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Summary - Mathematics, physics and chemistry formulas all in one

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For IIT JEE, mastering formulas in Mathematics, Physics, and Chemistry is crucial. Key formulas include Quadratic Equation in Maths, Newton’s Laws in Physics, and Mole Concept in Chemistry. Strong conceptual understanding and practice are essential for success.

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IIT JEE Formulas

Maths Formulas

Part 1

Circle Formula
The formula for circle are as stated below

Description Formula
2
Area of a Circle ● In terms of radius: π𝑟
π 2
● In terms of diameter: 4
×𝑑


Surface Area of a Circle 2
π𝑟

General Equation of a The general equation of a circle with coordinates of a centre(ℎ, 𝑘),
Circle 2 2
and radius 𝑟 is given as: (𝑥 − ℎ) + (𝑦 − 𝑘) = 𝑟
Standard Equation of a The Standard equation of a circle with centre (𝑎, 𝑏), and radius 𝑟 is
Circle 2 2 2
given as: (𝑥 − 𝑎) + (𝑦 − 𝑏) = 𝑟
Diameter of a Circle 2 × radius

Circumference of a Circle 2π𝑟
Intercepts made by Circle 𝑥2 + 𝑦2 + 2𝑔𝑥 + 2𝑓𝑦 + 𝑐 = 0
2
i. On 𝑥 −axis: 2 𝑔 − 𝑐
2
ii. On 𝑦 −axis: 2 𝑓 − 𝑐

Parametric Equations of 𝑥 = ℎ + 𝑟𝑐𝑜𝑠 θ ; 𝑦 = 𝑘 + 𝑟𝑠𝑖𝑛 θ
a Circle
Tangent 2
● Slope form: 𝑦 = 𝑚𝑥±𝑎 1 + 𝑚
2
● Point form: 𝑥𝑥1 + 𝑦𝑦1 = 𝑎 or 𝑇 = 0
● Parametric form: 𝑥𝑐𝑜𝑠 α + 𝑦𝑠𝑖𝑛 α = 𝑎

Pair of Tangents from a 2
𝑆𝑆1 = 𝑇
Point:

,Length of a Tangent 𝑆1

Director Circle 2 2 2 2 2 2
𝑥 + 𝑦 = 2𝑎 for 𝑥 + 𝑦 = 𝑎

Chord of Contact 𝑇=0
2𝐿𝑅
i. Length of chord of contact= 2 2
𝑅 +𝐿
ii. Area of the triangle formed by the pair of the
3
𝑅𝐿
tangents and its chord of contact = 2 2
𝑅 +𝐿
iii. Tangent of the angle between the pair of tangents
(
from 𝑥1, 𝑦1 = ) ( )
𝐿 −𝑅
2𝑅𝐿
2 2


iv. Equation of the circle circumscribing the triangle
𝑃𝑇1, 𝑇2 is:
(𝑥 − 𝑥1)(𝑥 + 𝑔) + (𝑦 − 𝑦1)(𝑦 + 𝑓) = 0
Condition of 2𝑔1𝑔2 + 2𝑓1𝑓2 = 𝑐1 + 𝑐2
orthogonality of Two
Circles
Radical Axis ( )
𝑆1 − 𝑆2 = 0 i.e. 2 𝑔1 − 𝑔2 𝑥 + 2 𝑓1 − 𝑓2 𝑦 + 𝑐1 − 𝑐2 = 0. ( ) ( )
Family of Circles 𝑆1 + 𝐾𝑆2 = 0, 𝑆 + 𝐾𝐿 = 0


Quadratic Equation Formula
The formula for quadratic equation are as stated below

Description Formula
General form of 2
𝑎𝑥 + 𝑏𝑥 + 𝑐 = 0; where 𝑎, 𝑏, 𝑐 are constants and 𝑎≠0.
Quadratic Equation
Roots of equations −𝑏+ 𝑏 −4𝑎𝑐
2 2
−𝑏− 𝑏 −4𝑎𝑐
α= 2𝑎
, β= 2𝑎
Sum and Product of If α and β are the roots of the quadratic equation
Roots 2
𝑎𝑥 + 𝑏𝑥 + 𝑐 = 0, then
𝑏
Sum of roots, α + β =− 𝑎
𝑐
Product of roots, αβ = 𝑎


Discriminant of 2
The Discriminant of the quadratic equation 𝑎𝑥 + 𝑏𝑥 + 𝑐 = 0 is
Quadratic equation 2
given by 𝐷 = 𝑏 − 4𝑎𝑐.

Nature of Roots 𝑏
● If 𝐷 = 0, the roots are real and equalα = β =− 2𝑎
.

, ● If 𝐷≠0, The roots are real and unequal.
● If 𝐷 < 0, the roots are imaginary and unequal.
● If 𝐷 > 0 and D is a perfect square, the roots are rational
and unequal.
● If 𝐷 > 0 and 𝐷 is not a perfect square, the roots are
irrational and unequal.

