CSLBgCONCRETEgC8gLICENSEgPRACTICEgTESTg1,g2,g3gANDg4gWITHggCOM
PLETEgSOLUTIONSg100%gVERIFIEDgNEW!!
-CSLBgConcretegC8gLicensegPracticegTestg1
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CSLBgConcretegC8gLicensegPracticegTestg1
Whatgisgthegvolumegofgagcylindergifgthegdiametergisg3gfeetgandgtheglengthgequalsgtog12gfeet?
- ANSWERg84.78gcubicgfeet
Explanation
Theregaregtwogwaysgtogsolvegthegproblem.gHowever,gregardlessgofgwhichgmethodgisguse
d,gyougneedgtogfirstgdeterminegthegareagofgthegcirclegthengmultiplygitgbygtheglength.Traditi
onalgMethodUsegthegfollowinggformula:Areagofgthegcircleg=gπgxgrgxgrWheregπg=g3.14gand
gradius
(r)g=g1.5gfeetg(halfgofgthegdiameterglength)Areag=g3.14gxg1.5gxg1.5Areag=g7.065gsq.gft.gM
ultiplygareagbyglengthgtogfindgthegvolume.7.065gxg12g=g84.78gShortcutgMethodgAreagofgci
rclegisg78.5%gofgthegsquare.gWorkgwithgthegcirclegasgagsquaregandgsolvegforgthegarea.gF
indgareagofgthegsquareginsteadgofgcircle.3'gxg3'g=g9gsq.gft.Sincegcirclegisg78.5%gofgthegsq
uare,gmultiplygareagofgthegsquaregbyg78.5%g(or.785gifgtheregisgnogpercentagegsigngongth
egcalculator).9gsq.gft.gx.785g=g7.065gsquaregfeetMultiplygareagbygtheglengthgtogfindgthegv
olume.7.065gxg12g=g84.78gcubicgfeet
Wheregaregspiralgrebargtiesgused?g- ANSWERgIngroundgcolumns
Controlgjointsgingsidewalksgshouldgbegspacedgatgwhatgintervals?g-
g ANSWERgEqualgtogthegwidthgofgthegslab
,Explanation:
Generallygthegcontrolgjointsgingsidewalksgshouldgbegspacedgequalgtogthegwidthgofgthegsla
b,gbutgnotgmoregthang6gfeetgapart.
Onegcubicgfootgofgcementgweighsgapproximately:g- ANSWERg 95g lbs
Howgmanygcubicgyardgofgconcretegisgrequiredgforgag4"gslabgwithgthegdiametergofg15gfeet?g-
gANSWERg2g½gcubicgyards
Explanation:
TraditionalgMethodUsegthegfollowinggformula:Areagofgthegcircleg=gπgxgrgxgrWheregπg=g3.1
4gandgradiusg(r)g=g7.5gfeetg(halfgofgthegdiameterglength)Areag=g3.14gxg7.5gxg7.5Areag=g1
76.625gsq.gft.Multiplygareagbygthegdepthgofgthegslabg(ingfeet)gtogfindgthegvolumegingcubic
gfeet.176.625gx.333g=g58.82gcubicgfeetConvertgcubicgfeetgintogcubicgyards.58.82g÷g27g=
2.18gcubicgyardsSinceg2.18gisgnotgaggivengoption,groundgupgthegnumbergtog2.5gcubicgy
ardsShortcutgMethodThisgproblemgcangbegsolvedgusinggagmuchgsimplergmethod.gFirstgi
sgtogfindgthegareagofgthegsquare,gthengconvertgitgintogthegareagofgthegcirclegbygmultiplyi
nggitgbyg78.5%.Areagofgthegsquareg=g15'gxg15'g=g225gsquaregfeetAreagofgthegcircleg=g225g
xg.785g=g176.625gsquaregfeetDividegthegvolumegbyg81gtogsolvegforgthegcubicgyardsgforg
ag4"gslab.176.625g÷g81g=g2.18gcubicgyardsSinceg2.18gisgnotgaggivengoption,groundgupgt
hegnumbergtog2.5gcubicgyards
Thegnormalgtolerancegforgtheglocationgofgbendsgandgendsgofgreinforcinggbargis:g-
gANSWERg+/-g2ginches
Howgmanygcubicgyardsgofgbackfillgaregrequiredgforgag3'gxg5'gtrench,g1500gftglong,gwithg
ag1gfootgdiametergpipe?g- ANSWERg789.72
Explanation:
Stepg1.gDeterminegthegnetgfacegareagofgthegtrenchgminusgpipe.Facegareagwithgpipe:g3gxg5
g=g15gsquaregfeetAreagofgthegpipe:g????=????????2Ag=g3.14gx.5gx.5Ag=g0.785Determin
egthegfacegareagofgthegtrenchgminusgareagofgthegpipe,gwhichgwillggivegyougthegnetgareagf
orgthegbackfill.15g-
g0.785g=g14.215Stepg2.gDeterminegthegtotalgvolumegofgthegbackfill.14.215gxg1500g=g213
22.5gcubicgfeetConvertgthegvolumegintogcubicgyards.21322.5g÷g27g=g789.72gcubicgyards
,Whengcangtheglivegloadgbegobtainedgbygmultiplyinggthegheight,gwidthgandglengthgofgagpo
urgandgdividedgbygthegdeadgload?g- ANSWERgNever
Thegtensilegstrengthgingconcretegisgdevelopedgby:g- ANSWERgSteelgreinforcement.
