EASY WAYS TO SOLVE
MATHEMATIC PROBLEM
QUICK COUNT
17 21 33 17 54 33
1. If P = 19 + 24 + 36 , then Q = 19 + 36 + 24 . So…
Answer
First, we sort denominators of numbers to make two
equations same as another
17 21 33
P= 19 + 24 + 36
17 33 54
Q = 19 + 24 + 36
After that, we know that numerators of Q is bigger than P
So, we can decide that P<Q
2.
1
8 + ( 18 : 18 ) + 18 =
Answer
1
Take a look at 8 + 8 : 8 + 8 = (1 1) 1
Because two fractional numbers inside the bracket are the same,
so the result is always 1.
Two fractional numbers outside the bracket are also the same, we
can change form equation
1 1 1 2
8
+ 8 → 2x 8
→ 8
So The Final Result is
2 2
1 + 8 = 18
3. `(12x30)2 − (118+241)2 =
Answer
(12x30)2 − (118+241)2 =(360)2 − (359)
Use this principle
a2 − b2 = (a+b)(a-b)
(360)2 − (359)2 = (360+359)(360−359)
= (719)(1)
MATHEMATIC PROBLEM
QUICK COUNT
17 21 33 17 54 33
1. If P = 19 + 24 + 36 , then Q = 19 + 36 + 24 . So…
Answer
First, we sort denominators of numbers to make two
equations same as another
17 21 33
P= 19 + 24 + 36
17 33 54
Q = 19 + 24 + 36
After that, we know that numerators of Q is bigger than P
So, we can decide that P<Q
2.
1
8 + ( 18 : 18 ) + 18 =
Answer
1
Take a look at 8 + 8 : 8 + 8 = (1 1) 1
Because two fractional numbers inside the bracket are the same,
so the result is always 1.
Two fractional numbers outside the bracket are also the same, we
can change form equation
1 1 1 2
8
+ 8 → 2x 8
→ 8
So The Final Result is
2 2
1 + 8 = 18
3. `(12x30)2 − (118+241)2 =
Answer
(12x30)2 − (118+241)2 =(360)2 − (359)
Use this principle
a2 − b2 = (a+b)(a-b)
(360)2 − (359)2 = (360+359)(360−359)
= (719)(1)
