WGU D335 OA /WGU D335 INTRODUCTION TO PYTHON OA FINAL EXAM NEWEST 2025 ACTUAL EXAM COMPLETE 200 QUESTIONS AND CORRECT DETAILED ANSWERS (VERIFIED ANSWERS) |ALREADY GRADED A+|BRAND NEW!!

WGU D335 OA /WGU D335 INTRODUCTION TO PYTHON OA FINAL EXAM NEWEST 2025
ACTUAL EXAM COMPLETE QUESTIONS AND CORRECT DETAILED ANSWERS (VERIFIED
ANSWERS) |ALREADY GRADED A+|BRAND NEW!!

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Create a solution that accepts three integer inputs representing the number of times an employee
travels to a job site. Output the total distance traveled to two decimal places given the following miles
per employee commute to the job site. Output the total distance traveled to two decimal places given
the following miles per employee commute to the job site:

Employee A: 15.62 miles

Employee B: 41.85 miles

Employee C: 32.67 miles

The solution output should be in the format

Distance: total_miles_traveled miles - (ANSWER)travels = {

"A": int(input()),

"B": int(input()),

"C": int(input())

}

miles_per_employee = {"A": 15.62, "B":41.85, "C": 32.67}

total_miles_traveled = sum(travels[employee] * miles_per_employee[employee] for employee in
travels)

print(f"Distance: {total_miles_traveled:.2f} miles")



Create a solution that accepts an integer input representing any number of ounces. Output the
converted total number of tons, pounds, and remaining ounces based on the input ounces value. There
are 16 ounces in a pound and 2,000 pounds in a ton.

The solution output should be in the format

Tons: value_1 Pounds: value_2 Ounces: value_3 - (ANSWER)ounces = int(input())

value_1 = ounces // (16 * 2000)

value_2 = (ounces % (16 * 2000)) // 16

, WGU D335 OA /WGU D335 INTRODUCTION TO PYTHON OA FINAL EXAM NEWEST 2025
ACTUAL EXAM COMPLETE QUESTIONS AND CORRECT DETAILED ANSWERS (VERIFIED
ANSWERS) |ALREADY GRADED A+|BRAND NEW!!










value_3 = ounces % 16

print(f"Tons: {value_1}")

print(f"Pounds: {value_2}")

print(f"Ounces: {value_3}")



Create a solution that accepts an integer input representing the index value for any any of the five
elements in the following list:

various_data_types = [516, 112.49, True, "meow", ("Western", "Governors", "University"), {"apple": 1,
"pear": 5}]

Using the built-in function type() and getting its name by using the .name attribute, output data type
(e.g., int", "float", "bool", "str") based on the input index value of the list element.

The solution output should be in the format

Element index_value: data_type - (ANSWER)index_value = int(input())

data_type = type(various_data_types[index_value]).__name__

print(f"Element {index_value}: {data_type}")



Create a solution that accepts any three integer inputs representing the base (b1, b2) and height (h)
measurements of a trapezoid in meters. Output the exact area of the trapezoid in square meters as a
float value. The exact area of a trapezoid can be calculated by finding the average of the two base
measurements, then multiplying by the height measurement.

Trapezoid Area Formula:A = [(b1 + b2) / 2] * h

The solution output should be in the format

Trapezoid area: area_value square meters - (ANSWER)b1 = int(input())

b2 = int(input())

h = int(input())