3b +b R1R2
R 1 R2 R3
andbforbonebresistor,b V =b I1R1
R2R3
Therefore,b I1b = Is
R b2R b +bRb R b +bRb R b b
b b 3 1b b 3 1b b 2
b R1R2b R1R2
2.10 lim ------------------ =b ------------ =b R2
R1b →b bR1b +bR R
1
2
dV dV dV
2.11 Ib =b C eqb------ =b Cb 1---------1 =b Cb2---------2
dt dt dt
FrombKVL,
Vb =b V1b +bV2
so
dV dV1 dV2
-------b =b ---------b+b---------
dt dt dt
Therefore,
----I---- =b ---I---b+b---I--- sobb ---1b --- = --1--b+b --1-- orb C C1C2
eqb = ------------------
Ceq C1 C2 Ceq C1 C2 bC
1b +bC
2
4 IntroductionbtobMechatronicsbandbMeasurementbSystems