Lookinggatgtheghousegplan.gWhatgwouldgthegtotalgcostgofgthegfoundationgslabgbe,gifgt
hegcontractorgchargedg$3.54gagsquaregfoot?g- ANSWERg$6524.90
Explanation
Thegeasiestgwaygtogsolvegforgthegareagofgthegslabgisgtogimagegagfullgrectanglegofgthegslab
gandgsubtractgvoidgareasgfromgthegareagofgthegslab.
Rectanglegarea:g28.167'gxg71.5'=g2013.94gsqgftLeftgvoidgarea:g6.667'gxg1.83'g=g12.2gsqgf
tCentergvoidgarea:g11.5'gxg1.83'g=g21.045gsqgftRightgvoidgarea:g9.167'gxg15'g=g137.505Net
gareagofgthegfoundationgslab:g2013.94g-g12.2g-g21.045g-
g137.505g=g1843.19gsqgft.Calculategthegpricegofgthegslab.1843.19gsqgftgxg$3.54g=g$6524.
90
Whatgisgthegminimumgspacinggofgparallelgreinforcinggbarsgplacedgingtwogorgmoreglayers?g-
gANSWERg1ginch
Explanation:
AccordinggtogthegAmericangConcretegInstitute,gwheregparallelgreinforcementgisgplacedgi
ngtwogorgmoreglayers,gbarsgingthegupperglayersgshallgbegplacedgdirectlygabovegbarsging
thegbottomglayergwithgcleargdistancegbetweenglayersgnotglessgthang1ginch.
Whengapplyinggconcretegtogconcretegtheregaregseveralgfactorsgtogconsider.gWhichgi
sgmostgimportant?g- ANSWERgIngmostgcasesgthegmostgimportantgisgthegbond.
Whatgisgthegpurposegofgthegrebar?g- ANSWERgTogincreaseg thegtensileg strength
, Theregaregmanygornamentalgusesgofgconcrete,gincludinggcastinggarchitecturalgelements
,gornaments,gandgfauxgfinishes.gHowgwouldgyougdescribegterrazzogingthegsimplestgterm
s?g-gANSWERgAgspecialgcombinationgofgcoloredgrockgandgglassgforgfloors.
WhatgisgthegminimumgsizegofganchorgboltgcangbegusedgingseismicgcategorygE?g-
g ANSWERg#5
Thegbuildinggcodegrequiresg5/8"ganchorgboltgtogbegusedgingseismicgcategorygE.
Constructiongloadsgare:g-
ANSWERgThegmaximumgloadsgtogwhichgagstructuregwillgev
ergbegsubjected.
Ingsomegcasesgitgmaygbegnecessarygtogusegstrongergorgdoublegties.gWhy?g-
ANSWERgAs
gagsafetygprecautiongwhengworkersgmaygneedgtogclimbgongreinforcement.
Whatgsizegofgrebargisgusedgtogreinforcegstemgwall?g- ANSWERg#4
Explanation:
Thegcodegrequiresg½ginchgrebargtogbegusedgingstemgwalls.
Ongconcretegpavinggorgroadway,gitgisgnormalgtogusegtransversegjointsgatgregularginterval
s.gThesegjointsgaregbestgfilledgandgsealed.gWhy?g-
ANSWERgTogreducegriskgofgexposuregt
ogthegreinforcing.
