Written by students who passed Immediately available after payment Read online or as PDF Wrong document? Swap it for free 4.6 TrustPilot
logo-home
Class notes

maths

Rating
-
Sold
-
Pages
8
Uploaded on
01-04-2025
Written in
2024/2025

Lecture notes of 8 pages for the course mathematics science at Fifth year / 11th Grade (schol)

Institution
Course

Content preview

LINEAR INEQUALITIES
MAIN CONCEPTS AND RESULTS
* Two real numbers or two algebraic expressions related by the symbol „<‟, „>‟, „≤‟ or „≥‟ form an
inequality.
* Numerical inequalities : 3 < 5; 7 > 5
* Literal inequalities : x < 5; y > 2; x ≥ 3, y ≤ 4
* Double inequalities : 3<5<7 ,2<y<4
* Strict inequalities : ax + b < 0 , ax + b > 0, ax2 + bx + c > 0
* Slack inequalities : ax + by ≤ c , ax + by ≥ c , ax2 + bx + c ≤ 0
* Linear inequalities : ax + b < 0, ax + b ≥ 0
* Quadratic inequalities : ax2 + bx + c > 0, ax2 + bx + c ≤ 0
** Algebraic Solutions of Linear Inequalities in One Variable and their Graphical
Representation




** Graph of system of linear inequalities, 2x - 6y < 12, 3x + 4y < 12 and 4x + 2y ≥ 8.




**Graph the system of linear inequalities. 2x - 3y < 6 , - x + y ≤ 4 , 2x + 4y < 8




36

, II. Some Illustrations/ Examples with solutions
1. The length of a rectangle is three times the breadth. If the minimum perimeter of the
rectangle is 160 cm, then

(a) breadth > 20 cm (b) length < 20 cm (c) breadth x ≥ 20 cm (d) length ≤ 20 cm

Correct option: (c) breadth x ≥ 20 cm

Solution:

Let x be the breadth of a rectangle.

So, length = 3x

Given that the minimum perimeter of a rectangle is 160 cm.

Thus, 2 (3x + x) ≥ 160

⇒ 4x ≥ 80

⇒ x ≥ 20

2.If – 3x + 17 < – 13, then

(a) x∈ (10, ∞) (b) x ∈ [10, ∞) (c) x ∈ (–∞, 10] (d) x ∈ [– 10, 10)

Correct option: (a) x ∈ (10, ∞)

Solution:

Given,

-3x + 17 < -13

Subtracting 17 from both sides,

-3x + 17 – 17 < -13 – 17

⇒ -3x < -30

⇒ x > 10 {since the division by negative number inverts the inequality sign}

⇒ x ∈ (10, ∞)

3. The interval form of x ≤ -2 is

(a) x∈ (–∞, – 2) (b) x ∈ (–∞, – 2] (c) x ∈ (– 2, ∞] (d) x ∈ [– 2, ∞)

Correct option: (b) x ∈ (–∞, – 2]

4.If |x −1| > 5, then

(a) x∈ (– 4, 6) (b) x ∈ [– 4, 6] (c) x ∈ (–∞, – 4) U (6, ∞) (d) x ∈ [–∞, – 4) U [6, ∞)

Correct option: (c) x ∈ (–∞, – 4) ∪ (6, ∞)

Solution:

|x – 1| > 5

37

Written for

Institution
Secondary school
Course
School year
4

Document information

Uploaded on
April 1, 2025
Number of pages
8
Written in
2024/2025
Type
Class notes
Professor(s)
Sachin sir
Contains
All classes

Subjects

$8.49
Get access to the full document:

Wrong document? Swap it for free Within 14 days of purchase and before downloading, you can choose a different document. You can simply spend the amount again.
Written by students who passed
Immediately available after payment
Read online or as PDF

Get to know the seller
Seller avatar
himanshu789

Get to know the seller

Seller avatar
himanshu789
Follow You need to be logged in order to follow users or courses
Sold
-
Member since
1 year
Number of followers
0
Documents
45
Last sold
-

0.0

0 reviews

5
0
4
0
3
0
2
0
1
0

Recently viewed by you

Why students choose Stuvia

Created by fellow students, verified by reviews

Quality you can trust: written by students who passed their tests and reviewed by others who've used these notes.

Didn't get what you expected? Choose another document

No worries! You can instantly pick a different document that better fits what you're looking for.

Pay as you like, start learning right away

No subscription, no commitments. Pay the way you're used to via credit card and download your PDF document instantly.

Student with book image

“Bought, downloaded, and aced it. It really can be that simple.”

Alisha Student

Working on your references?

Create accurate citations in APA, MLA and Harvard with our free citation generator.

Working on your references?

Frequently asked questions