Chapter n 1: MEASUREMENT
1. The nSInstandard nofntime nis nbased non:
A. the ndailynrotationnofnthe nearth
B. the nfrequencynofnlightnemitted nbynKr86
C. the nyearlynrevolutionnofnthe nearthnaboutnthe nsun
D. anprecisionnpendulum nclock
E. none nofnthese
nAns: n E
2. Annanosecond nis:
A. 109ns
B. 10−9ns
C. 10−10 n s
D. 10−10 n s
E. 10−12
Ans:n B
3. The nSInstandard nofnlengthnis nbased non:
A. the ndistance nfrom nthe nnorthnpole ntonthe nequatornalong na nmeridiannpassing nthroughnParis
B. wavelength nofnlightnemitted nbynHg198
C. wavelength nofnlightnemitted nbynKr86
D. anprecisionnmeternstickninnParis
E. the nspeed nofnligh
tnAns:n E
4. Inn1866,nthe nU.nS.nCongressndefinednthenU.nS.nyardnas nexactlyn3600/3937n internationalnmeter
.nThis nwas ndone nprimarilynbecause:
A. lengthncannbe nmeasured nmore naccuratelyninnmeters nthanninnyards
B. the nmeternis nmore nstable nthannthe nyard
C. this ndefinitionnrelates nthe ncommonnU.nS.nlengthnunits ntona nmore nwidelynused nsystem
D. there nare nmore nwavelengths ninna nyardnthanninna nmeter
E. the nmembers nofnthis nCongressnwerenexceptionallynintelligen
tnAns:n C
5. Whichnofnthe nfollowing nis nclosestntona nyardninnlength?
A. 0.01nm
B. 0.1m n
C. 1nm
D. 100nm
E. 1000nm
Ans:n C
Chaptern1: MEASUREMENT 1
, 6. There nis nnonSInbase nunitnfornarea nbecause:
A. annarea nhas nnonthickness; nhence nnonphysicalnstandard ncannbe nbuilt
B. we nlive ninnanthree n(notnantwo)ndimensionalnworld
C. itnis nimpossible ntonexpress nsquare nfeetninnterms nofnmeters
D. area ncannbe nexpressed ninnterms nofnsquare nmeters
E. area nis nnotnannimportantnphysicalnquantit
ynAns:n D
7. The nSInbase nunitnfornmass nis:
A. gram
B. pound
C. kilogram
D. ounce
E. kilopound
nAns: n C
8. An gram n is:
A. 10−6n kg
B. 10−3n kg
C. 1n kg
D. 103n kg
E. 106n kg
Ans:n B
9. Whichnofnthe nfollowing nweighs naboutnanpound?
A. 0.05n kg
B. 0.5nkg
C. 5n kg
D. 50nkg
E. 500nkg
Ans:n D
10. (5.0n ×n 104)n ×n (3.0n ×n 106)n =n
A. 1.5n×n109
B. 1.5n×n1010
C. 1.5n×n1011
D. 1.5n×n1012
E. 1.5n×n1013
Ans:n C
11. (5.0n ×n 104)n ×n (3.0n ×n 10−6)n =n
A. 1.5n×n10−3
B. 1.5n×n10−1
C. 1.5n×n101
D. 1.5n×n103
E. 1.5n×n105
Ans:n B
2 Chaptern1: MEASUREMENT
,12. 5.0n×n105n +n3.0n×n106n =