Whengbatchinggconcrete,gwhatgpercentagegofgconcretegpowdergisgcommonlygused?g-
gANSWERg25%gtog40%gcementgpowder
Thegsidesgofgthegmaingfieldgofgthegslabgmustgbegreinforcedgwithgang byg
grid.g-
gANSWERg15".18"
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CSLBgConcretegC8gLicensegPracticegTestg1
Whatgisgthegvolumegofgagcylindergifgthegdiametergisg3gfeetgandgtheglengthgequalsgtog12gfeet?
- ANSWERg84.78gcubicgfeet
Explanation
Theregaregtwogwaysgtogsolvegthegproblem.gHowever,gregardlessgofgwhichgmethodgisguse
d,gyougneedgtogfirstgdeterminegthegareagofgthegcirclegthengmultiplygitgbygtheglength.Traditi
onalgMethodUsegthegfollowinggformula:Areagofgthegcircleg=gπgxgrgxgrWheregπg=g3.14gand
gradius
(r)g=g1.5gfeetg(halfgofgthegdiameterglength)Areag=g3.14gxg1.5gxg1.5Areag=g7.065gsq.gft.gM
ultiplygareagbyglengthgtogfindgthegvolume.7.065gxg12g=g84.78gShortcutgMethodgAreagofgci
rclegisg78.5%gofgthegsquare.gWorkgwithgthegcirclegasgagsquaregandgsolvegforgthegarea.gF
indgareagofgthegsquareginsteadgofgcircle.3'gxg3'g=g9gsq.gft.Sincegcirclegisg78.5%gofgthegsq
uare,gmultiplygareagofgthegsquaregbyg78.5%g(or.785gifgtheregisgnogpercentagegsigngongth
egcalculator).9gsq.gft.gx.785g=g7.065gsquaregfeetMultiplygareagbygtheglengthgtogfindgthegv
olume.7.065gxg12g=g84.78gcubicgfeet
Wheregaregspiralgrebargtiesgused?g- ANSWERgIngroundgcolumns
Controlgjointsgingsidewalksgshouldgbegspacedgatgwhatgintervals?g-
g ANSWERgEqualgtogthegwidthgofgthegslab
,Explanation:
Generallygthegcontrolgjointsgingsidewalksgshouldgbegspacedgequalgtogthegwidthgofgthegsla
b,gbutgnotgmoregthang6gfeetgapart.
Onegcubicgfootgofgcementgweighsgapproximately:g- ANSWERg 95g lbs
Howgmanygcubicgyardgofgconcretegisgrequiredgforgag4"gslabgwithgthegdiametergofg15gfeet?g-
gANSWERg2g½gcubicgyards
Explanation:
TraditionalgMethodUsegthegfollowinggformula:Areagofgthegcircleg=gπgxgrgxgrWheregπg=g3.1
4gandgradiusg(r)g=g7.5gfeetg(halfgofgthegdiameterglength)Areag=g3.14gxg7.5gxg7.5Areag=g1
76.625gsq.gft.Multiplygareagbygthegdepthgofgthegslabg(ingfeet)gtogfindgthegvolumegingcubic
gfeet.176.625gx.333g=g58.82gcubicgfeetConvertgcubicgfeetgintogcubicgyards.58.82g÷g27g=
2.18gcubicgyardsSinceg2.18gisgnotgaggivengoption,groundgupgthegnumbergtog2.5gcubicgy
ardsShortcutgMethodThisgproblemgcangbegsolvedgusinggagmuchgsimplergmethod.gFirstgi
sgtogfindgthegareagofgthegsquare,gthengconvertgitgintogthegareagofgthegcirclegbygmultiplyi
nggitgbyg78.5%.Areagofgthegsquareg=g15'gxg15'g=g225gsquaregfeetAreagofgthegcircleg=g225g
xg.785g=g176.625gsquaregfeetDividegthegvolumegbyg81gtogsolvegforgthegcubicgyardsgforg
ag4"gslab.176.625g÷g81g=g2.18gcubicgyardsSinceg2.18gisgnotgaggivengoption,groundgupgt
hegnumbergtog2.5gcubicgyards
Thegnormalgtolerancegforgtheglocationgofgbendsgandgendsgofgreinforcinggbargis:g-
gANSWERg+/-g2ginches
Howgmanygcubicgyardsgofgbackfillgaregrequiredgforgag3'gxg5'gtrench,g1500gftglong,gwithg
ag1gfootgdiametergpipe?g- ANSWERg789.72
Explanation:
Stepg1.gDeterminegthegnetgfacegareagofgthegtrenchgminusgpipe.Facegareagwithgpipe:g3gxg5
g=g15gsquaregfeetAreagofgthegpipe:g????=????????2Ag=g3.14gx.5gx.5Ag=g0.785Determin
egthegfacegareagofgthegtrenchgminusgareagofgthegpipe,gwhichgwillggivegyougthegnetgareagf
orgthegbackfill.15g-
g0.785g=g14.215Stepg2.gDeterminegthegtotalgvolumegofgthegbackfill.14.215gxg1500g=g213
22.5gcubicgfeetConvertgthegvolumegintogcubicgyards.21322.5g÷g27g=g789.72gcubicgyards
,Whengcangtheglivegloadgbegobtainedgbygmultiplyinggthegheight,gwidthgandglengthgofgagpo
urgandgdividedgbygthegdeadgload?g- ANSWERgNever
Thegtensilegstrengthgingconcretegisgdevelopedgby:g- ANSWERgSteelgreinforcement.