Formation of Quadratic If α and β are the roots of the quadratic equation, then
Equation with given 2
(𝑥 − α)(𝑥 − β) = 0; 𝑥 − (α + β)𝑥 + αβ = 0;
roots 2
● 𝑥 − (𝑆𝑢𝑚 𝑜𝑓 𝑟𝑜𝑜𝑡𝑠)𝑥+ 𝑝𝑟𝑜𝑑𝑢𝑐𝑡 𝑜𝑓 𝑟𝑜𝑜𝑡s=0
Common Roots 2
● If two quadratic equations 𝑎1𝑥 + 𝑏1𝑥 + 𝑐1 = 0 &
2
𝑎2𝑥 + 𝑏2𝑥 + 𝑐2 = 0 have both roots common, then
𝑎1 𝑏1 𝑐1
𝑎2
= 𝑏2
= 𝑐2
.
● If only one root α is common, then
𝑐1𝑎2−𝑐2𝑎1 𝑏1𝑐2−𝑏2𝑐1
α= 𝑎1𝑏2−𝑎2𝑏1
= 𝑐1𝑎2−𝑐2𝑎1


Range of Quadratic 𝑏
● If − 2𝑎
not belong to [𝑥1, 𝑥2] then,
Expression
2
𝑓(𝑥) = 𝑎𝑥 + 𝑏𝑥 + 𝑐 in
[{ ( ) }
𝑓(𝑥)∈ 𝑓 𝑥1 , 𝑓(𝑥2) , 𝑚𝑎𝑥⁡{𝑓 𝑥1 , 𝑓(𝑥2)} ( ) ]
𝑏
restricted domain ● If− 2𝑎
∈[𝑥1, 𝑥2] then,
𝑥∈[𝑥1, 𝑥2]
{( ) ( )
𝑓(𝑥)∈⎡⎢ 𝑓 𝑥1 , 𝑓 𝑥2 , −

𝐷
4𝑎 }, ( ) ( )
𝑚𝑎𝑥⁡{𝑓 𝑥1 , 𝑓 𝑥2 , −
𝐷
4𝑎
}⎤⎥

2
Consider the quadratic equation 𝑎𝑥 + 𝑏𝑥 + 𝑐 = 0
Roots under special 𝑏
● If 𝑐 = 0, then one root is zero. Other root is− 𝑎
.
cases
● If 𝑏 = 0The roots are equal but in opposite signs.
● If 𝑏 = 𝑐 = 0, then both roots are zero.
● If 𝑎 = 𝑐, then the roots are reciprocal to each other.
● If 𝑎 + 𝑏 + 𝑐 = 0, then one root is 1 and the second root is
𝑐
𝑎
.
● If 𝑎 = 𝑏 = 𝑐 = 0, then the equation will become an
identity and will satisfy every value of 𝑥.

Graph of Quadratic 2
The graph of a quadratic equation 𝑎𝑥 + 𝑏𝑥 + 𝑐 = 0 is a
equation parabola.
● If 𝑎 > 0, then the graph of a quadratic equation will be
concave upwards.
● If 𝑎 < 0, then the graph of a quadratic equation will be
concave downwards.

, Maximum and Minimum 2
Consider the quadratic expression 𝑎𝑥 + 𝑏𝑥 + 𝑐 = 0
value ● If 𝑎 < 0, then the expression has the greatest value at
𝑏 𝐷
𝑥 =− 2𝑎 . The maximum value is − 4𝑎 .
● If 𝑎 > 0, then the expression has the least value at
𝑏 𝐷
𝑥 =− 2𝑎 . The minimum value is − 4𝑎 .

Quadratic Expression in The general form of a quadratic equation in two variables 𝑥 and 𝑦 is
Two Variables 2 2
𝑎𝑥 + 2ℎ𝑥𝑦 + 𝑏𝑦 + 2𝑔𝑥 + 2𝑓𝑦 + 𝑐.
To solve the expression into two linear rational factors, the
condition is ∆ = 0
[a h g]
∆= [ h b f ] =0
[g f c]

2 2 2 2
𝑎𝑏𝑐 + 2𝑓𝑔ℎ − 𝑎𝑓 − 𝑏𝑔 − 𝑐ℎ = 0 And ℎ − 𝑎𝑏 > 0. This is
called the Discriminant of the given expression.


Binomial Theorem Formula
Quick formula revision for jee mains and advanced.


Description Formula
Binomial Theorem for 𝑛 𝑛
(𝑥 + 𝑎) =nC0𝑥𝑛𝑎0 + nC1𝑥𝑛−1𝑎 + nC2𝑥𝑛−2𝑎2 + … + nCr𝑥𝑛−𝑟𝑎𝑟 + … + nCn.𝑥𝑎
positive Integral Index General terms = 𝑇𝑟+1 =nCr𝑥𝑛−𝑟𝑎𝑟


Deductions of Binomial 𝑛
● (1 + 𝑥) =nC0+ nC1𝑥 + nC2𝑥2 +nC3𝑥3 + … +nCr𝑥𝑟 + … +nCn𝑥𝑛 which is
Theorem the standard form of binomial expansion.
𝑡ℎ
General Term= (𝑟 + 1) term: 𝑇𝑟+1 =nCr
𝑟 𝑛(𝑛−1)(𝑛−2)……(𝑛−𝑟+1) 𝑟
𝑥 = 𝑟!
.𝑥


● 𝑛 n n
C n
C2 n 3 C
(1 − 𝑥) = 0− 1𝑥 + 2𝑥 − 3𝑥 + … + (− 1)
𝑟nC 𝑟
r𝑥 + … + (− 1)
𝑛n
n𝑥
𝑛C C
𝑡ℎ 𝑟n
General Term= (𝑟 + 1) term: 𝑇𝑟+1 = (− 1) . Cr
𝑟 𝑛(𝑛−1)(𝑛−2)……(𝑛−𝑟+1) 𝑟
𝑥 = 𝑟!
.𝑥



Middle Term in the 𝑡ℎ

expansion of(𝑥 + 𝑎)
𝑛 ● If 𝑛 is even then middle term = ( + 1) term. 𝑛
2
𝑛+1 𝑡ℎ 𝑛+3 𝑡ℎ
● If 𝑛 is odd then middle terms are ( ) and ( ) 2 2
term.
● Binomial coefficients of middle term is the greatest Binomial
coefficients

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