A. 8.0n×n105
B. 8.0n×n106
C. 5.3n×n105
D. 3.5n×n105
E. 3.5n×n106
Ans:n E
13. (7.0n ×n 106)/(2.0n ×n 10−6)n =n
A. 3.5n×n10 −1 2
B. 3.5n×n10− 6
C. 3.5
D. 3.5n×n106
E. 3.5n×n1012
Ans:n E
14. The nnumbernofnsignificantnfigures ninn0.00150nis:
A.n n 2
B.n n 3
C.n n 4
D.n n 5
E.n n 6
Ans:n B
15. The nnumbernofnsignificantnfigures ninn15.0nis:
A.n n 1
B.n n 2
C.n n 3
D.n n 4
E.n n 5
Ans:n C
16. 3.2n ×n 2.7 n =n
A. 9
B. 8
C. 8.6
D. 8.64
E. 8.640
Ans:n C
Chaptern1: MEASUREMENT 3
, 17. 1.513n+n27.3n=n
A. 29
B. 28.8
C. 28.9
D. 28.81
E. 28.813
( )Ans:n B
18. 1nminis nequivalentnton1609 nm nson55nmphnis:
A. 15n m/s
B. 25nm/s
C. 66 nm/s
D. 88nm/s
E. 1500nm/s
nAns: n B
19. Ansphere nwithnanradius nofn1.7 ncm nhas nanvolume nof:
A. 2.1n×n10 − 5n m 3
B. 9.1n×n10 − 4 n m 3
C. 3.6 n×n10 −3 nm 3
D. 0.11nm 3
E. 21n m 3
Ans:n A
20. Ansphere nwithnanradius nofn1.7 ncm nhas nansurface narea nof:
A. 2.1n×n10 − 5n m 2
B. 9.1n×n10 − 4 n m 2
C. 3.6 n×n10 −3 nm 2
D. 0.11nm 2
E. 36 nm 2
Ans:n C
21. Anrightncircularncylindernwithnanradius nofn2.3ncm nand na nheightnofn1.4 nm nhas na nvolume nof:
A. 0.20nm 3
B. 0.14 nm 3
C. 9.3n×n10 −3 nm 3
D. 2.3n×n10 − 3 nm 3
E. 7.4 n×n10− 4n m 3
Ans:n D
22. Anrightncircularncylindernwithnanradiusnofn2.3ncmnandnanheightnofn1.4 ncmnhasnantotalnsurfacenare
anof:
A. 1.7 n×n10 −3 n m 2
B. 3.2n×n10 − 3 nm 2
C. 2.0n×n10−3n m 3
D. 5.3n×n10 − 3n m 2
E. 7.4 n×n10−3 n m 2
Ans:n D
4 Chaptern1: MEASUREMENT
1. The nSInstandard nofntime nis nbased non:
A. the ndailynrotationnofnthe nearth
B. the nfrequencynofnlightnemitted nbynKr86
C. the nyearlynrevolutionnofnthe nearthnaboutnthe nsun
D. anprecisionnpendulum nclock
E. none nofnthese
nAns: n E
2. Annanosecond nis:
A. 109ns
B. 10−9ns
C. 10−10 n s
D. 10−10 n s
E. 10−12
Ans:n B
3. The nSInstandard nofnlengthnis nbased non:
A. the ndistance nfrom nthe nnorthnpole ntonthe nequatornalong na nmeridiannpassing nthroughnParis
B. wavelength nofnlightnemitted nbynHg198
C. wavelength nofnlightnemitted nbynKr86
D. anprecisionnmeternstickninnParis
E. the nspeed nofnligh
tnAns:n E
4. Inn1866,nthe nU.nS.nCongressndefinednthenU.nS.nyardnas nexactlyn3600/3937n internationalnmeter
.nThis nwas ndone nprimarilynbecause:
A. lengthncannbe nmeasured nmore naccuratelyninnmeters nthanninnyards
B. the nmeternis nmore nstable nthannthe nyard
C. this ndefinitionnrelates nthe ncommonnU.nS.nlengthnunits ntona nmore nwidelynused nsystem
D. there nare nmore nwavelengths ninna nyardnthanninna nmeter
E. the nmembers nofnthis nCongressnwerenexceptionallynintelligen
tnAns:n C
5. Whichnofnthe nfollowing nis nclosestntona nyardninnlength?
A. 0.01nm
B. 0.1m n
C. 1nm
D. 100nm
E. 1000nm
Ans:n C
Chaptern1: MEASUREMENT 1
, 6. There nis nnonSInbase nunitnfornarea nbecause:
A. annarea nhas nnonthickness; nhence nnonphysicalnstandard ncannbe nbuilt
B. we nlive ninnanthree n(notnantwo)ndimensionalnworld
C. itnis nimpossible ntonexpress nsquare nfeetninnterms nofnmeters
D. area ncannbe nexpressed ninnterms nofnsquare nmeters
E. area nis nnotnannimportantnphysicalnquantit
ynAns:n D
7. The nSInbase nunitnfornmass nis:
A. gram
B. pound
C. kilogram
D. ounce
E. kilopound
nAns: n C
8. An gram n is:
A. 10−6n kg
B. 10−3n kg
C. 1n kg
D. 103n kg
E. 106n kg
Ans:n B
9. Whichnofnthe nfollowing nweighs naboutnanpound?
A. 0.05n kg
B. 0.5nkg
C. 5n kg
D. 50nkg
E. 500nkg
Ans:n D
10. (5.0n ×n 104)n ×n (3.0n ×n 106)n =n
A. 1.5n×n109
B. 1.5n×n1010
C. 1.5n×n1011
D. 1.5n×n1012
E. 1.5n×n1013
Ans:n C
11. (5.0n ×n 104)n ×n (3.0n ×n 10−6)n =n
A. 1.5n×n10−3
B. 1.5n×n10−1
C. 1.5n×n101
D. 1.5n×n103
E. 1.5n×n105
Ans:n B
2 Chaptern1: MEASUREMENT
,12. 5.0n×n105n +n3.0n×n106n =
A. 8.0n×n105
B. 8.0n×n106
C. 5.3n×n105
D. 3.5n×n105
E. 3.5n×n106
Ans:n E
13. (7.0n ×n 106)/(2.0n ×n 10−6)n =n
A. 3.5n×n10 −1 2
B. 3.5n×n10− 6
C. 3.5
D. 3.5n×n106
E. 3.5n×n1012
Ans:n E
14. The nnumbernofnsignificantnfigures ninn0.00150nis:
A.n n 2
B.n n 3
C.n n 4
D.n n 5
E.n n 6
Ans:n B
15. The nnumbernofnsignificantnfigures ninn15.0nis:
A.n n 1
B.n n 2
C.n n 3
D.n n 4
E.n n 5
Ans:n C
16. 3.2n ×n 2.7 n =n
A. 9
B. 8
C. 8.6
D. 8.64
E. 8.640
Ans:n C
Chaptern1: MEASUREMENT 3
, 17. 1.513n+n27.3n=n
A. 29
B. 28.8
C. 28.9
D. 28.81
E. 28.813
( )Ans:n B
18. 1nminis nequivalentnton1609 nm nson55nmphnis:
A. 15n m/s
B. 25nm/s
C. 66 nm/s
D. 88nm/s
E. 1500nm/s
nAns: n B
19. Ansphere nwithnanradius nofn1.7 ncm nhas nanvolume nof:
A. 2.1n×n10 − 5n m 3
B. 9.1n×n10 − 4 n m 3
C. 3.6 n×n10 −3 nm 3
D. 0.11nm 3
E. 21n m 3
Ans:n A
20. Ansphere nwithnanradius nofn1.7 ncm nhas nansurface narea nof:
A. 2.1n×n10 − 5n m 2
B. 9.1n×n10 − 4 n m 2
C. 3.6 n×n10 −3 nm 2
D. 0.11nm 2
E. 36 nm 2
Ans:n C
21. Anrightncircularncylindernwithnanradius nofn2.3ncm nand na nheightnofn1.4 nm nhas na nvolume nof:
A. 0.20nm 3
B. 0.14 nm 3
C. 9.3n×n10 −3 nm 3
D. 2.3n×n10 − 3 nm 3
E. 7.4 n×n10− 4n m 3
Ans:n D
22. Anrightncircularncylindernwithnanradiusnofn2.3ncmnandnanheightnofn1.4 ncmnhasnantotalnsurfacenare
anof:
A. 1.7 n×n10 −3 n m 2
B. 3.2n×n10 − 3 nm 2
C. 2.0n×n10−3n m 3
D. 5.3n×n10 − 3n m 2
E. 7.4 n×n10−3 n m 2
Ans:n D
4 Chaptern1: MEASUREMENT