Lookinggatgtheghousegplan.gWhatgwouldgthegtotalgcostgofgthegfoundationgslabgbe,gifgt
hegcontractorgchargedg$3.54gagsquaregfoot?g- ANSWERg$6524.90
Explanation
Thegeasiestgwaygtogsolvegforgthegareagofgthegslabgisgtogimagegagfullgrectanglegofgthegslab
gandgsubtractgvoidgareasgfromgthegareagofgthegslab.
Rectanglegarea:g28.167'gxg71.5'=g2013.94gsqgftLeftgvoidgarea:g6.667'gxg1.83'g=g12.2gsqgf
tCentergvoidgarea:g11.5'gxg1.83'g=g21.045gsqgftRightgvoidgarea:g9.167'gxg15'g=g137.505Net
gareagofgthegfoundationgslab:g2013.94g-g12.2g-g21.045g-
g137.505g=g1843.19gsqgft.Calculategthegpricegofgthegslab.1843.19gsqgftgxg$3.54g=g$6524.
90
Whatgisgthegminimumgspacinggofgparallelgreinforcinggbarsgplacedgingtwogorgmoreglayers?g-
gANSWERg1ginch
Explanation:
AccordinggtogthegAmericangConcretegInstitute,gwheregparallelgreinforcementgisgplacedgi
ngtwogorgmoreglayers,gbarsgingthegupperglayersgshallgbegplacedgdirectlygabovegbarsging
thegbottomglayergwithgcleargdistancegbetweenglayersgnotglessgthang1ginch.
Whengapplyinggconcretegtogconcretegtheregaregseveralgfactorsgtogconsider.gWhichgi
sgmostgimportant?g- ANSWERgIngmostgcasesgthegmostgimportantgisgthegbond.
Whatgisgthegpurposegofgthegrebar?g- ANSWERgTogincreaseg thegtensileg strength
, Theregaregmanygornamentalgusesgofgconcrete,gincludinggcastinggarchitecturalgelements
,gornaments,gandgfauxgfinishes.gHowgwouldgyougdescribegterrazzogingthegsimplestgterm
s?g-gANSWERgAgspecialgcombinationgofgcoloredgrockgandgglassgforgfloors.
WhatgisgthegminimumgsizegofganchorgboltgcangbegusedgingseismicgcategorygE?g-
g ANSWERg#5
Thegbuildinggcodegrequiresg5/8"ganchorgboltgtogbegusedgingseismicgcategorygE.
Constructiongloadsgare:g-
ANSWERgThegmaximumgloadsgtogwhichgagstructuregwillgev
ergbegsubjected.
Ingsomegcasesgitgmaygbegnecessarygtogusegstrongergorgdoublegties.gWhy?g-
ANSWERgAs
gagsafetygprecautiongwhengworkersgmaygneedgtogclimbgongreinforcement.
Whatgsizegofgrebargisgusedgtogreinforcegstemgwall?g- ANSWERg#4
Explanation:
Thegcodegrequiresg½ginchgrebargtogbegusedgingstemgwalls.
Ongconcretegpavinggorgroadway,gitgisgnormalgtogusegtransversegjointsgatgregularginterval
s.gThesegjointsgaregbestgfilledgandgsealed.gWhy?g-
ANSWERgTogreducegriskgofgexposuregt
ogthegreinforcing.
Whengbatchinggconcrete,gwhatgpercentagegofgconcretegpowdergisgcommonlygused?g-
gANSWERg25%gtog40%gcementgpowder
Thegsidesgofgthegmaingfieldgofgthegslabgmustgbegreinforcedgwithgang byg
grid.g-
gANSWERg15".18"
