INMO BASIC PRACTICE SHEET

1




MOBP-2025
Basic Inequalities DPP-01

1. If we multiply whole inequality by a negative 1
6. Solution of inequality  3 is
number then x −5
(A) sign of inequality remains same. (A) x (–, 5)
(B) sign of inequality gets reversed.  16 
(B) x   ,  
(C) depends, which negative number is multiplied. 3 
(D) depends, both side of inequality are positive or  16 
(C) x   5, 
negative.  3
 16 
2. If    then (D) x  ( −,5)   ,  
3 
(A) 2  3
(B)   – 7. Solution of inequality (x2 – 12x + 35) < 0
(C) 2 > 2 (A) x  (5, 7) (B) x  [5, 7)
(D) –  – (C) x  (5, 7] (D) x  [5, 7]


3. Correct option represents x2 + x − 2
8. Values of ‘x’ satisfying : 0
x2 − x − 12
3 4 5 9 11 (A) x (–, −3]  [−2,1]  [4, )
(A) x  (3, 5]  [9, 11) (B) x (–, −3)  [−2,1]  (4, )
(B) x  (3, 5]  [9, 11) – {4} (C) x (–3,4)
(C) x  (3, 4)  (4, 5)  [3, 11) (D) x (–3, –2]  (4, )
(D) x  (3, 4)  (4, 5]  (9, 11)
9. Values of ‘x’ satisfying both inequalities:
x −8 x −5
4. Solution of inequality : 5 x–34& 0
2 x +1
(A) x < 2 (B) x  18 (A) x  (–, 7]
(C) x  18 (D) x  2 (B) x  (–, –1)
(C) x  (–, –1)  (5, 7]
x −1 (D) x  (5, 7]
5. Values of ‘x’ satisfying : 0
2− x
10. Largest integral value of x satisfying:
(A) x  [1, 2]
x2 − 9
(B) x  [1, 2) 0
( x − 1)( x − 6)
(C) x  (–, 1]  (2, )
(A) 5 (B) 3
(D) x  (1, 2)
(C) 4 (D) 6